A little more of Vadim's example
> my $a = ; say $a.raku;
("a", "b", "c")
> my @a = ; say @a.raku;
["a", "b", "c"]
> @a[1]='X'; say @a.raku;
["a", "X", "c"]
> $a[1]='X'
Cannot modify an immutable List ((a b c))
in block at line 1
$a is a scalar container, holds one thing. In this example a
Sigils mean a lot. For example, they create a context:
my $a = 1,2,3;
my @a = 1,2,3;
$a = ; say $a.raku;
@a = ; say @a.raku;
If you have some (actually, a lot of) spare time you can watch my class from
TRC2021 where I cover a lot about symbols/sigils/object interaction in Raku:
On Sunday, August 22, Marc Chantreux wrote:
> my ($a, $b) = { @^a[0,2...Inf], @a[1,3...Inf] }.(q<(){}[]>.comb); say $a[0];
> say $b[0]
>
> oh. i never see this direct call of a lambda before but it really makes
> sense! this is the answer i like the most.
I think it's possible to avoid the
On Sun, Aug 22, 2021 at 2:58 PM Marc Chantreux wrote:
> so of course i tried
>
> my (@a, @b) = { .[0,2…∞], .[1,3…∞] }.(q.comb);
>
> because i have two lists and two containers. this doesn't work.
> which means @ and $ combines with = to define how things are stored
> but i don't understand how
thanks everyone for sharing,
Vadim,
my ($a, $b) = { @^a[0,2...Inf], @a[1,3...Inf] }.(q<(){}[]>.comb); say $a[0];
say $b[0]
oh. i never see this direct call of a lambda before but it really makes
sense! this is the answer i like the most.
i rewrote it my way and this works
my ($a, $b) = {
