RE: [PHP-DB] Re: onnecting to MSSQL database from Linux?
I have got a copy of ctllib-linux-elf.tgz as it says on the php website, but I need another file called devlib.tgz. Anyone know where I can get a copy from??? Chris -Original Message- From: Avi Schwartz [mailto:[EMAIL PROTECTED]] Sent: 18 September 2002 02:44 To: [EMAIL PROTECTED] Subject: Re: [PHP-DB] Re: onnecting to MSSQL database from Linux? I did build it with --with-sybase, but then I forgot to install the new version. Face turning red... Sorry for the false alarm. It now works like a charm. Avi Adam Williams wrote: He's using microsoft sql server, not mysql. try --with-mssql On Wed, 18 Sep 2002, Jason Morehouse wrote: It means you haven't compiled mysql support into php. Recompile it using --with-mysql On Tue, 17 Sep 2002 15:30:29 +, Avi Schwartz wrote: I have PHP4 and freetds installed and I am trying to connect to a mssql server. The problem I am having is that the mssql_connect() call generates the following error: Fatal error: Call to undefined function: mssql_connect() -- Avi Schwartz Universe-watching, like golf and aging, [EMAIL PROTECTED] promotes humility - William R. Everdell -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP-DB] using more that 2 conditions to obtain info from db
hi everyone, I am new to all php and mySQL. What i am trying to do is to obtain information from the db using 3 conditions. this is what i've got $sql_num = mysql_query(SELECT * FROM siteinfo WHERE dive_operator = '1' AND status = '1',$db) or die (mysql_error()); the 3 conditions i need is dive_operator=1 destination=whatever status=1 how can i add destination=whatever to the mix? thanks in advance for your assistance.
Re: [PHP-DB] Writing to files (db related) ish
Hi, Hi All I know how to open, read write to files using Php. But how can you write some content to a particular place in a file, Not the start or end but say the middle some where. Example: Basic html file html head title/title /head body Write my stuff here!!! /body /html This eventually will relate to a db so I hope its not completely of topic. It doesn't seam to be database related... But any way Two solutions: 1st solution( recommended ): - read the entire file into a string( fread, ) - do a string relacement, ie: replace the string body/body with the string bodywhat you want/body. 2st solution: - use fseek function to place the file pointer where you want - write the string to the file Miguel -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP-DB] Caculating minutes since DATETIME column?
I need a way to calculate the number of minutes since the value of a DATETIME column in mysql. Any ideas? Thanks. -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] Caculating minutes since DATETIME column?
SELECT UNIX_TIMESTAMP(NOW()) - UNIX_TIMESTAMP(your_column) / 60 AS Minutes FROM your_table ---John Holmes... -Original Message- From: Leif K-Brooks [mailto:[EMAIL PROTECTED]] Sent: Thursday, September 26, 2002 12:29 PM To: [EMAIL PROTECTED] Subject: [PHP-DB] Caculating minutes since DATETIME column? I need a way to calculate the number of minutes since the value of a DATETIME column in mysql. Any ideas? Thanks. -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP-DB] Session understanding
Hi people,
if i use this code:
?php
session_start();
if(empty($_SESSION['username'])) {
die('An error has ocurred. It may be that you have not logged in, or
that your session has expired.
Please try a href=login.phplogging in/a again or contact
the
a href=mailto:[EMAIL PROTECTED];system administrator/a');
}
?
in one page to check if the user is logged, and in this same page i include another
page, do i have to put this same test in this page that is beiing included??? this
question may be dumb but i don´t knowthnaks a lot for the help.
Equipe Pratic Sistemas
Rodrigo Corrêa
Fone: (14) 441-1700
[EMAIL PROTECTED]
[EMAIL PROTECTED]
RE: [PHP-DB] Session understanding
If you include the other page AFTER you do this check you'll be fine. So run
your if statement and then add an else...include other.php;
HTH,
Steve.
-Original Message-
From: Rodrigo [mailto:[EMAIL PROTECTED]]
Sent: Thursday, September 26, 2002 9:38 AM
To: PHP
Subject: [PHP-DB] Session understanding
Hi people,
if i use this code:
?php
session_start();
if(empty($_SESSION['username'])) {
die('An error has ocurred. It may be that you have not
logged in, or that your session has expired.
