s empty it still get ''
(empty) as part of the query
- Original Message - From: "Sylvain Gourvil"
<[EMAIL PROTECTED]>
To:
Sent: Wednesday, September 21, 2005 3:26 PM
Subject: [PHP-DB] Re: newbie question on PHP & Mysql...
Evert Meulie wrote:
Hi!
I
rom: "Sylvain Gourvil" <[EMAIL PROTECTED]>
To:
Sent: Wednesday, September 21, 2005 3:26 PM
Subject: [PHP-DB] Re: newbie question on PHP & Mysql...
Evert Meulie wrote:
Hi!
I've tried your suggestions, but still get the same error message. The
'print_r($result);' t
Evert Meulie wrote:
Hi!
I've tried your suggestions, but still get the same error message. The
'print_r($result);' that I added does not print anything, so that would
explain why I get the errors.
My idea is to call this script with a value, like:
script.php value
Doesn't that put the value
Hi!
I've tried your suggestions, but still get the same error message. The
'print_r($result);' that I added does not print anything, so that would explain
why I get the errors.
My idea is to call this script with a value, like:
script.php value
Doesn't that put the value in $argv[1] ?
Regar
Hi Evert, try:
echo mysql_result($result,0,0), "\n";
echo mysql_result($result,0,1);
You forgot a zero...
Regards, Sigrid
"Evert Meulie" <[EMAIL PROTECTED]> schrieb im Newsbeitrag
news:[EMAIL PROTECTED]
> Hi all!
>
> I'm taking my first steps with PHP & MySQL.
>
> Can anyone give me a hint on w
Hi Evert, try:
echo mysql_result($result,0,0), "\n";
echo mysql_result($result,0,1);
You forgot a zero...
Regards, Sigrid
"Evert Meulie" <[EMAIL PROTECTED]> schrieb im Newsbeitrag
news:[EMAIL PROTECTED]
> Hi all!
>
> I'm taking my first steps with PHP & MySQL.
>
> Can anyone give me a hint on w
Hi,
I guess you used a single quote over the query so the text, $argv[1],
was entered into the query rather than the value inside it.
try:
$result = mysql_query('SELECT SUM(AcctInputOctets),
SUM(AcctOutputOctets) FROM radacct WHERE username = ' .$argv[1] );
OR
$result = mysql_query("SELECT SU
Hi !
Could you do a "print_r($result)" after your mysql_query ?
Or you sure of your argv[1] ?
Sylvain Gourvil
Evert Meulie wrote:
Hi all!
I'm taking my first steps with PHP & MySQL.
Can anyone give me a hint on why this would not work?
*
$result = mysql_query('SELECT S
