[PHP-DB] More on strings

2001-03-20 Thread Mick Lloyd

I thought I had it but I didn't! I can only get LIKE to perform queries that
allow me use the result for a subsequent query but for accuracy, I need to
use actual values. The first statement below works OK (at least I get a
Resource id #) - courtesy of help received here - but will not return
$pcodeid from the third statement - it dies giving me "No pcodeid". Using
the LIKE version (second one below) works fine and I can use the $pcodeid
array elements as I like. Any thoughts gratefully received.

 $resultp = mysql_query("select Primaryid from primarycodes where Code =
'".$row['Primaryexpertise']."'") or die (mysql_error());

 $resultp = mysql_query("select Primaryid from primarycodes where Code like
'%$row[Primaryexpertise]%'") or die (mysql_error());

 $pcodeid = mysql_fetch_array($resultp) or die("No pcodeid");


Regards

Mick Lloyd
[EMAIL PROTECTED]
Tel: +44 (0)1684 560224


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[PHP-DB] MySQL errors on win32

2001-03-20 Thread Dirk Bonenkamp - Bean IT

Hi all,

I just installed apache, php  mysql on a win98 laptop. I normally use
linux 

Things work fine, but when I execute more queries in one script, I get
error messages like:

Warning: MySQL: Unable to save result set in c:/program files/apache
group/apache/htdocs/network-club.com/agenda.php4 on line 14

I saw something in the FAQ about this, but that was when upgrading.

I use Win98 SE UK, Apache 1.3.14, php 4.0.4pl1, Mysql 3.23.22-beta.

TIA,

Dirk


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[PHP-DB] No. of Users online right now?

2001-03-20 Thread Dan Eskildsen

Hi there,

This is a NewBie Question:
While out surfing I have often seen a message like:  "There are 17 users on
this site at the moment."

Can I do this with php?  Just to show how many people are on (browsing) the
site at that moment?  I run a community website.

Thanks

==
Regards from Denmark, Europe
Please cc your reply to [EMAIL PROTECTED]
==
I haven't lost my mind, I've got it backed up on TAPE somewhere...



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[PHP-DB] Expires Pages

2001-03-20 Thread Marcelo Pereira

Hello,

I'd like the user of my site to log in/out, but, how can I disallow the user to press 
the 'back button' of the browse after logout, and back to the page ???

What I need:

- The user press 'logout';
   if (user press the 'back button' of the browser) then
  show a page telling that the page expired just when the user clicked at logout.
   fi

I was reading about cookies, I think I have to go in this direction, but, how ???

Thanks in advance,

See ya.

Marcelo Pereira
Campinas' University - Brazil



RE: [PHP-DB] Expires Pages

2001-03-20 Thread Steve Brett

this should work ... in the top of the page, before any other headers are
sent

?php
header ("Ex-pires:Mon, 26 Jul 1997 05:00:00 GMT"); // Date in the past
header ("Last-Modified: " . gmdate("D, d M Y H:i:s") . " GMT");
// al-ways modified
header ("Cache-Control: no-cache, must-revalidate"); // HTTP/1.1
header ("Pragma: no-cache"); // HTTP/1.0
?

 -Original Message-
 From: Marcelo Pereira [mailto:[EMAIL PROTECTED]]
 Sent: 20 March 2001 12:32
 To: [EMAIL PROTECTED]
 Subject: [PHP-DB] Expires Pages
 
 
 Hello,
 
 I'd like the user of my site to log in/out, but, how can I 
 disallow the user to press the 'back button' of the browse 
 after logout, and back to the page ???
 
 What I need:
 
 - The user press 'logout';
if (user press the 'back button' of the browser) then
   show a page telling that the page expired just when the 
 user clicked at logout.
fi
 
 I was reading about cookies, I think I have to go in this 
 direction, but, how ???
 
 Thanks in advance,
 
 See ya.
 
 Marcelo Pereira
 Campinas' University - Brazil
 

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RE: [PHP-DB] problems configuring php and postgres - call to undefined function

2001-03-20 Thread Steve Brett

get the postgrtesql source code and untar then run ./configure etc etc on
postgresql

then run ./configure in php as

./configure --with-pgsql=/path/to/untarred/source/files

e.g.

postgresql source untarred to /usr/src/postgresql

php configure options are:

./configure --with-pgsql=/usr/src/postgresql/ 

and not /usr/local/pgsql

php needs to see the source code not the install dir.

Steve

 -Original Message-
 From: Gary Huntress [mailto:[EMAIL PROTECTED]]
 Sent: 20 March 2001 12:39
 To: [EMAIL PROTECTED]
 Subject: Re: [PHP-DB] problems configuring php and postgres - "call to
 undefined function"
 
 
 I just added phpinfo() to my test page and the "configure 
 command" section
 does NOT include --with-pgsqlclearly that is my problem
 
 I just deleted my php-4.0.4 source directory and reinstalled 
 the tarball,
 ran ./configure --with-pgsql=/usr/local/pgsql --with-xml ; make ; make
 install, received no errors and still have the same error.
 