Please try a href=login.phplogging in/a again
or contact the
a href=mailto:[EMAIL PROTECTED];system
administrator/a');
}
?
in one page to check if the user is logged, and in this same page i include
another page, do i have to put this same test in this page that is beiing
included??? this question may be dumb but i don´t knowthnaks a lot for
the help.
Equipe Pratic Sistemas
Rodrigo Corrêa
Fone: (14) 441-1700
[EMAIL PROTECTED]
[EMAIL PROTECTED]
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Re: [PHP-DB] Caculating minutes since DATETIME column?
Thanks a lot for your help, but just a not to anuyone else who tries this. Since there's no ()s around UNIX_TIMESTAMP(NOW()) - UNIX_TIMESTAMP(your_column) , it thinks that you're trying to get: UNIX_TIMESTAMP(NOW()) - (UNIX_TIMESTAMP(your_column) /60) Instead of: (UNIX_TIMESTAMP(NOW()) - UNIX_TIMESTAMP(your_column)) / 60 John Holmes wrote: SELECT UNIX_TIMESTAMP(NOW()) - UNIX_TIMESTAMP(your_column) / 60 AS Minutes FROM your_table ---John Holmes... -Original Message- From: Leif K-Brooks [mailto:[EMAIL PROTECTED]] Sent: Thursday, September 26, 2002 12:29 PM To: [EMAIL PROTECTED] Subject: [PHP-DB] Caculating minutes since DATETIME column? I need a way to calculate the number of minutes since the value of a DATETIME column in mysql. Any ideas? Thanks. -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP-DB] Re: Setting up a web server wit Redhat 7.3
I dont know if this is the right list. I have installed the php-mysql package and can now connect to the database. There is however error which I do not undertand. Warning: No MySQL-Link resource supplied in /usr/local/www/vantweststamps/databaselogin.php on line 15 Connected successfully ,Line 15 is mysql_close(); If I then go on top use a page which requires the database connection I get: Warning: Supplied argument is not a valid MySQL result resource in /usr/local/www/vantweststamps/stampconditionlist.php on line 39 Line 39 is: if ($row= mysql_fetch_array($result)) These pages all work without error on my win98 machine with apache, mysql and php. Is there any documentation which lists all of these error conditions and suggests ways of solving them? Regards Peter Goggin -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP-DB] Current row of query
Is there a mysql or array variable for the current row of a query array? I want to alternate background colours for each row of the query output so i need to know the current row number. Thanks -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] Session understanding
as long as that same session code is present at the top of all the included files that
are put in later. basicaly you need to put the session code in every page (even if
you only intend use it as an include) you wish to protect otherwise its contents can
be read by directly typing in the url in the same way that you can read included .js
and .css files.
-Original Message-
From: NIPP, SCOTT V (SBCSI) [mailto:[EMAIL PROTECTED]]
Sent: 26 September 2002 15:57
To: Griffiths, Daniel; Steve Bradwell; Rodrigo; PHP
Subject: RE: [PHP-DB] Session understanding
Can't you get around this by making the session code a separate,
required file that is at the beginning of every protected page? I think
this is basically the same thing, just making sure because I am about to try
and implement some session controls myself. Thanks.
-Original Message-
From: Griffiths, Daniel [mailto:[EMAIL PROTECTED]]
Sent: Thursday, September 26, 2002 9:55 AM
To: Steve Bradwell; Rodrigo; PHP
Subject: RE: [PHP-DB] Session understanding
make sure that the test code is in every page you wish to protect, even the
included ones, if its not there someone could still get the contents simply
be typing in the url of 'other.php' should they guess it etc, better to be
safe than sorry
-Original Message-
From: Steve Bradwell [mailto:[EMAIL PROTECTED]]
Sent: 26 September 2002 15:02
To: Rodrigo; PHP
Subject: RE: [PHP-DB] Session understanding
If you include the other page AFTER you do this check you'll be fine. So run
your if statement and then add an else...include other.php;
HTH,
Steve.
-Original Message-
From: Rodrigo [mailto:[EMAIL PROTECTED]]
Sent: Thursday, September 26, 2002 9:38 AM
To: PHP
Subject: [PHP-DB] Session understanding
Hi people,
if i use this code:
?php
session_start();
if(empty($_SESSION['username'])) {
die('An error has ocurred. It may be that you have not
logged in, or that your session has expired.
