Re: [PHP-DB] Session End

2002-02-09 Thread Jeroen Timmers

hello,

i think you could not realize that with php and sessions.

Because you can not read the session from a visitor.

or ?

Jeroen

- Original Message -
From: Hayan Al Mamoun [EMAIL PROTECTED]
To: PHPList (E-mail) [EMAIL PROTECTED]
Sent: Saturday, February 09, 2002 7:52 AM
Subject: [PHP-DB] Session End


 Hi, How can I realize that one session in PHP has been ended, I mean I
want
 a trigger that the visitor of my website, has left ;)
 Thanks

 Best Regards
 Hayan


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Re: [PHP-DB] Maintain MySQL Transactions

2002-02-09 Thread Jeroen Timmers

what would you like todo?
explain further

Jeroen
- Original Message - 
From: Hayan Al Mamoun [EMAIL PROTECTED]
To: PHPList (E-mail) [EMAIL PROTECTED]
Sent: Saturday, February 09, 2002 7:51 AM
Subject: [PHP-DB] Maintain MySQL Transactions


 Hi, How can I maintain MySQL transactions with PHP
 
 Best Regards
 Hayan
 
 
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[PHP-DB] Re: Oracle 9i support

2002-02-09 Thread Jarosaw Jankowski



Theodore D Boardman wrote:

 Greetings!

 As far as I can tell from the documentation, the OCI8 driver supports Oracle
 8. However, on the ADODB site, they mention that the OCI8 driver supports
 Oracle 8/9.

 Can someone clarify what the status of support for Oracle 9i is in PHP? I
 need to know if I need to stick with Oracle 8i now or not.

 Ted Boardman
 Communications Technology Editor
 Indiana University Alumni Association
 [EMAIL PROTECTED]
 http://www.alumni.indiana.edu

Hi,
As i know there is no problem with oracle 9i - there where some posts
about that in php manual in the OCI functions section.
Jarry




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[PHP-DB] Re: Creating temp table with data out of 2 tables possible?

2002-02-09 Thread Jarosaw Jankowski



Andy wrote:

 Hi there,

 how is it possible to copy rows from more then one table into a temporary
 table?

 I have 250 city tables named after the country e.g: ca_cities. Now the user
 has choosen stuff from
 lets say ca and gm. I want to collect the data into a temp table and then
 querry this temp table for other stuff.

 I always get the error:
 Error: 1060 Duplicate column name 'id'

 Here is my statement made for a sample of two tables creating the temporary
 one ( works with one)

  $stmt =
  CREATE TEMPORARY TABLE all_cities
  SELECT * FROM $DB2.$country_found[0]_cities,
 $DB2.$country_found[1]_cities
  ;

 Does anybody have a clue whats going on here?

 Thanx  for any help

 Andy

try to use coulumn names not * and rename columns
Jarek



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Re: [PHP-DB] Re: Oracle 9i support

2002-02-09 Thread Thies C. Arntzen

On Sat, Feb 09, 2002 at 01:10:58PM +0100, Jaros?aw Jankowski wrote:
 
 
 Theodore D Boardman wrote:
 
  Greetings!
 
  As far as I can tell from the documentation, the OCI8 driver supports Oracle
  8. However, on the ADODB site, they mention that the OCI8 driver supports
  Oracle 8/9.
 
  Can someone clarify what the status of support for Oracle 9i is in PHP? I
  need to know if I need to stick with Oracle 8i now or not.
 
  Ted Boardman
  Communications Technology Editor
  Indiana University Alumni Association
  [EMAIL PROTECTED]
  http://www.alumni.indiana.edu
 
 Hi,
 As i know there is no problem with oracle 9i - there where some posts
 about that in php manual in the OCI functions section.
 Jarry

9i work fine - we're even going to have scollable cursor
support in the oci-driver soon (which requires 9i).

tc
 
 

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Re: [PHP-DB] Maintain MySQL Transactions

2002-02-09 Thread Miles Thompson


Unless there has been a very recent development, MySQL doesn't support 
transactions. Use PostgreSQL, DB, etc.

Miles Thompson


At 09:51 AM 2/9/2002 +0300, Hayan Al Mamoun wrote:
Hi, How can I maintain MySQL transactions with PHP

Best Regards
Hayan


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Re: Re: [PHP-DB] Maintain MySQL Transactions

2002-02-09 Thread Jeroen Timmers

you must first connect to the mysql database,

for example

  $dbhost = localhost;
  $dbuser = DATABASE USER;
  $dbpass = DATABASE PASSWORD;
  $database = DATABASE NAME;
  @mysql_connect($dbhost, $dbuser, $dbpass) or die (Deze pagina is
tijdelijk offline.);
  @mysql_select_db($database) or die (Deze pagina is tijdelijk offline.);

after the connect you need to query the stuff

for example

$result = mysql_query(select * from table where id  5);
while ($row = mysql_fetch_array($result))
{
  echo $rij[0];
  echo $rij[id];
}

/* delete query */'
$result = mysql_query(delete from table where id = 1);
$nr = mysql_affected_rows($result);

echo $nr . rows are deleted.;

i hope you have enough info

the examples are not tested.

