>> "m" == moritz writes:
>
> m> S02 says:
>
> m> "To get a Perlish representation of any object, use the .perl method.
> Like
> m> the Data::Dumper module in Perl 5, the .perl method will put quotes
> around
> m> strings, square brackets around list values,"
>
> m> So according to t
Uri,
On Sun, 04 Jan 2009 22:37:43 -0500, Uri Guttman wrote:
> that fails with nested arrays. we don't want them to flatten.
>
> my $c = eval '(1, (4, 5), 3)';
>
> will that work as you envision?
No, but it's not what I'm proposing. A reference must Perlify as a
reference, just as it does toda
> "ML" == Markus Laker writes:
ML> Adding a single backslash before `eval' pushes an anonymous array on to
ML> @b, as you envisage wanting to do:
ML> # Imagine that @a.perl has produced this:
ML> my $p = "('blue', 'light', 'hazard')";
ML> my @b;
ML> @b.push(\eval $p);
but that
On Sun, 04 Jan 2009 14:19:15 -0500, Uri Guttman wrote:
>> "m" == moritz writes:
> m> But I think that a .perl()ification as ("blue", "light", "hayard",) would
> m> make much more sense, because simple thing like
>
> m> @a.push eval(@b.perl)
>
> m> would then DWIM.
>
> for your def
> "m" == moritz writes:
m> S02 says:
m> "To get a Perlish representation of any object, use the .perl method. Like
m> the Data::Dumper module in Perl 5, the .perl method will put quotes around
m> strings, square brackets around list values,"
m> So according to this, Rakudo has it
> m...@edward:~/perl/6$ ./ap2
> @c: 3 elements: ["blue", "light", "hazard"]
> @c[0]: blue
> $c: 3 elements: ["blue", "light", "hazard"]
> $c[0]: blue
> m...@edward:~/perl/6$
>
>
> Is Rakudo's behaviour correct here?
S02 says:
"To get a Perlish representation of any object, use the .perl method. L
This behaviour looks wrong to me:
m...@edward:~/perl/6$ cat ap1
#!/home/msl/bin/perl6
my @a = ;
my $p = @a.perl;
say "\...@a: {...@a.elems} elements: $p";
say '@a[0]: ', @a[0];
my @b = eval $p;
say "\...@b: {...@b.elems} elements: $p";
say '@b[0]: ',@b[0];
say '@b[0][0]: ', @b[0][0];
m...@
