aturday, June 26, 2004, 7:37:36 PM, water_foul wrote:
>
> w> i get this error:
> w> Warning: Access denied for user: '[EMAIL PROTECTED]' (Using
> w> password: YES) in
> w>
C:\Inetpub\localroot\aichlmayr.net\sites\aaron\module\runescape\runerunner\s
> w> ervice
oh... one request, no replying to sender
"Water_foul" <[EMAIL PROTECTED]> wrote in message
news:[EMAIL PROTECTED]
> i get this error:
> Warning: Access denied for user: '[EMAIL PROTECTED]' (Using
> password: YES) in
>
C:\Inetpub\localroot\aichlmayr.net\sit
i get this error:
Warning: Access denied for user: '[EMAIL PROTECTED]' (Using
password: YES) in
C:\Inetpub\localroot\aichlmayr.net\sites\aaron\module\runescape\runerunner\s
ervices.php on line 3
and the code up to line 3 is:
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not connect to server, incorrect username,
> password or host : ".mysql_error()); <-this bracket!!!
> $connection=Mysql_connect($dbHost , $dbName , $dbPassword)
>
>
>
> Saturday, June 26, 2004, 7:23:30 PM, water_foul wrote:
>
> w> i get the following error
i get the following error:
Parse error: parse error, unexpected ';' in
C:\Inetpub\localroot\aichlmayr.net\sites\aaron\module\runescape\runerunner\s
ervices.php on line 4
from the following code:
' . $item[1] . '' . $user1[2].
'' .
$user2[2]. '' . $item[2] . '');
};
//this function is called by ano
; > Sent: Wednesday, June 23, 2004 2:53 AM
> > To: [EMAIL PROTECTED]
> > Subject: Re: [PHP-DB] problem
> >
> >
> > Water_foul wrote:
> >
> > > i fixed those things and it didn't fix it :( :( :( :( :( :(
> > :( :( :( is
> > > there a icq
gt; also wrap single quotes around the digit "3".
>
>
> - Original Message -
> From: "water_foul" <[EMAIL PROTECTED]>
> Date: Wednesday, June 23, 2004 8:58 am
> Subject: Re: [PHP-DB] problem
>
> > I checked em all they were right
>
I checked em all they were right
"Daniel Clark" <[EMAIL PROTECTED]> wrote in message
news:[EMAIL PROTECTED]
> Sounds like it doesn't like your SQL statement. Perhaps a field or table
> name is incorrect?
>
> > Warning: mysql_fetch_array(): supplied argument is not a valid MySQL
> > result
> > reso
Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result
resource in ...
"Daniel Clark" <[EMAIL PROTECTED]> wrote in message
news:[EMAIL PROTECTED]
> What error are you getting?
>
> > why doesn't this work:
> > $pic=mysql_query('SELECT Rune, username FROM RuneRunn
I tried that it didn't work
"Cole S. Ashcraft" <[EMAIL PROTECTED]> wrote in message
news:[EMAIL PROTECTED]
> Just from looking at it, it seems to be because you are redefining a
> variable, which destroys it, then calling for a mysql resource that has
> been destroyed. What is the error?
>
> I can'
why doesn't this work:
$pic=mysql_query('SELECT Rune, username FROM RuneRunner
RuneRunner_1 WHERE (User_ID = 3)',$connection);
$pic=mysql_fetch_array($pic);
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I am new to databases and php and I was wondering if any one would point me
to a good guide
anything would help :)
thanks in advance,
water_foul
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