Jeroen Timmers.

http://www.php.net/manual/en/ref.mysql.php
- Original Message -
From: Hayan Al Mamoun [EMAIL PROTECTED]
To: Jeroen Timmers [EMAIL PROTECTED]
Sent: Saturday, February 09, 2002 12:54 PM
Subject: Re: Re: [PHP-DB] Maintain MySQL Transactions


 I have two sql statements, and I want to execute them all or
 nothing at all.
 For an example
 1- Delete * from sometable where Id=SOMETHING
 2- insert into OtherTable (fieldlist) values (valuelist) where
 Id=SOMETHING.
 How can I do so?




 
 Get your own 800 number
 Voicemail, fax, email, and a lot more
 http://www.ureach.com/reg/tag


  On Sat, 9 Feb 2002, Jeroen Timmers ([EMAIL PROTECTED])
 wrote:

  what would you like todo?
  explain further
 
  Jeroen
  - Original Message -
  From: Hayan Al Mamoun [EMAIL PROTECTED]
  To: PHPList (E-mail) [EMAIL PROTECTED]
  Sent: Saturday, February 09, 2002 7:51 AM
  Subject: [PHP-DB] Maintain MySQL Transactions
 
 
   Hi, How can I maintain MySQL transactions with PHP
  
   Best Regards
   Hayan
  
  
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   To unsubscribe, visit: http://www.php.net/unsub.php
  
  
 
 
 





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[PHP-DB] Searching records...

2002-02-09 Thread Todd Williamsen

What I am doing is user inputs their contact information, then copies and
pastes text and also uploads a formal document, which the location is stored
in the database.

Now, the text that gets pasted into the text field is then stored into the
database for search purposes.

This is the problem... How would I go about searching this field?  I wanted
to return all results with the keyword(s)?

This is what I came up with the Help of Nicole Amashta.  But it doesn't work
too hot.  I feel I am lost

=

?
include variables.php;
$delimiter = ,;

$connection = @mysql_connect($databaseserver, $databaseuser, $databasepass)
or die (could not connect to database);
$db = @mysql_select_db($databasename, $connection) or die(Could not select
database);
$sql = SELECT id, FirstName, LastName, Resume, ResumeUp FROM
$canidatetable;
$result = mysql_query($sql, $connection) or die(Couldn't execute query);

while ($row = mysql_fetch_array($result))
   {
$id = $row['id'];

$FirstName = $row['FirstName'];

$LastName = $row['LastName'];

$filename = $row['Resume'];
 $ResumeUp = $row['ResumeUp'];

   $keywords = explode( $delimiter, $words );

   for ($i=0; $i  count($keywords); $i++) {

   $kw = $keywords[$i];

 if( eregi($kw, $contents) ) {

echo The Words b$kw/b has been found in the resume of

olli$LastName, $FirstName a
href=\http://madden.williamsen.net/recruiter/resumes/$ResumeUp\;Resume/a
/li/ol;
}
else {
echo The keyword $kw was not found in the resume
$LastName, $FirstNamebr;
}
  }

}

?
=



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Re: [PHP-DB] Searching records...

2002-02-09 Thread Jason Wong

On Sunday 10 February 2002 00:58, Todd Williamsen wrote:
 What I am doing is user inputs their contact information, then copies and
 pastes text and also uploads a formal document, which the location is
 stored in the database.

 Now, the text that gets pasted into the text field is then stored into the
 database for search purposes.

 This is the problem... How would I go about searching this field?  I wanted
 to return all results with the keyword(s)?

 This is what I came up with the Help of Nicole Amashta.  But it doesn't
 work too hot.  I feel I am lost

Please elaborate. What does doesn't work too hot mean?

Does it work or not?

If it doesn't, what's wrong with it?

If it does work, why don't you like it?

If it makes you feel better, I feel lost as well :)


-- 
Jason Wong - Gremlins Associates - www.gremlins.com.hk

/*
I'd love to go out with you, but I have to floss my cat.
*/

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Re: [PHP-DB] Maintain MySQL Transactions

2002-02-09 Thread Jason Wong

On Sunday 10 February 2002 00:21, Miles Thompson wrote:
 Unless there has been a very recent development, MySQL doesn't support
 transactions. Use PostgreSQL, DB, etc.

