[PHP-DB] how to "email article to a friend"

2001-06-19 Thread sgibbs

I'm a newbie and have only worked with php to send email from webform input.
I now want to add a new feature to my website: "Email article to a friend"
and I don't know where to start. 

I want to add this feature to webpages that are dynamically created from a
mysql database.  How do I pull this same info. and send it in an email?

I'm desperately looking for help at the absolute basic level. I'm not even
clear on how I would "grab" the current url from which I want to email.

Please respond to my email directly as I'm on the digest version. I'll print
a summary and post to the list afterwards.

Thank you, Shawna

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[PHP-DB] Any word in how to connect to PPROGRESS db using PHP.

2001-06-19 Thread Hector M Banda

Hi all,

Does any body have any information about how to access a PROGRESS
database using PHP?

I know this has been asked before and I just want to be upto date.

Thanks,

-- 


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Fax: (425) 790-6379
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[PHP-DB] Search in a MySQL TEXT field

2001-06-19 Thread Antonio Mármol Albert

Hello,

What is the better method for doing searchs in a TEXT field ?

I have news in a web, but I think that use << field LIKE '%foo%' >> can
overload my server if the traffic grows up.

Have you any reference about this? (urls, scripts, methods, documents...)

Thanks
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http://www.infurma.es

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[PHP-DB] One quick favor!!!!!!

2001-06-19 Thread Scott Fletcher

When I get the data from the database and put it into the ""
code and use it in the post form, " . ".  And so on.
When I click the hyperlink to go to the next page, I saw the ugly code in
the URL address section of the web browser's window.  It said,
"http://*/test_final/cart/cart_index.php?menu=category&category=fruit%20
%20%20%20%20%20%20%20%20%PHPSESSID=0E731DE82293C1E5FE524448731F7006".

How do I got rid of hte "20%" data since I only have the word,"fruit"
from the database table.  I suspect that it have to do with the HTML form
post and get method.  How do I get rid of it???

Thanks!
 Scott



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Re: [PHP-DB] Query in a function

2001-06-19 Thread Andreas D. Landmark

At 19.06.2001 09:21, you wrote:
>Hello
>I have a query that I have placed in a function that is in a file that I
>"include" in the page to be displayed. It doesn't work. I know that the code
>works because when I place the code in the page to be displayed directly it
>works fine.
>
>I can't figure it out. Thanks in advance for any help.
>John
>
>Here is the function contained in lib.inc:
>function type_select()
>{
>$connection = mysql_connect($server, $user, $pass);

are $server, $user and $pass global variables?
If not, they wouldn't be available inside the function and you'd either 
have to make
them global, or pass them to the function.

That could explain why you can't connect...


-- 
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Real Time, adj.:
 Here and now, as opposed to fake time, which only occurs there
and then.


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[PHP-DB] Why?

2001-06-19 Thread Chadwick Rolfs

Why do I recieve, but cannot post.  I keep getting permanent errors from
the mailer daemons.  Sorry, I don't have a copy of the last one, but I
don't think this message will go through

Chadwick Rolfs



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[PHP-DB] Informix question

2001-06-19 Thread Bård Farstad

Hi all,

I'm writing an application which uses the PHP interface to informix. I'm 
having trouble with newlines in char/varchar or lvarchar fields.

How can I store newlines (\n) to an informix database without using blobs?

I'm using:

-- 
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Systems developer
ez.no | developer.ez.no | zez.org

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[PHP-DB] products

2001-06-19 Thread bryan

I am pulling some products out of my database (doing some other things to
it), but basically making a big array.

Now, if I want to set my quantity to zero, and remove every instance where 
the $iID is, i should be able to do :

  if($cart[num_items] == "0") {
   
session_unregister('cart');
   
   } else {
  
unset($cart[products][$iID]);
   
  }

If I have one product in the array, it works fine.  If I have two products in the 
array,
it does nothing (except decrements my number of items in the cart).

Could anyone show me another solution to this problem?

thanks so much
bryan




Re: [PHP-DB] mssql_fetch_array problem

2001-06-19 Thread Dan Brunner

Hello!!!

Try using the second argument of mysql _fetch_array
MYSQL_NUM

This will insure that an integer is used..



If not let me knowI'll do testing...