 There is *something* that I'm not cleaning up properly..
 
 Regards,
 
 Gary
 
 "Rasmus Lerdorf" [EMAIL PROTECTED] wrote in message
 [EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
  What kind of binary install did you do?  An rpm?  If so, simply also
  install the rpm-devel package and it will compile nicely.
 
  -Rasmus
 
  On Tue, 20 Mar 2001, Gary Huntress wrote:
 
   I am trying to get postgresql (pg) support for php 
 working on my RH7
 box.  I
   had a working binary installation of postgres 7.03.  I 
 thought I had
 read
   that php4 had default support for pg, but my call to 
 pg_connect() gave
 me a
   "Call to undefined function" error.
  
   So, next I tried to re ./configure and
 add --with-pgsql=/usr/local/pgsql.
   That would not compile, bombing when it looked for 
 "postgres.h".   I did
 not
   have the pg source (since this was a binary installation) 
 so I installed
   that next (in /usr/src, if that matters)
  
   I deleted my existing binary installation of pg, and ran 
 ./configure;
 gmake;
   gmake install with no errors, and I added an entry in 
 /etc/ld.so.conf as
   stated in the pg INSTALL.   Pg is running fine with 
 several db and I can
   remotely connect, so I think thats ok.
  
   After finishing with the source installation of pg, I re- 
 ./configure
 php,
   make and get the same error looking for "postgres.h"
  
   kludge I then manually edited the ./configure file and added the
 include
   path to /usr/src/postgres/install/kludge  After this, I could
 successfully
   make php, then make install.
  
   I restarted apache, but I am still getting "Call to 
 undefined function".
  
   Any thoughts?   I'm pretty much out of ideas right now.
  
   Regards,
  
   Gary Huntress
  
  
  
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[PHP-DB] LO on postgreSQL HELP!

2001-03-20 Thread Patrick

Hallo!
I'm trying to read lo objects (images) from postgreSQL  using php's
pg_loreadall() function with the intention of put them dirctly on a html
document, but I can't. I also have problems about how to embed the result of
the pg_loread() on a html document.
Somebody can help me?
Thak you very much!



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[PHP-DB] mysql_result

2001-03-20 Thread Shahmat Dahlan

I'm trying to use mysql_result to extract data from one particular field
in a record. So I suppose the most viable solution is to use
mysql_result. But when I do this:

$sqlstmt="SELECT * FROM dept WHERE shortname=$shortname";
$result=mysql_query($sqlstmt);
$temp=mysql_result($result,0,"shortname"); -- This will give me an
error

Did I do anything wrong here?

Thanks in advance.
Shahmat


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Re: [PHP-DB] More on strings

2001-03-20 Thread Darryl Friesen

  $resultp = mysql_query("select Primaryid from primarycodes where Code =
 '".$row['Primaryexpertise']."'") or die (mysql_error());

  $resultp = mysql_query("select Primaryid from primarycodes where Code
like
 '%$row[Primaryexpertise]%'") or die (mysql_error());

  $pcodeid = mysql_fetch_array($resultp) or die("No pcodeid");

Two suggestions.:

First, stick the query into a variable instead of using it directly; that
way you can do some simple debugging (i.e. print the query to the page
instead of posting this email).  Second, take the array variable out of the
double quotes, like you did in the first line.

$sql = "select Primaryid from primarycodes where Code like'%" .
$row[Primaryexpertise] . "%'";
print $sql . "BR\n";
$resultp = mysql_query($sql) or die (mysql_error());


- Darryl

 --
  Darryl Friesen, B.Sc., Programmer/Analyst[EMAIL PROTECTED]
  Education  Research Technology Services, http://gollum.usask.ca/
  Department of Computing Services,
  University of Saskatchewan
 --
  "Go not to the Elves for counsel, for they will say both no and yes"




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Re: [PHP-DB] Select where

2001-03-20 Thread ben

On Wed, 21 Mar 2001, boclair wrote:

 This is simple but  I cannot see where I am going wrong
 
 I have a table members with one of the fields
 status, varchar(10)
 
 The values may be active or retired or deceased or null
 
 If I run the select
 
 SELECT * FROM members WHERE status = 'deceased';
 
 I getMySQL said: You have an error in your SQL syntax near
 '\'deceased\';' at line 1
 
 Will somebody show me the correct syntax
 
 Tim Morris
 
 
 

you need to pass the quotes to mysql, hence you have to backslash them in
the php code. Try :

$query="SELECT * FROM members WHERE status = \"deceased\"";

--
Ben
History is curious stuff You'd think by now we had enough Yet the fact
remains I fear They make more of it every year.


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Re: [PHP-DB] How do I test on number of fields ?