The v4 series of MySQL does support transactions.


-- 
Jason Wong - Gremlins Associates - www.gremlins.com.hk

/*
Without love intelligence is dangerous;
without intelligence love is not enough.
-- Ashley Montagu
*/

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Re: [PHP-DB] count from the results

2002-02-09 Thread Jason Wong

On Sunday 10 February 2002 00:55, Barry Rumsey wrote:
 I have the following code:
 $query = SELECT * FROM artist WHERE artist LIKE 'b%' ORDER BY artist
 ASC;

[snip]

 What I would like to know is how do I do a count on each result
 returned.e.g. Benny(4) , Bill(10)

Try:

$query = SELECT artist, count(artist) FROM artist WHERE artist LIKE 'b%' 
ORDER BY artist ASC;



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Jason Wong - Gremlins Associates - www.gremlins.com.hk

/*
Love is being stupid together.
-- Paul Valery
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Re: [PHP-DB] Resource link errors

2002-02-09 Thread Ken Thompson



Thanks Rick, Now it works.


On Thursday 07 February 2002 03:04 pm, Rick Emery wrote:
 The following means you have not opened a link to your database.
 Concerntrate your efforts there.

 Warning: Supplied argument is not a valid MySQL-Link
 resource in /var/www/html/list.php3 on line 26

 -Original Message-
 From: Ken Thompson [mailto:[EMAIL PROTECTED]]
 Sent: Thursday, February 07, 2002 3:23 PM
 To: [EMAIL PROTECTED]
 Subject: [PHP-DB] Resource link errors


 Hello all,
 I'm very new to php and have been beating my head on the wall over this for
 2
 days. I've searched through the php documentation but I guess I either
 don't

 know where or what to look for or don't understand what I'm seeing.
 I think this has to be an array but the original doesn't seem to think
 so.(see below)
 I've tried ($myrow = mysql_fetch_array($result)) and still get the same
 errors.
 The original that I used as an example works OK showing the results of
 Name,

 Position. They didn't include a data cell for $myrow[3] ...
 =
 THIS WORKS:
 ?php

 $title = Welcome to the Web-Site of; /*I commented this out and finaly
 removed it cuz I don't want the title echoed in the final page.*/

 include(header.inc);

 $result = mysql_query(SELECT * FROM employees,$db);

 echo table border=1\n;

 echo trtdName/tdtdPosition/tr\n;

 while ($myrow = mysql_fetch_row($result)) {

 echo(trtd%s %s/tdtd%s/tr\n, $myrow[1], $myrow[2],
 $myrow[3]);

 }

 echo /table\n;
 include(footer.inc);

 ?
 ===
 What I am trying to do is to return the results of the query into a table
 with these items:
 +---+-+--+-+-++

 | Field | Type| Null | Key | Default | Extra  |

 +---+-+--+-+-++

 | id| tinyint(4)  |  | PRI | NULL| auto_increment |
 | year  | int(4)  | YES  | | NULL||
 | make  | varchar(20) | YES  | | NULL||
 | model | varchar(20) | YES  | | NULL||
 | engine| varchar(20) | YES  | | NULL||
 | fuel  | varchar(8)  | YES  | | NULL||
 | trans | varchar(10) | YES  | | NULL||
 | condition | varchar(20) | YES  | | NULL||
 | price | varchar(10) | YES  | | 0   ||
 | location  | varchar(20) | YES  | | NULL||

 +---+-+--+-+-++
 These are the errors that show up when I run the page in the browser.
 The database is local and I'm on Linux-Mandrake 8.1 using Apache web
 server. I can get the results I want from the command line, that is I can
 make queries and get the proper info returned.
 what have I done to cause it not to work?


 Warning: Supplied argument is not a valid MySQL-Link
 resource in /var/www/html/list.php3 on line 26

 Warning: Supplied argument is not a valid MySQL result
 resource in /var/www/html/list.php3 on line 32

  THIS DOESN'T:
 I get the table and the item name e.g. Year, Make etc.
 Once I get the 3 cells returning the proper info, I want to add the rest of
 the cells needed to display all the info in the web page. I don't think it
 should be a problem, comments on this?

 ?php

 include(header.inc);

 //(Line 26 below, everything above ?php is plain html.)
 $result = mysql_query(SELECT * FROM autos,$db);

 echo table border=1\n;

 echo trtdYear/tdtdMake/tdtdModel/td/tr\n;

 //(Line 32 below)
 while ($myrow = mysql_fetch_row($result)) {

 //What does the '%s' mean? I read it someplace in the tutorial
 //but can't find it now.

 printf(trtd%s %s/tdtd%s/tr\n, $myrow[1], $myrow[2],
 $myrow[3]);

 }

 echo /table\n;
 include(footer.inc);

 ?

