> please note the time "intervals" that are working. what i
> want is to select only data that is two weeks old or younger. i did a
> test with one day and it worked great. i inserted the two-week/14days
> and neither of them worked. 1 month worked. i could not find anything
> on php.net that
hello,
thank you for your time.
please note the time "intervals" that are working. what i
want is to select only data that is two weeks old or younger. i did a
test with one day and it worked great. i inserted the two-week/14days
and neither of them worked. 1 month worked. i could not find an
I once read a great article in the first or second issue of
http://www.phparch.com/ on database abstraction layers. At which point I
used the tutorial as a starting point for creating a very similar structure
I named dbWave. There are only minor differences and a postgresql driver is
now included f
> I am a novice PHP dev having a strange issue with
mysql_fetch_array.
> For some reason, it is keeping data from previous queries in the
array,
> and
> displaying it in the web page.
> My development platform is Win2k SP2, Apache 1.3.23, PHP 4.3.0,
> MySQL-MAX 3.23.47-nt.
> Here is the
> I have a situation where I have a network at work with only Sequel
Server
> 2000 on a Microsoft IIs Server. Is php a viable option for accessing
a
> sequel database?
Sure...
---John W. Holmes...
PHP Architect - A monthly magazine for PHP Professionals. Get your copy
today. http://www.phparch
> I would like to know how to get error messages to
> appear if something goes wrong. Like if the mysql
> finds the database account but fails to update the
> table, finds the table but a unique entry is inputted
> so can't add. I'd like to be able, if possible, to
> customize the error message.
``List-Unsubscribe''
Hello,
I am a novice PHP dev having a strange issue with mysql_fetch_array.
For some reason, it is keeping data from previous queries in the array, and
displaying it in the web page.
My development platform is Win2k SP2, Apache 1.3.23, PHP 4.3.0,
MySQL-MAX 3.23.47-nt.
Here is the code t
Hi,
I would like to know how to get error messages to
appear if something goes wrong. Like if the mysql
finds the database account but fails to update the
table, finds the table but a unique entry is inputted
so can't add. I'd like to be able, if possible, to
customize the error message. Could
I have a situation where I have a network at work with only Sequel Server
2000 on a Microsoft IIs Server. Is php a viable option for accessing a
sequel database?
Thanks
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try :
if (strlen($products) == 0) {
echo "nothing entered in field";
}
http://www.php.net/manual/en/function.strlen.php
Jeff
- Original Message -
From: "Aaron Wolski" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Wednesday, February 05, 2003 3:03 PM
Subject: [PHP-DB] check
Please, any idea to resolve my problem!!!
I have the output:
Connected to DataBase Oracle!
Warning: OCIStmtExecute: ORA-03106: fatal two-task communication protocol
error in /var/www/html/ora2.php on line 21
Warning: OCIFetchStatement: ORA-24374: define not done before fetch or
execute and fetc
Well well well.. with the help of someone else pointing me in a
different direction altogether here's what we came up with that totally
works!
$PRODUCT_SELECTED = TRUE;
foreach($products as $value) {
if(empty($value)) {
$PRODUCT_SELEC
hallo,
look like here?
http://www.php.net/manual/en/function.sizeof.php
echo sizeof($HTTP_POST_VARS["myArrayObject"]);
a.v.l
-Ursprüngliche Nachricht-
Von: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]]
Gesendet: Mittwoch, 5. Februar 2003 02:54
An: Aaron Wolski
Cc: [EMAIL PROTECTED]
Be
Somebody else replied with isset($varname). Try that. The count() function
is working as expected (see
http://www.php.net/manual/en/function.count.php). So maybe it's not the best
choice for trying to find out what you want.
> -Original Message-
> From: Aaron Wolski [mailto:[EMAIL PROTECTE
to find out if an array is empty use:
empty()
it must be unset
NULL returns false
0 returns false
it must be truly empty to return true...
> Ok... well
>
> When I select the "select product" which has a option value="" it tells
> me the count is one (1). If I select an ACTUAL product it tells
Ok... well
When I select the "select product" which has a option value="" it tells
me the count is one (1). If I select an ACTUAL product it tells me
one(1) was select.. if I select two ACTUAL products it tells me two (2)
products were selected.
For SOME reason it doesn't seem to be recognizing t
I usually use:
while(list($key,$value) = each($products)) {
echo "$key:$value";
}
On Wed, 2003-02-05 at 15:03, Aaron Wolski wrote:
> Argh
>
>
> HOW does one check for an array being empty from a form field??