2001-03-20 Thread Jason Stechschulte

On Mon, Mar 19, 2001 at 10:06:52PM -0800, Toke Herkild wrote:
 I've written this login rutine
 
 But that doesn't work... I've tried to use mysql_num_rows too but I still
 get :
 bWarning/b:  Supplied argument is not a valid MySQL result resource in
 bg://web/herkild/html/loginout.php/b on line b113/bbr
 
 if ($ACTION == 'Login') {
   $query = "SELECT user.ID FROM user WHERE ";
   $query .= "user.brugerID = $LoginBrugerID AND ";
   $query .= "user.kodeord = $LoginKodeord;";
 
   $mysql_result = mysql_query($query, $mysql_link);
 
 (line 113 )  if ($row = mysql_fetch_row($mysql_result)){
 setcookie("Herkild_Domain", $row[0]);
 Logged_in();
   }
   else {
 wronguser();
   }
 }

It looks like you might be missing some quotes in your query.  After you
call mysql_query(), call mysql_error($mysql_link);  It will show you
your error in your query.

-- 
Jason Stechschulte
[EMAIL PROTECTED]
--
There are still some other things to do, so don't think if I didn't fix
your favorite bug that your bug report is in the bit bucket.  (It may be,
but don't think it.  :-)  Larry Wall in [EMAIL PROTECTED]

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Re: [PHP-DB] Select where

2001-03-20 Thread boclair


- Original Message -
From: boclair [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Wednesday, March 21, 2001 12:02 AM
Subject: [PHP-DB] Select where


 This is simple but  I cannot see where I am going wrong

 I have a table members with one of the fields
 status, varchar(10)

 The values may be active or retired or deceased or null

 If I run the select

 SELECT * FROM members WHERE status = 'deceased';

 I getMySQL said: You have an error in your SQL syntax near
 '\'deceased\';' at line 1

 Will somebody show me the correct syntax

___

 $query = "SELECT * FROM members where status='deceased'"

 Then just call the $query in your script
___

Thanks, I only gave the mySQL but the php scripting is


$deceased = mysql_query(SELECT * FROM members where
status=\'deceased\'");
 and later
while ($myrow = mysql_fetch_row($deceased))

MySQL now says in relation to the *while* line
Warning: Supplied argument is not a valid MySQL result resource

Tim Morris



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Re: [PHP-DB] mysql_result

2001-03-20 Thread Shahmat Dahlan

I've tried what you suggested and it works, thanks.


Russ Michell wrote:

 Try:

 $sqlstmt="SELECT * FROM dept WHERE shortname='$shortname'";
 //Include single quotes..

 Russ

 #---#

  "Believe nothing - consider everything"

   Russ Michell
   Anglia Polytechnic University Webteam
   http://gertrude.sipu.anglia.ac.uk/webteam
   [EMAIL PROTECTED]
   +44 (0)1223 363271 ext 2331

   www.theruss.com

 #---#


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Re: [PHP-DB] mysql_result

2001-03-20 Thread Shahmat Dahlan

That didn't quite work, I tried using single quote enclose within double
quotes and it works.
$sqlstmt="SELECT * FROM dept WHERE shortname='$shortname'";

Thanks anyway


ben wrote:

 On Tue, 20 Mar 2001, Shahmat Dahlan wrote:

  I'm trying to use mysql_result to extract data from one particular field
  in a record. So I suppose the most viable solution is to use
  mysql_result. But when I do this:
 
  $sqlstmt="SELECT * FROM dept WHERE shortname=$shortname";
  $result=mysql_query($sqlstmt);
  $temp=mysql_result($result,0,"shortname"); -- This will give me an
  error
 
  Did I do anything wrong here?
 
  Thanks in advance.
  Shahmat

 The problem is that the query is wrong. Try
 $sqlstmt="SELECT * FROM dept WHERE shortname=\"$shortname\"";

 (you need to send quotes to mysql if the type of shortname in your
 database is text or the like, that's why there's the \"$var\")

 --
 Ben
 History is curious stuff You'd think by now we had enough Yet the fact
 remains I fear They make more of it every year.


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Re: [PHP-DB] Select where

2001-03-20 Thread Darryl Friesen

 Thanks, I only gave the mySQL but the php scripting is

 $deceased = mysql_query(SELECT * FROM members where
 status=\'deceased\'");
  and later
 while ($myrow = mysql_fetch_row($deceased))

 MySQL now says in relation to the *while* line
 Warning: Supplied argument is not a valid MySQL result resource

Yikes!  I hope those are typos, and that you didn't cut and paste that query
from your script.  If you did, then it needs some work.  Try:

$deceased = mysql_query("SELECT * FROM members where status='deceased'");

You need the leading double quote before SELECT, and you don't need to
escape the single quotes.


- Darryl

 --
  Darryl Friesen, B.Sc., Programmer/Analyst[EMAIL PROTECTED]
  Education  Research Technology Services, http://gollum.usask.ca/
  Department of Computing Services,
  University of Saskatchewan
 --
  "Go not to the Elves for counsel, for they will say both no and yes"



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[PHP-DB] Dynamically build a form from mySQL table

2001-03-20 Thread Martin E. Koss

Hi,
I've been trying to figure this out by looking through the code in
phpMyAdmin but I'm not getting very far.

