Hi,
I've been trying to figure this out by looking through the code in
phpMyAdmin but I'm not getting very far.
What I want to do is dynamically generate a form where I get a table row
containing the field name in one cell and the input field in the next cell,
for example:
$DatabaseName =
If you are using MySQL you can use the "mysql_list_fields" to get the fields
names from a table.
HTH
Jayme.
-Mensagem Original-
De: Martin E. Koss [EMAIL PROTECTED]
Para: [EMAIL PROTECTED]
Enviada em: tera-feira, 20 de maro de 2001 12:02
Assunto: [PHP-DB] Dynamically build a