-- 

Ken Thompson, North West Antique Autos
Payette, Idaho
Email: [EMAIL PROTECTED]
http://www.nwaa.com
Sales and brokering of antique autos and parts.

Linux- Coming Soon To A Desktop Near You
Registered Linux User #183936


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[PHP-DB] Re: count from the results

2002-02-09 Thread Raymond Lilleodegard

Hi Barry!

you can do it like this for example:

 $query = SELECT * FROM artist WHERE artist_name LIKE 'b%' ORDER BY artist
ASC;

 $count = mysql_query(SELECT COUNT(artist) AS count FROM artist WHERE
artist_name LIKE 'b%',$db);
 $x = mysql_fetch_array($count);
 $result = mysql_query($query) or die(Select Failed!);
 $number = $x[count];
 echo h3Total Number Of Artists In \B\:nbsp;nbsp;;
 echo $number;
 echo brbr/h3;

 if (mysql_num_rows($result)) {
 echo table;
 echo trthArtists/th;
 while ($qry = mysql_fetch_array($result)){
 echo tr;
 echo td;
 echo $qry[artist];
 }}?


Barry Rumsey [EMAIL PROTECTED] wrote in message
news:[EMAIL PROTECTED]...
 I have the following code:
 $query = SELECT * FROM artist WHERE artist LIKE 'b%' ORDER BY artist
 ASC;
 $result = mysql_query($query) or die(Select Failed!);
 echo h3Total Number Of Artists In \B\:nbsp;nbsp;;
 echo mysql_num_rows($result);
 echo brbr/h3;
 if (mysql_num_rows($result)) {
 echo table;
 echo trthArtists/th;
 while ($qry = mysql_fetch_array($result)){
 echo tr;
 echo td;
 echo $qry[artist];
 }}?

 What I would like to know is how do I do a count on each result
 returned.e.g. Benny(4) , Bill(10)





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Re: [PHP-DB] Maintain MySQL Transactions

2002-02-09 Thread Paul DuBois

At 2:00 +0800 2/10/02, Jason Wong wrote:
On Sunday 10 February 2002 00:21, Miles Thompson wrote:
  Unless there has been a very recent development, MySQL doesn't support
  transactions. Use PostgreSQL, DB, etc.

The v4 series of MySQL does support transactions.

MySQL has supported transactions since version 3.23.17.  At that time
BDB tables were the only transaction-capable type.  InnoDB tables were
added in version 3.23.34a.

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[PHP-DB] Re: option in forms

2002-02-09 Thread Adam Royle

I think this is what you're getting at:

select name=artistID
option value=?= $row[ID] ??= $row[ArtistName] ?/option
/select

or something like that so it would look like (in HTML)

select name=artistID
option value=23Artist's Name First in list/option
option value=44Artist's Name second in list/option
option value=105Artist's Name third in list/option
/select

if you select the first item in the list, the next page will produce:

$artistID = 23

so yah... thats it
---____-_--_-_-_-_-___-___--_-_-_-_--

I know how to do the option call e.g.
This is the list of artists already in our database :
SELECT name=artist
?php echo $option_block; ?
/SELECT
But I want to do a form where they select the option then fill out rest
of form. The option above returns the artist name, but I want to insert
the artistid.


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[PHP-DB] Outputing Distinct rows

2002-02-09 Thread KingZeus

I'll give you all the short version of what I need and if it is enough for
you to help that would be great. I need to pull the last 10 updated topics
from a table and output them. However, the posts table lists each post and
then has a topic id. There is also a table of topics with topic id, title,
etc. I cannot just pull the last 10 posts in the post table because those
posts could all be for the same topic and I'm trying to output the last 10
updated topics (not posts). How can I do this? I can't find anything on the
subject. This is what I tried as a random guess:
$sql = SELECT DISTINCT posts.topic_id, posts.forum_id,  topics.topic_title,
topics.topic_replies WHERE topics.topic_id = posts.topic_id DESC LIMIT 10;

Any ideas about what I need to do? I'm sure it is pretty simple.

Regards,
Steve KingZeus Downs
Co-Webmaster:
http://www.cncrenegade.com


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[PHP-DB] PHP MySQL and updating

2002-02-09 Thread Jennifer Downey

Hi again,

I am having trouble with updating. How do I tell php to update the database
at mid night instead of every time the browser is
refreshed? I have looked for it but can't find the info.

Also I thought session ID's were different between users. Is this true?

Thanks
Jennifer Downey



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