Hi Neil,
I would actually like to get a sample of this code as well if you don't
mind
K-
-Original Message-
From: Neil Smith [MVP, Digital media]
[mailto:[EMAIL PROTECTED]
Sent: 25 June 2004 16:22
To: [EMAIL PROTECTED]
Cc: [EMAIL PROTECTED]
Subject: Re: [PHP-DB] Date help neede
0
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Subject: RE: [PHP-DB] Date help needed
One thing he wanted which I didn't know how to do (Javascript I guess which
I don't know much about) was to preload a database of email address, and as
Hi there,
>A drop down with 365 days !?!? Isn't that a "little" big?
Actually it's Fridays, Sundays and Tuesdays for 2 years (365 was an example)
it's for an Admin for a client, and he asked that it be in a dropdown box
and he's the boss, so he gets what he wants :-)
One thing he wanted which
A drop down with 365 days !?!? Isn't that a "little" big?
> I have a problem, I currently have some code which populates a dropdown
> box
> - this code gives me every day for the next x amount of days (EG: a years
> worth of days), however what I really need to be able to do, is to find a
> way
Hi there,
Just got back and tried it and it works perfectly, thank you so much for
your help, you've got me out of a bind here ;-)
Chris
You could loop through the weeks and put those 3 specifically in:
$days = array();
for($i = 0; $i < 365; $i +=7) {
$days[] = strtotime('next Monday', strtoti
You could loop through the weeks and put those 3 specifically in:
$days = array();
for($i = 0; $i < 365; $i +=7) {
$days[] = strtotime('next Monday', strtotime('+ '.$i.' days'));
$days[] = strtotime('next Friday', strtotime('+ '.$i.' days'));
$days[] = strtotime('next Sunday', strtotime('+ '.
Hi there everyone,
I have a problem, I currently have some code which populates a dropdown box
- this code gives me every day for the next x amount of days (EG: a years
worth of days), however what I really need to be able to do, is to find a
way to display this data in the dropdown box but ONL
Hello,
You said that you are using MySQL. Create 2 columns like:
create_ts INT UNSIGNED NOT NULL,
last_login_ts INT UNSIGNED NOT NULL
Use the MySQL UNIX_TIMESTAMP() function, comparable to the PHP time()
function (number of seconds since 1-1-1970 12:00:00 AM).
UPDATE table SET last_login_ts=
At 17.11.2001 14:45, Srinivasan Ranganathan wrote:
>Hi
>
>I need to store the date and time of sign-up and date
>and time of last successful login in a mysql database
>and calculate how long the user has been using a site.
>how do i do this?
Store date either in seconds since 19700101 or use your
Hi
I need to store the date and time of sign-up and date
and time of last successful login in a mysql database
and calculate how long the user has been using a site.
how do i do this?
thanks in advance
Srinivasan
__
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Everything you'l
I desperately need to know whether it is possible to call an Oracle
function in PHP. For example...
$functionResult=hubins($name,$commit_yn)
where hubins is a stored procedure in our Oracle database.
Can this be done? My first thought was to do something like this:
$functionCall="hubins($
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When I want to subtract a day from a date, and pass the date to a function
that will do the subtraction and then return the new value, so why does php
sometimes subtract the year, i
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