The display will look like
1
2 2 2 2 2 2 2 2 2
3 3 3 3 3 3 3 3 3 3 3 3 3
4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4
Everybody on level 1 will be on same row
and so on
On 5/7/08, A. Joseph <[EMAIL PROTECTED]> wrote:
> Please i knew this not the best place to post this
Rainer Bendig Aka Ny wrote:
I want to build an array containing two arrays $navm[] and $navs[],
$navs[] should go to $navm[items].
- -sourcecode:start8<--
$resultm = $db->query("SELECT * FROM ".$p."_cats WHERE ms='m' \
ORDER BY sortorder A
"Miguel Guirao" <[EMAIL PROTECTED]> wrote in message
news:[EMAIL PROTECTED]
> Hi!!
>
> I have a table with many options from when the user can select them,
> after that, his/her selections will be stored in a database.
>
> In the mean time, I want to store his/her selections in an array like
> this
Hi
Pete I forgot to write that $acces is a field from Db and there are values
1,2,3,4
a need to split those values to make that IF
Brettking I think that is solution
"Peppe" <[EMAIL PROTECTED]> wrote in message
news:[EMAIL PROTECTED]
> Hi
> I have a variable cold $access and there are values 1,2,3
if($access ==2)
{
echo "do something";
}
Peppe wrote:
Hi
I have a variable cold $access and there are values 1,2,3,4,5
How can I check for example
If ($access =='2'){
echo "go further";
}
How can I make this work
Thanx in advance
--
PHP Database Mailing List (http://www.php.net/)
To unsubsc
Thanks that works like a charm and I learned some tricks that I can apply to
some other code!!! Ozzie
Hi there. here ya go.
$array_of_exams = Array();
$array_of_exams['Full Head'] = 'Head Examination History';
$array_of_exams['Full Body'] = 'Body Examination History';
$array_of_exams['Full Butt'
Hi there. here ya go.
$array_of_exams = Array();
$array_of_exams['Full Head'] = 'Head Examination History';
$array_of_exams['Full Body'] = 'Body Examination History';
$array_of_exams['Full Butt'] = 'Butt Examination History';
$exam_dates = Array();
foreach ($array_of_exams as $exam => $description
Much simpler:
foreach ($arrText as $text)
{
print $text;
}
Use that code. Just add in your HTML tags and it will be much cleaner and
faster.
"Michael Conway" <[EMAIL PROTECTED]> wrote in message
news:!~!UENERkVCMDkAAQACABgAeI4MkiQKXEijmrrs5/EPIcKA
[EMAIL PROTECTED]
> I
7;4.99',
'large' => '6,99'))
Then access them like this
$smallburger = $ar['burger']['small']
Hope this helps.
Simon
-Original Message-
From: David Robley [mailto:[EMAIL PROTECTED]]
Sent: 8 October 2002 06:49
To: [EMAIL PROTECTED]
Subject:
In article <000801c26e10$a2128510$f7fea8c0@chris>, [EMAIL PROTECTED]
says...
> Hi there everyone,
>
> I have a problem i'm trying to figure out but i'm not too good with arrays, just
>know the basics, if anyone could help me out on this it would be wonderful :-)
>
> I have two sets of data in
It may be because your not initialising your array. ie:
$partner_type = array();
$partner_region = array();
PHP should automatically make it an array (if its not previously a different
type) as soon as you do $partner_type[] but if you get no results from your
query then it wont
(i am new to these groups, but shouldn't there be a follow-up-to on a
X-post?)
César aracena wrote:
> I have this form in which one Administrator can insert new members and
> after that, in another page, a form where he/she can insert the new
> members sons & daughters. I want to display a tabl
> -Original Message-
> From: Andy [mailto:[EMAIL PROTECTED]]
> Sent: 04 January 2002 20:24
> To: [EMAIL PROTECTED]
> Subject: [PHP-DB] Re: Array not supported for strings???
>
> $stmt= "
> SELECT country
> from $DB2.$geo_T1
> w
On Saturday 05 January 2002 04:24, Andy wrote:
> Here is the full code:
>
> ###
> # Get the name of the country:
>
> if (isset($country_id)){ //only if there are results
>
>for($i=0; $i< count($country_id); $i++){
> $stmt= "
> SEL
Here is the full code:
###
# Get the name of the country:
if (isset($country_id)){ //only if there are results
for($i=0; $i< count($country_id); $i++){
$stmt= "
SELECT country
from $DB2.$geo_T1
where country_code =
Hi,
> I have a drop-down menu that has been prepopulated with an array from a
> column name CompanyName. What I need to do is take the CompanyName lookup
> the CompanyID in the company table and insert the CompanyID into a row in
a
> table called contacts with a CompnayID column.
[...]
Is this a
This is a PHP question and should really be asked on the PHP list.
But a suggestion. Tried using field names instead of number? ie.
$myrow["catid"];
I'd have to read up the PHP manual to find out for sure but I'm sure you can
do that just as well as I can.
- Original Message -
From: "
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