Hi!
Another question to improve understanding of Perl6 internals.
Let's say, I've got an idea of allowing a user to define a 'template' class.
I.e. it wouldn't be used directly, but I could be used as a base for creating a
new one (or a couple of new ones – it would depend). Basically, what is
What's going on here- is this error a mistake on my part, or a bug?
$ perl6 -e "say 3 ~ ( 'a' | 'b' )"
Type check failed for return value; expected Str:D but got Junction
(any("3a", "3b"))
in block at -e line 1
$ perl6 -e "say 'x' ~ ( 'a' | 'b' )"
any(xa, xb)
$ perl6 -v
This is Rakudo Sta
I turns out there is a candidate for
Str:D, Junction:D
but not for
Any:D, Junction:D
so it is going through one of the other &infix:<~> candidates,
specifically it looks like it could be
*@args
Which doesn't apparently work with Junctions. So yes it is a bug.
On Sat, Dec 22, 2018 at 9:05 PM