What I want to do is dynamically generate a form where I get a table row
containing the field name in one cell and the input field in the next cell,
for example:

$DatabaseName = "FocusDynamics";
$TableName = "Items";

// open the table and get all field names, sizes, etc.,

// for each Field name, print something like:

PRINT "tr\n";
PRINT "td$FieldName/td\n";
PRINT "tdinput type=\"text\" name=\"$FieldName\" value=\"$FieldValue\"
maxlength=\"FieldSize\"/td\n";
PRINT "/tr";

How do I get all this info from the table?

Thanks for any help.


Martin E. Koss
M: 07946-706459
E: [EMAIL PROTECTED]


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RE: [PHP-DB] problems configuring php and postgres - call to und efined function

2001-03-20 Thread Steve Brett

  --with-pgsql[=DIR]  Include PostgreSQL support.  DIR is the PostgreSQL
  base install directory, defaults to
/usr/local/pgsql.
  Set DIR to shared to build as a dl, or shared,DIR 
  to build as a dl and still specify DIR.

this did not work when i compiled.

pointing at the source did.

i tried pointing php at both dirs to no avail.


 -Original Message-
 From: Rasmus Lerdorf [mailto:[EMAIL PROTECTED]]
 Sent: 20 March 2001 16:09
 To: Steve Brett
 Subject: RE: [PHP-DB] problems configuring php and postgres - "call to
 und efined function"
 
 
 Well, you just didn't point PHP at the right place then.
 
 On Tue, 20 Mar 2001, Steve Brett wrote:
 
  it wouldn't compile without it.
 
  really.
 
 
 
   -Original Message-
   From: Rasmus Lerdorf [mailto:[EMAIL PROTECTED]]
   Sent: 20 March 2001 15:46
   To: Steve Brett
   Subject: RE: [PHP-DB] problems configuring php and 
 postgres - "call to
   und efined function"
  
  
   Well, that's not true.  If you install from source it 
 will install the
   libpq.a and the postgres.h files.  You should never point PHP
   at the raw
   source directory.
  
   -Rasmus
  
   On Tue, 20 Mar 2001, Steve Brett wrote:
  
just an add-on.
   
if you compile form source the --with-pgsql= needs to point
   to the source
directory in order to find the files it needs.
   
it does say in the php configure help option that it should
   point to the
install dir i think whihc is a bit confusing as i learnt to
   my peril (and
boredom)
   
Steve
   
 -Original Message-
 From: Rasmus Lerdorf [mailto:[EMAIL PROTECTED]]
 Sent: 20 March 2001 08:03
 To: Gary Huntress
 Cc: [EMAIL PROTECTED]
 Subject: Re: [PHP-DB] problems configuring php and
   postgres - "call to
 undefined function"


 What kind of binary install did you do?  An rpm?  If so,
   simply also
 install the rpm-devel package and it will compile nicely.

 -Rasmus

 On Tue, 20 Mar 2001, Gary Huntress wrote:

  I am trying to get postgresql (pg) support for php working
 on my RH7 box.  I
  had a working binary installation of postgres 7.03.  I
 thought I had read
  that php4 had default support for pg, but my call to
 pg_connect() gave me a
  "Call to undefined function" error.
 
  So, next I tried to re ./configure and add
 --with-pgsql=/usr/local/pgsql.
  That would not compile, bombing when it looked for
 "postgres.h".   I did not
  have the pg source (since this was a binary installation)
 so I installed
  that next (in /usr/src, if that matters)
 
  I deleted my existing binary installation of pg, and ran
 ./configure; gmake;
  gmake install with no errors, and I added an entry in
 /etc/ld.so.conf as
  stated in the pg INSTALL.   Pg is running fine with several
 db and I can
  remotely connect, so I think thats ok.
 
  After finishing with the source installation of pg, I re-
 ./configure php,
  make and get the same error looking for "postgres.h"
 
  kludge I then manually edited the ./configure file and
 added the include
  path to /usr/src/postgres/install/kludge  After this, I
 could successfully
  make php, then make install.
 
  I restarted apache, but I am still getting "Call to
 undefined function".
 
  Any thoughts?   I'm pretty much out of ideas right 
 now.
 
  Regards,
 
  Gary Huntress
 
 
 
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[PHP-DB] getmxrr() timed out

2001-03-20 Thread Vlad

Hi all
Such problem - I cant get MX records from my php script
When I use getmxrr() function it times out. But such functions as gethostbyname() work.
Anybody knows the problem?

Thanks, Vlad





RE: [PHP-DB] problems configuring php and postgres - call to und efined function

2001-03-20 Thread Rasmus Lerdorf

But did you have /usr/local/pgsql/include and /usr/local/pgsql/lib
directories with the correct files in them?

