On Thu, Jan 15, 2009 at 10:52:55PM -0800, Mark Lentczner wrote:
I'm re-working my Periodic Table of the Operators chart to be up-to-
date. I did the first major pass based on S03-operators. However, the
last few days I've been plowing through STD.pm and have discovered that
there some
Author: lwall
Date: 2009-01-27 18:43:18 +0100 (Tue, 27 Jan 2009)
New Revision: 25060
Modified:
docs/Perl6/Spec/S03-operators.pod
src/perl6/STD.pm
Log:
[STD] more operator hacking inspired by mtnviewmark++
[S03] added comparison-reversion metaoperator
Modified:
On Tue, Jan 27, 2009 at 9:43 AM, pugs-comm...@feather.perl6.nl wrote:
+=head2 Reversed comparison operators
+
+Any infix comparison operator returning type COrder may be transformed
into its reversed sense
+by prefixing with C-.
+
+-cmp
+-leg
+-=
+
+To avoid confusion with
On Tue, Jan 27, 2009 at 10:59:34AM -0800, Jon Lang wrote:
: If there are only a handful of operators to which the new
: meta-operator can be applied, why do it as a meta-operator at all?
As a metaoperator it automatically extends to user-defined comparison
operators, but I admit that's not a
On Tue, Jan 27, 2009 at 11:56:16AM -0800, Larry Wall wrote:
: Arguably autogenerated operators should give way to hardwired ones,
: much like foo\w* gives way to foobar currently.
Though I should point out that this wouldn't help with -=, since it's
autogenerated either way, unless you divide the
On Sun, Jan 18, 2009 at 10:57:26PM -0800, Mark Lentczner wrote:
I was looking through STD.pm at the parsing of metaops. I was exploring
to see if the legal metaops for a given operator could be notated on the
operator chart. What I found was some oddness...
Caveat: The actual
Larry Wall wrote:
Jon Lang wrote:
: If there are only a handful of operators to which the new
: meta-operator can be applied, why do it as a meta-operator at all?
As a metaoperator it automatically extends to user-defined comparison
operators, but I admit that's not a strong argument.
On Jan 27, 2009, at 12:29 PM, Jon Lang wrote:
So $a -= $b is equivalent to $b = $a, not -($a = $b). OK.
I'd suggest choosing a better character for the meta-operator (one
that conveys the meaning of reversal of order rather than opposite
value); but I don't think that there is one.
There
