SELECT
FROM_DAYS(TO_DAYS(purchaseDate)-DAYOFYEAR(purchaseDate)+WEEK(purchaseDate)*7)
will hopefully return the date you need. You'll have to enclose all that
in a DATE_FORMAT to get a printable date tho. Last minute note: you
might have to subtract 1 from the last term because I guess MySQL st
Hello all,
I am creating a finance manager in php and mysql for my own accounting
purposes (and to broaden my skills in php and sql) and I have a couple
of pages where I view statistics on how much I spend, etc, and what
patterns are formed from my spending.
I have made a couple of pages with
Hello,
I have a problem I can't seem to overcome. Maybe it's just something simple
but for some reason I am unable to read in values from a mysql db column
(enum) and display the results in an option box.
I can display the values to the screen but I can't seem to get them into the
option box. Th
Here is how you do it:
$pictures = array( 1, 2, 3, 4, 5, 6, 7, etc.)
shuffle($pictures) //This will randomly rearrange them in the array.
//then
echo "$pictures[1]
echo $pictures[2]
echo $pictures[3]";
Dave Carrera <[EMAIL PROTECTED]> wrote: Hi All
I have a fuctioning array of about 20
http://www.zend.com/zend/tut/drop-down.php
or do a Google search for 'javascript chained select'
"Chris Payne" <[EMAIL PROTECTED]> wrote in message
01c2092d$17a9fdb0$f7fea8c0@chris">news:01c2092d$17a9fdb0$f7fea8c0@chris...
> Im having an issue with pulldown selection speeds,
> is there