On Tue, 20 Mar 2001, Steve Brett wrote:

   --with-pgsql[=DIR]  Include PostgreSQL support.  DIR is the PostgreSQL
   base install directory, defaults to
 /usr/local/pgsql.
   Set DIR to shared to build as a dl, or shared,DIR
   to build as a dl and still specify DIR.

 this did not work when i compiled.

 pointing at the source did.

 i tried pointing php at both dirs to no avail.


  -Original Message-
  From: Rasmus Lerdorf [mailto:[EMAIL PROTECTED]]
  Sent: 20 March 2001 16:09
  To: Steve Brett
  Subject: RE: [PHP-DB] problems configuring php and postgres - "call to
  und efined function"
 
 
  Well, you just didn't point PHP at the right place then.
 
  On Tue, 20 Mar 2001, Steve Brett wrote:
 
   it wouldn't compile without it.
  
   really.
  
  
  
-Original Message-
From: Rasmus Lerdorf [mailto:[EMAIL PROTECTED]]
Sent: 20 March 2001 15:46
To: Steve Brett
Subject: RE: [PHP-DB] problems configuring php and
  postgres - "call to
und efined function"
   
   
Well, that's not true.  If you install from source it
  will install the
libpq.a and the postgres.h files.  You should never point PHP
at the raw
source directory.
   
-Rasmus
   
On Tue, 20 Mar 2001, Steve Brett wrote:
   
 just an add-on.

 if you compile form source the --with-pgsql= needs to point
to the source
 directory in order to find the files it needs.

 it does say in the php configure help option that it should
point to the
 install dir i think whihc is a bit confusing as i learnt to
my peril (and
 boredom)

 Steve

  -Original Message-
  From: Rasmus Lerdorf [mailto:[EMAIL PROTECTED]]
  Sent: 20 March 2001 08:03
  To: Gary Huntress
  Cc: [EMAIL PROTECTED]
  Subject: Re: [PHP-DB] problems configuring php and
postgres - "call to
  undefined function"
 
 
  What kind of binary install did you do?  An rpm?  If so,
simply also
  install the rpm-devel package and it will compile nicely.
 
  -Rasmus
 
  On Tue, 20 Mar 2001, Gary Huntress wrote:
 
   I am trying to get postgresql (pg) support for php working
  on my RH7 box.  I
   had a working binary installation of postgres 7.03.  I
  thought I had read
   that php4 had default support for pg, but my call to
  pg_connect() gave me a
   "Call to undefined function" error.
  
   So, next I tried to re ./configure and add
  --with-pgsql=/usr/local/pgsql.
   That would not compile, bombing when it looked for
  "postgres.h".   I did not
   have the pg source (since this was a binary installation)
  so I installed
   that next (in /usr/src, if that matters)
  
   I deleted my existing binary installation of pg, and ran
  ./configure; gmake;
   gmake install with no errors, and I added an entry in
  /etc/ld.so.conf as
   stated in the pg INSTALL.   Pg is running fine with several
  db and I can
   remotely connect, so I think thats ok.
  
   After finishing with the source installation of pg, I re-
  ./configure php,
   make and get the same error looking for "postgres.h"
  
   kludge I then manually edited the ./configure file and
  added the include
   path to /usr/src/postgres/install/kludge  After this, I
  could successfully
   make php, then make install.
  
   I restarted apache, but I am still getting "Call to
  undefined function".
  
   Any thoughts?   I'm pretty much out of ideas right
  now.
  
   Regards,
  
   Gary Huntress
  
  
  
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RE: [PHP-DB] problems configuring php and postgres - call to und efined function

2001-03-20 Thread Steve Brett


from phpinfo()

'./configure' '--with-mysql=no' '--with-apache=/usr/src/apache_1.3.14/'
'--with-pgsql=/usr/src/postgresql-7.0.3/' '--with-xml' '--enable-track-vars'
'--enable-trans-sid' '--with-gd'

Steve

 -Original Message-
 From: Rasmus Lerdorf [mailto:[EMAIL PROTECTED]]
 Sent: 20 March 2001 16:09
 To: Steve Brett
 Subject: RE: [PHP-DB] problems configuring php and postgres - "call to
 und efined function"
 
 
 Well, you just didn't point PHP at the right place then.
 
 On Tue, 20 Mar 2001, Steve Brett wrote:
 
  it wouldn't compile without it.
 
  really.
 
 
 
   -Original Message-
   From: Rasmus Lerdorf [mailto:[EMAIL PROTECTED]]
   Sent: 20 March 2001 15:46
   To: Steve Brett
   Subject: RE: [PHP-DB] problems configuring php and 
 postgres - "call to
   und efined function"
  
  
   Well, that's not true.  If you install from source it 
 will install the
   libpq.a and the postgres.h files.  You should never point PHP
   at the raw
   source directory.
  