>
> Tried a billion different things and NOTHING works
What about:
count($arrayname)
Should tell you how many items are in an array.
> -Original Message-
> From: Aaron Wolski [mailto:[EMAIL PROTECTED]]
> Sent: Wednesday, February 05, 2003 4:04 PM
> To: [EMAIL PROTECTED]
> Subject: [PHP-DB] checking for empty array from a form field?
> gr
Eu tenho dois um para os meses e outros para os anos, como faço para garantir
que o utilizador não possa escolher um ano já passado, e durante o presente ano apenas
os meses seguintes e o actual.
Desde já obrigado
__
Rui Palma
ICQ#
First try isset($product) to see if it's being POSTed or GETted
properly. You might need to use $_POST['products'] or
$_GET['products'].
--- Aaron Wolski <[EMAIL PROTECTED]> wrote:
> Argh
>
>
> HOW does one check for an array being empty from a form
> field??
>
> Tried a bi
if empty($products)
echo "its empty";
else
echo "its not empty";
jay merritt
[EMAIL PROTECTED]
[EMAIL PROTECTED]
Quoting Aaron Wolski <[EMAIL PROTECTED]>:
> Argh
>
>
> HOW does one check for an array being empty from a form field??
>
> Tried a billion different t
Argh
HOW does one check for an array being empty from a form field??
Tried a billion different things and NOTHING works
I've tried:
if ($products == "\n") {
echo "hello";
}
else {
echo "bye";
}
if ($products == "") {
echo "hello";
}
else {
print_r($_FILES) doesn't show full path of the filename I selected. I'm not
trying to upload but just need to be able to open the file for viewing.
Help.
-
This mail sent through ISOT. To find out more
about ISOT, visit http://isot.com
--
P
On Thursday 06 February 2003 01:13, Aaron Wolski wrote:
> Hi All,
>
> Again.. a little off topic - sorry (again!).
>
> Have a form that allows me to select a bunch of product names from a
> drop down combo box.
>
> I'm trying to create code like "in ('Product name1','Product Name2) to
> be inserted
The 1st one didn't work, but the 2nd one did work. Fantastic! Thanks alot,
you saved me from frustrations.
Quoting "John W. Holmes" <[EMAIL PROTECTED]>:
> > I'm having problem querying a table with a field value containing an
> > appostropy, please help. Using ODBC to connect MSAcess database
Hi All,
Again.. a little off topic - sorry (again!).
Have a form that allows me to select a bunch of product names from a
drop down combo box.
I'm trying to create code like "in ('Product name1','Product Name2) to
be inserted into an SQL statement.
I figured that since $products was ALREADY
Thank Jason! It counts now.
So if i want to make something like
Most view tutorial is $row[title] << How can i do this?
Regards,
- Original Message -
From: "Jason Wong" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Wednesday, February 05, 2003 1:44 PM
Subject: Re:
You can take the selected items posted to your page and use in_array() to
search for the current item as your code creates the list. this is a chunk
of code that i use to do the same thing. I wrote this a long time ago, so
there may be better ways to do thisbut it works. ;-)
<>
if (in_array
Hi All,
Sorry to be a pain on this one as it is sorta off topic.. but any help
would be awesome.
I'm creating a report for Product Popularity in which the Admin is
present with a form and they have the ability to select A product or
multiple products from a drop down combo box.
The form is su
Try
p.php:
//Not
echo($fname);
?>
Jochem
Bismi Jomon wrote:
hi,
i hav two programs ,
p.php:
echo($fname)
?>
i tried these programs and i didnt get the value of the variable in
another php program. butit is not getting. one our friend told to put like
echo $_post(fna
Hi,
you have to write it exactly like this:
echo $_POST['fname'];
HTH,
Bastian
>
> echo $_post(fname)
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On Wednesday 05 February 2003 16:36, bismi jomon wrote:
> hi,
>
> i hav two programs ,
>
>
>
>
>
>
>
>
>
>
>
>
>
> p.php:
>
>
>
> echo($fname)
>
> ?>
>
> i tried these programs and i didnt get the value of the variable in another
> php program. butit is not getting. one our friend told to
hi,
i hav two programs ,
p.php:
echo($fname)
?>
i tried these programs and i didnt get the value of the variable in another php
program. butit is not getting. one our friend told to put like
echo $_post(fname)
but it is also not working. now getting the error about post ar
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