Dan Brunner






On Monday, June 18, 2001, at 11:18 PM, Jennifer Arcino Demeterio wrote:

> hello all,
>
> hope someone could help me 
>
> it seems that the mssql_fetch_array did not work as it should when the 
> data
> type to be fetch is an integer ... is there any work around for this?
>
> Below is my script ...
>
> $country_sql = "select countryname, countryid from TBL_COUNTRY";
> if ($country_query = mssql_query($country_sql)) {
>while ($myrow = mssql_fetch_array($country_query))
>   if ($country == $myrow["countryid"]) {
>print " selected>" .
> $countryid . "";
>  } else {
>print "" .
> $countryid . "";
>  }
>   }
> }
>
>
> Thanks!
>
>
>
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Re: [PHP-DB] mssql_fetch_array problem

2001-06-19 Thread Anil Kumar



try:

 if ($country == intval($myrow["countryid"]))

mssql_fetch_array is found to have some weird behavior.
 






On Tue, 19 Jun 2001, Jennifer Arcino Demeterio wrote:

> hello all,
> 
> hope someone could help me 
> 
> it seems that the mssql_fetch_array did not work as it should when the data
> type to be fetch is an integer ... is there any work around for this?
> 
> Below is my script ...
> 
> $country_sql = "select countryname, countryid from TBL_COUNTRY";
> if ($country_query = mssql_query($country_sql)) {
>while ($myrow = mssql_fetch_array($country_query))
>   if ($country == $myrow["countryid"]) {
>print "" .
> $countryid . "";
>  } else {
>print "" .
> $countryid . "";
>  }
>   }
> }
> 
> 
> Thanks!
> 
> 
> 
> 

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Re: [PHP-DB] One quick favor!!!!!!

2001-06-19 Thread Hugh Bothwell

Each '%20' is a URL-encoded space character.  In other words, the string you
are getting back from your database query looks like 'fruit  '.  I
suspect you coded the field as a fixed-length string.

The best long-term fix is to change the field type to a variable-length
string, so that 'fruit' is returned without trailing spaces.

For a quick stop-gap, look at the PHP function trim().

""Scott Fletcher"" <[EMAIL PROTECTED]> wrote in message
9go2fi$q1h$[EMAIL PROTECTED]">news:9go2fi$q1h$[EMAIL PROTECTED]...
> When I get the data from the database and put it into the ""
> code and use it in the post form, " . ".  And so
on.
> When I click the hyperlink to go to the next page, I saw the ugly code in
> the URL address section of the web browser's window.  It said,
>
"http://*/test_final/cart/cart_index.php?menu=category&category=fruit%20
> %20%20%20%20%20%20%20%20%PHPSESSID=0E731DE82293C1E5FE524448731F7006".
>
> How do I got rid of hte "20%" data since I only have the word,"fruit"
> from the database table.  I suspect that it have to do with the HTML form
> post and get method.  How do I get rid of it???
>
> Thanks!
>  Scott




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[PHP-DB] php accessing oracle

2001-06-19 Thread Martin Langlois

I want to make a query from a oracle database with php. That's what I do:

$link=Ora_Logon("user","1234");
$query = "select * from sales";
$cursor = ora_do($link,$query);
while(ora_fetch($cursor))
{   
print "$cursor";
}

I have an arror, it's doesn't recongnize ora_logon() function.

Do i have to include something special?




-- 
Martin Langlois
Programmeur-analyste
Inter.net Canada
5252, boul. de Maisonneuve Ouest
bureau 200
Montréal,Qc
H4A 3S5

http://www.ca.inter.net



Re: [PHP-DB] Query in a function

2001-06-19 Thread Jimmy Brake

errr maybe

you need to pass the function the values of the variables you are using either by 
declaring them global inside the function:

global $server,$user,$pass,$type_id;

or passing them to the function directly:

function type_select($server,$user,$pass,$type_id)

hope this helps :-)

Jimmy Brake

On Tue, 19 Jun 2001, seriousj wrote:

> Hello
> I have a query that I have placed in a function that is in a file that I
> "include" in the page to be displayed. It doesn't work. I know that the code
> works because when I place the code in the page to be displayed directly it
> works fine.
> 
> I can't figure it out. Thanks in advance for any help.
> John
> 
> Here is the function contained in lib.inc:
> function type_select()
> {
>$connection = mysql_connect($server, $user, $pass);
>echo("");
>$query1 = "SELECT * FROM type";
>$result1 = mysql_db_query($db, $query1, $connection);
>echo(!isset($type_id)?"--Please select a
> Type--":"");
>if(mysql_num_rows($result1) > 0)
>{
>   while($row1 = mysql_fetch_array($result1))
>   {
>  $result1_type_id = $row1["type_id"];
>  $result1_type_desc = $row1["type_description"];
>  echo("  echo(isset($type_id)?($result1_type_id==$type_id ? "selected " :
> ""):"");
>  echo("value=\"");
>  echo($result1_type_id);
>  echo("\">");
>  echo( $result1_type_desc);
>  echo("");
>   }
>}
>else
>{
>   echo("Error");
>}
>echo("");
> }
> 
> And here is the call to that function in the page that is displayed:
> include("lib.inc");
> ?>
> 
>  //TYPE selection
> if(!isset($type_id))
> {
>type_select();
> }
> 
> And here is the error message:
> Warning: MySQL Connection Failed: Can't connect to local MySQL server
> through socket '/tmp/mysql.sock' (2) in
> /web/sites/268/seriousj/www.mccartney.f2s.com/opus/tnzp/lib.inc on line 21
> 
> 
> 
> 
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> 


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[PHP-DB] mysql client compression with php?

2001-06-19 Thread Shriram Chaubal \(Personal\)

Hi,

I have to connect my php server to a remote mysql database and would like to
minimize the bandwidth usage.

Adding a setting in my.cnf as follows only seems to affect the mysql client
applications and not php.

[client]
compress

I have noticed a define in the php sources called "HAVE_COMPRESS" but have
no clue where it gets defined.

Any tips?

Cheers,
Shri






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[PHP-DB] PHP and MRTG

2001-06-19 Thread Guðmundur Ö. Ingvarsson

Is anyone out there using PHP in conjunction with MRTG?

I'm currently looking for a PHP script that analyzes a MRTG log file and
generates the image

Kveðja / Regards

==
Guðmundur Örn Ingvarsson
Chief technician of daily operations /
Rekstrarstjóri á rekstrarborði
Íslandssími hf
Web Site - http://www.islandssimi.is
E-Mail - [EMAIL PROTECTED]
Buisness phone - +354 595 5000
==


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RE: [PHP-DB] mssql_fetch_array problem

2001-06-19 Thread Craig Vincent

Not being able to see your code and not knowing exactly what problem you are
having I can only throw a few guesses here.  If you could elaborate more on
what you are expecting and what you are getting that would be a big help.


$country_sql = "select countryname, countryid from TBL_COUNTRY";


You don't use the value of countryname anywhere in your statement...is it
necessary?


if ($country_query = mssql_query($country_sql)) {


What is this statement intended to do?  Typical when a query is formed PHP
gives the query an integer id.  But that ID is allocated by PHP and if you
add a new query earlier in the code later on the ID for this query will most
likely change...which then will make it not equal what you're expecting it
to equal...in this case $country_query.

Also on a further note you need to use == instead of = otherwise PHP will
assume the statement is always true.


   while ($myrow = mssql_fetch_array($country_query))
  if ($country == $myrow["countryid"]) {
   print "" .
$countryid . "";
 } else {
   print "" .
$countryid . "";
 }
  }
}


Your while statement is missing a { was this code working when you used
it?
Also unless you need PHP returning the success of printing the text you're
better off using echo instead of print.

Based on what I see this code may be what you're looking for

(untested)
$country_sql = 'SELECT countryid FROM TBL_COUNTRY';
while ($myrow = mssql_fetch_row($country_query)) {
echo "$myrow[0]"; }
else { echo ">$myrow[0]"; }
}

Sincerely,

Craig Vincent


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RE: [PHP-DB] mssql_fetch_array problem

2001-06-19 Thread Michael Rudel

Hi Jennifer,

… I think that you want to display the Countryname in the DropDownBox, won't you ?