   -Rasmus
  
   On Tue, 20 Mar 2001, Steve Brett wrote:
  
just an add-on.
   
if you compile form source the --with-pgsql= needs to point
   to the source
directory in order to find the files it needs.
   
it does say in the php configure help option that it should
   point to the
install dir i think whihc is a bit confusing as i learnt to
   my peril (and
boredom)
   
Steve
   
 -Original Message-
 From: Rasmus Lerdorf [mailto:[EMAIL PROTECTED]]
 Sent: 20 March 2001 08:03
 To: Gary Huntress
 Cc: [EMAIL PROTECTED]
 Subject: Re: [PHP-DB] problems configuring php and
   postgres - "call to
 undefined function"


 What kind of binary install did you do?  An rpm?  If so,
   simply also
 install the rpm-devel package and it will compile nicely.

 -Rasmus

 On Tue, 20 Mar 2001, Gary Huntress wrote:

  I am trying to get postgresql (pg) support for php working
 on my RH7 box.  I
  had a working binary installation of postgres 7.03.  I
 thought I had read
  that php4 had default support for pg, but my call to
 pg_connect() gave me a
  "Call to undefined function" error.
 
  So, next I tried to re ./configure and add
 --with-pgsql=/usr/local/pgsql.
  That would not compile, bombing when it looked for
 "postgres.h".   I did not
  have the pg source (since this was a binary installation)
 so I installed
  that next (in /usr/src, if that matters)
 
  I deleted my existing binary installation of pg, and ran
 ./configure; gmake;
  gmake install with no errors, and I added an entry in
 /etc/ld.so.conf as
  stated in the pg INSTALL.   Pg is running fine with several
 db and I can
  remotely connect, so I think thats ok.
 
  After finishing with the source installation of pg, I re-
 ./configure php,
  make and get the same error looking for "postgres.h"
 
  kludge I then manually edited the ./configure file and
 added the include
  path to /usr/src/postgres/install/kludge  After this, I
 could successfully
  make php, then make install.
 
  I restarted apache, but I am still getting "Call to
 undefined function".
 
  Any thoughts?   I'm pretty much out of ideas right 
 now.
 
  Regards,
 
  Gary Huntress
 
 
 
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 [EMAIL PROTECTED]
 


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 [EMAIL PROTECTED]

   
  
 
 

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Re: [PHP-DB] How to display HTML code?

2001-03-20 Thread Phillip Bow

Now that is cool.  I wish I had noticed that one before.  Would have saved a
lot of odd keystrokes.
--
phill

""Joe Brown"" [EMAIL PROTECTED] wrote in message
996a64$k3a$[EMAIL PROTECTED]">news:996a64$k3a$[EMAIL PROTECTED]...
 try:
 ?php
 echo htmlentities("A HREF=home.phpHome/A");
 ?
 ""Osman Omar"" [EMAIL PROTECTED] wrote in message
 00f901c0b0cf$c99e7da0$da604a2b@sony">news:00f901c0b0cf$c99e7da0$da604a2b@sony...
  Hi,
 
  Suppose I want to display HTML code eg "A HREF=home.phpHome/A"
 
  How can I do that in php?
 
 
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[PHP-DB] class method

2001-03-20 Thread bryan

I am really new working with classes.  Some of the ideas I am getting, some I am not.
I wrote this simple little class, with a connection method, and a method to loop 
through the
data.  I am not even sure if my code is write (for the loop), but I am having trouble
displaying the data.  My connection works fine, but my loop is jacked.  Could anyone
suggest or maybe correct a mistake (if you see any)?  Just looking to see if I am 
started in the right direction, or if I have this all bass ackwards.  
I have no clue if this is even possible.  I am looking to create a while loop for 
whatever
query I run, and make each row equal to whatever field I put in.  I have all variables
defined within the scope of my class.

Thanks for your help.
 
Code :

function getdata() {

$this-sql = $query;

$result = mysql_query($query);

$fetch = "mysql_fetch_array";

 while ($row = $fetch($result)) {
 
 $this-field = $row['$this-field'];

 }

 if(!$result) {
 
  $this-error = mysql_error();

 return;
 
}

}

**
End

thanks!!!

[ bryan fitch . programmer . [EMAIL PROTECTED] ]






Re: [PHP-DB] problems configuring php and postgres - FIXED

2001-03-20 Thread Gary Huntress

My thanks to everyone who provided me info and other hints/tips.

The vast majority of the problem was human error of course, sprinkling in a
few bad assumptions and some configuration problems...its amazing I got it
working at allbut it is :)

Thanks again to everyone.

Gary
"Rasmus Lerdorf" [EMAIL PROTECTED] wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
 But did you have /usr/local/pgsql/include and /usr/local/pgsql/lib
 directories with the correct files in them?

 On Tue, 20 Mar 2001, Steve Brett wrote:

--with-pgsql[=DIR]  Include PostgreSQL support.  DIR is the
PostgreSQL
base install directory, defaults to
  /usr/local/pgsql.
Set DIR to shared to build as a dl, or
shared,DIR
to build as a dl and still specify DIR.
 
  this did not work when i compiled.
 
  pointing at the source did.
 
  i tried pointing php at both dirs to no avail.
 
 

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[PHP-DB] Transmitting Arrays

2001-03-20 Thread Mark Collin

I have a form which dynamically builds a table by taking data out of a mysql
database

http://www.fyrespray.net/screenshots/admin/modifyscreenshot.php4?pageid=1

but i'm having problems whn i try to modify the data i'm trying to put all
the data into arrays serialize it, urlencode it then send it on to the next
page to put it into database and then send back to the original page when
its done, i'm having a problem actually sendig my arrays around though, the
second page doesn't seem to get any data after i have unserialized it and
urlunecoded it.

anyone have any ideas, i've been fiddleing about a load with the code and
there is a good chance i have totally messed it up now heres the state its
in atm though if you would like to look

http://www.fyrespray.net/screenshots/admin/modifyscreenshot.txt
http://www.fyrespray.net/screenshots/admin/modify.txt

(prolly need to save the first page if your browser is picking up the html
bits and making half of a web page up like mine does)


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Re: [PHP-DB] class method

2001-03-20 Thread JJeffman

I need a little more information to help you.
Is the $query variable a global one ? Or is it a property of the class ( var
$query; )  ?
Why are you assigning the "mysql_fetch_array" function to a variable if call
it is easier ?

You have misplaced the "if $result" statement, the right position, I think ,
is :

function getdata() {
$this-sql = $query;
$result = mysql_query($query);
if( $result ) { // Check if $result is valid instead of NOT valid
   // $fetch = "mysql_fetch_array";
   while ($row = mysql_fetch_array($result)) {
 $this-field = $row['$this-field'];
}
}
else  $this-error = mysql_error();
return;
}

HTH

Jayme.

www.conex.com.br/jjeffman/antispam.html

-Mensagem Original-
De: bryan [EMAIL PROTECTED]
Para: db [EMAIL PROTECTED]
Enviada em: tera-feira, 20 de maro de 2001 16:21
Assunto: [PHP-DB] class method


I am really new working with classes.  Some of the ideas I am getting, some
I am not.
I wrote this simple little class, with a connection method, and a method to
loop through the
data.  I am not even sure if my code is write (for the loop), but I am
having trouble
displaying the data.  My connection works fine, but my loop is jacked.
Could anyone
suggest or maybe correct a mistake (if you see any)?  Just looking to see if
I am
started in the right direction, or if I have this all bass ackwards.
I have no clue if this is even possible.  I am looking to create a while
loop for whatever
query I run, and make each row equal to whatever field I put in.  I have all
variables
defined within the scope of my class.

Thanks for your help.

Code :

function getdata() {

$this-sql = $query;

$result = mysql_query($query);

$fetch = "mysql_fetch_array";

 while ($row = $fetch($result)) {

 $this-field = $row['$this-field'];

 }

 if(!$result) {

  $this-error = mysql_error();

 return;

}

}

**
End

thanks!!!

[ bryan fitch . programmer . [EMAIL PROTECTED] ]






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Re: [PHP-DB] Dynamically build a form from mySQL table

2001-03-20 Thread JJeffman

If you are using MySQL you can use the "mysql_list_fields" to get the fields
names from a table.

HTH

Jayme.

-Mensagem Original-
De: Martin E. Koss [EMAIL PROTECTED]
Para: [EMAIL PROTECTED]
Enviada em: tera-feira, 20 de maro de 2001 12:02
Assunto: [PHP-DB] Dynamically build a form from mySQL table


 Hi,
 I've been trying to figure this out by looking through the code in
 phpMyAdmin but I'm not getting very far.

 What I want to do is dynamically generate a form where I get a table row
 containing the field name in one cell and the input field in the next
cell,
 for example:

 $DatabaseName = "FocusDynamics";
 $TableName = "Items";

 // open the table and get all field names, sizes, etc.,

 // for each Field name, print something like:

 PRINT "tr\n";
 PRINT "td$FieldName/td\n";
 PRINT "tdinput type=\"text\" name=\"$FieldName\" value=\"$FieldValue\"
 maxlength=\"FieldSize\"/td\n";
 PRINT "/tr";

 How do I get all this info from the table?

 Thanks for any help.


 Martin E. Koss
 M: 07946-706459
 E: [EMAIL PROTECTED]


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Re: [PHP-DB] No. of Users online right now?

2001-03-20 Thread JJeffman

Have a look on Sessions. You can also write to a database every time a new
visitor runs into your site and check if the other are still connected.

You have to create a script that tracks every movement of the visitor. It is
not a simple script. As far as I know the web server doesn't give you this
information .

HTH.

Jayme.

-Mensagem Original-
De: Dan Eskildsen [EMAIL PROTECTED]
Para: [EMAIL PROTECTED]
Enviada em: tera-feira, 20 de maro de 2001 07:46
Assunto: [PHP-DB] No. of Users online right now?


 Hi there,

 This is a NewBie Question:
 While out surfing I have often seen a message like:  "There are 17 users
on
 this site at the moment."

 Can I do this with php?  Just to show how many people are on (browsing)
the
 site at that moment?  I run a community website.