Try this one (in your while-loop):


if ($country == $myrow["countryid"])
{
   print ""
   . $myrow["countryname"]
   . ""
   . "\n";
}
else
{
   print ""
   . $myrow["countryname"]
   . ""
   . "\n";
}


Hope this helps. If not, plz post what is going wrong.

Greetinx,
  Mike

Michael Rudel
- Web-Development, Systemadministration -
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fax: +49-(0)7531-89207-13
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> -Original Message-
> From: Jennifer Arcino Demeterio [mailto:[EMAIL PROTECTED]]
> Sent: Tuesday, June 19, 2001 6:18 AM
> To: [EMAIL PROTECTED]
> Subject: [PHP-DB] mssql_fetch_array problem
>
>
> hello all,
>
> hope someone could help me 
>
> it seems that the mssql_fetch_array did not work as it should
> when the data
> type to be fetch is an integer ... is there any work around for this?
>
> Below is my script ...
>
> $country_sql = "select countryname, countryid from TBL_COUNTRY";
> if ($country_query = mssql_query($country_sql)) {
>while ($myrow = mssql_fetch_array($country_query))
>   if ($country == $myrow["countryid"]) {
>print " " selected>" .
> $countryid . "";
>  } else {
>print "" .
> $countryid . "";
>  }
>   }
> }
>
>
> Thanks!
>
>
>
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>


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[PHP-DB] Query in a function

2001-06-19 Thread seriousj

Hello
I have a query that I have placed in a function that is in a file that I
"include" in the page to be displayed. It doesn't work. I know that the code
works because when I place the code in the page to be displayed directly it
works fine.

I can't figure it out. Thanks in advance for any help.
John

Here is the function contained in lib.inc:
function type_select()
{
   $connection = mysql_connect($server, $user, $pass);
   echo("");
   $query1 = "SELECT * FROM type";
   $result1 = mysql_db_query($db, $query1, $connection);
   echo(!isset($type_id)?"--Please select a
Type--":"");
   if(mysql_num_rows($result1) > 0)
   {
  while($row1 = mysql_fetch_array($result1))
  {
 $result1_type_id = $row1["type_id"];
 $result1_type_desc = $row1["type_description"];
 echo("");
 echo( $result1_type_desc);
 echo("");
  }
   }
   else
   {
  echo("Error");
   }
   echo("");
}

And here is the call to that function in the page that is displayed:
include("lib.inc");
?>

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[PHP-DB] Informix & blobs problem -609 / core dump

2001-06-19 Thread Christian Haul

Hi.
 
When trying to insert anything into a BLOB column in informix I get a
-609 error back (invalid use of TEXT/BYTE host variable), no matter
what parameters used when ifx_create_blob'ing. Inserting into TEXT
columns does work OK.
 
When trying to read anything from a TEXT or BLOB column, php dies.
"child pid 4286 exit signal Segmentation fault (11)"
 
Setup
 
SuSE 7.0
Linux 2.2.19-i686 (PIII)
Informix Dynamic Server 2000 Version 9.21.UC3
apache 1.3.17
php-4.0.4pl1
 
or
 
Sun Solaris 7
U60
Informix Dynamic Server 2000 Version 9.20.UC2
php-4.0.4pl1
apache 1.3.11
 
Attached you'll find a) the db definition b) a small script for
inserting data and c) a small script to read the data.
 
As the informix code didn't change in 4.0.5 (no diff on source in
extensions/informix) I haven't tried upgrading.
 
Help appreciated.
 
TIA,
 
Chris.

--
create database test_shen in public;

database test_shen;

create table test (
   id serial,
   b1 blob,
   t1 text,
   primary key (id)
);

select * from test;

grant connect to 'infdb1';
grant all on test to 'infdb1';




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[PHP-DB] mssql_fetch_array problem

2001-06-19 Thread Jennifer Arcino Demeterio

hello all,

hope someone could help me 

it seems that the mssql_fetch_array did not work as it should when the data
type to be fetch is an integer ... is there any work around for this?

Below is my script ...

$country_sql = "select countryname, countryid from TBL_COUNTRY";
if ($country_query = mssql_query($country_sql)) {
   while ($myrow = mssql_fetch_array($country_query))
  if ($country == $myrow["countryid"]) {
   print "" .
$countryid . "";
 } else {
   print "" .
$countryid . "";
 }
  }
}


Thanks!



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