 Thanks

 ==
 Regards from Denmark, Europe
 Please cc your reply to [EMAIL PROTECTED]
 ==
 I haven't lost my mind, I've got it backed up on TAPE somewhere...



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Re: [PHP-DB] class method

2001-03-20 Thread bryan

Yeah, the var $query is defined to the class.

I did mistype the result, thanks.

I was able to make this bad boy work with placing

$field = $row['row_name'];  // whatever the row is called.

But, if that is the case, why would I need a class?
I am just trying to make it so that I can use the
loop for any query that needs it, and can show any row
when I need it.

I appreciate your help!  Thanks a lot
bryan



- Original Message -
From: "JJeffman" [EMAIL PROTECTED]
To: "db" [EMAIL PROTECTED]
Sent: Tuesday, March 20, 2001 1:46 PM
Subject: Re: [PHP-DB] class method


 I need a little more information to help you.
 Is the $query variable a global one ? Or is it a property of the class (
var
 $query; )  ?
 Why are you assigning the "mysql_fetch_array" function to a variable if
call
 it is easier ?

 You have misplaced the "if $result" statement, the right position, I think
,
 is :

 function getdata() {
 $this-sql = $query;
 $result = mysql_query($query);
 if( $result ) { // Check if $result is valid instead of NOT valid
// $fetch = "mysql_fetch_array";
while ($row = mysql_fetch_array($result)) {
  $this-field = $row['$this-field'];
 }
 }
 else  $this-error = mysql_error();
 return;
 }

 HTH

 Jayme.

 www.conex.com.br/jjeffman/antispam.html

 -Mensagem Original-
 De: bryan [EMAIL PROTECTED]
 Para: db [EMAIL PROTECTED]
 Enviada em: tera-feira, 20 de maro de 2001 16:21
 Assunto: [PHP-DB] class method


 I am really new working with classes.  Some of the ideas I am getting,
some
 I am not.
 I wrote this simple little class, with a connection method, and a method
to
 loop through the
 data.  I am not even sure if my code is write (for the loop), but I am
 having trouble
 displaying the data.  My connection works fine, but my loop is jacked.
 Could anyone
 suggest or maybe correct a mistake (if you see any)?  Just looking to see
if
 I am
 started in the right direction, or if I have this all bass ackwards.
 I have no clue if this is even possible.  I am looking to create a while
 loop for whatever
 query I run, and make each row equal to whatever field I put in.  I have
all
 variables
 defined within the scope of my class.

 Thanks for your help.

 Code :
 
 function getdata() {

 $this-sql = $query;

 $result = mysql_query($query);

 $fetch = "mysql_fetch_array";

  while ($row = $fetch($result)) {

  $this-field = $row['$this-field'];

  }

  if(!$result) {

   $this-error = mysql_error();

  return;

 }

 }

 **
 End

 thanks!!!

 [ bryan fitch . programmer . [EMAIL PROTECTED] ]






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[PHP-DB] Sessions and MySQL

2001-03-20 Thread Rob Wheeldon

I am trying to implement session support with mysql. I am using
session.set_save_handler but don't really have a great set of functions does
anyone have some good ones?



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[PHP-DB] Loading extensions

2001-03-20 Thread Shahmat Dahlan

I have IIS 4 with PHP 4pl1 running on Win NT 4. I can't seem to load the
(*.dll) extensions. There seem to be something wrong with the extension
path. The browsercap.ini path is pointing to the right path. Can anyone
help?

Thanks in advance.
Shahmat


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[PHP-DB] A NETWORK MARKETER?

2001-03-20 Thread timmyralley8627




ATTENTION:  ANY SERIOUS NETWORK MARKETER
TAKE A LOOK AT THE FOLLOWING OPPORTUNITY I CAME ACROSS!!
IF YOU PLUG INTO THEIR PROVEN SYSTEM, THEY GUARANTEE YOU SUCCESS, 
AND PROVIDE YOU WITH FREE LEADS TO BUILD YOUR GROUP!!


DO NOT LET THIS SLIP AWAY!!  CLICK BELOW AND FIND OUT AS I DID,
WHY THESE GUYS ARE THE LEADERS IN THE INDUSTRY!!



http://www.geocities.com/businessupdates2000




*
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24 Hours, SIMPLYEMAIL [EMAIL PROTECTED] FOR IMMEDIATE 
REMOVAL FROM ANY FUTURE EMAILS FROM OUR COMPANY.
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Re: [PHP-DB] Loading extensions

2001-03-20 Thread Yasuo Ohgaki

I've posted notes on PHP Manual

http://www.php.net/manual/en/install-windows.php

It might help.

--
Yasuo Ohgaki


""Shahmat Dahlan"" [EMAIL PROTECTED] wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
 I have IIS 4 with PHP 4pl1 running on Win NT 4. I can't seem to load the
 (*.dll) extensions. There seem to be something wrong with the extension
 path. The browsercap.ini path is pointing to the right path. Can anyone
 help?

 Thanks in advance.
 Shahmat


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