Please try a href=login.phplogging in/a again
or contact the
a href=mailto:[EMAIL PROTECTED];system
administrator/a');
}
?
in one page to check if the user is logged, and in this same page i include
another page, do i have to put this same test in this page that is beiing
included??? this question may be dumb but i don´t knowthnaks a lot for
the help.
Equipe Pratic Sistemas
Rodrigo Corrêa
Fone: (14) 441-1700
[EMAIL PROTECTED]
[EMAIL PROTECTED]
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Re: [PHP-DB] Current row of query
oops...
I meant:
(if $i is odd)
...
because $i would be the current index in the array.
Brad Bonkoski wrote:
why not this?
$result = mysql_query(Select * from table');
$num_rows = mysql_num_rows($rows);
for ($i=0; $i$num_rows, $i++)
{
$row = mysql_fetch_array($result);
if ($num_rows is odd)
{
print $row with BG color of red;
}
else
{
printf $row with BG color of purple;
}
}
HTH
-Brad
Patrick Lebon wrote:
Is there a mysql or array variable for the current row of a query array?
I want to alternate background colours for each row of the query output so i
need to know the current row number.
Thanks
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Re: [PHP-DB] Current row of query
why not
if (!($1%2))
{
echo even!;
}
else
{
echo odd!;
}
Adam
On Thu, 26 Sep 2002, Brad Bonkoski wrote:
oops...
I meant:
(if $i is odd)
...
because $i would be the current index in the array.
Brad Bonkoski wrote:
why not this?
$result = mysql_query(Select * from table');
$num_rows = mysql_num_rows($rows);
for ($i=0; $i$num_rows, $i++)
{
$row = mysql_fetch_array($result);
if ($num_rows is odd)
{
print $row with BG color of red;
}
else
{
printf $row with BG color of purple;
}
}
HTH
-Brad
Patrick Lebon wrote:
Is there a mysql or array variable for the current row of a query array?
I want to alternate background colours for each row of the query output so i
need to know the current row number.
Thanks
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RE: [PHP-DB] Current row of query
Not sure here, but you might also run into a problem if you start your if
statement with $i=0. If PHP does not treat the value 0 as even or odd, your
first row is most likely going to be purple along with your second row. I
know it's nitpicky, but I could see myself spending half an hour trying to
figure out why the code works, but not the way I want it to.
-Original Message-
From: Brad Bonkoski [mailto:[EMAIL PROTECTED]]
Sent: Thursday, September 26, 2002 11:10 AM
To: Patrick Lebon; [EMAIL PROTECTED]
Subject: Re: [PHP-DB] Current row of query
oops...
I meant:
(if $i is odd)
...
because $i would be the current index in the array.
Brad Bonkoski wrote:
why not this?
$result = mysql_query(Select * from table');
$num_rows = mysql_num_rows($rows);
for ($i=0; $i$num_rows, $i++)
{
$row = mysql_fetch_array($result);
if ($num_rows is odd)
{
print $row with BG color of red;
}
else
{
printf $row with BG color of purple;
}
}
HTH
-Brad
Patrick Lebon wrote:
Is there a mysql or array variable for the current row of
a query array?
I want to alternate background colours for each row of
the query output so i
need to know the current row number.
Thanks
--
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Re: [PHP-DB] Current row of query
Thanks, im currently doing something similar to this but I was wondering if
there was an already defined variable that i could use rather then have to
create a value and increment it myself. I guess am being picky, but was just
curious as im new to php.
This is how im currently doing it...
$rowNum = 0;
while ( $row = mysql_fetch_array($result) )
{
$rowNum++;
if ($rowNum % 2) { $bgCol = #EADBC6; } else { $bgCol = #EFE1CE; }
echo ..;
}
Brad Bonkoski [EMAIL PROTECTED] wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
why not this?
$result = mysql_query(Select * from table');
$num_rows = mysql_num_rows($rows);
for ($i=0; $i$num_rows, $i++)
{
$row = mysql_fetch_array($result);
if ($num_rows is odd)
{
print $row with BG color of red;
}
else
{
printf $row with BG color of purple;
}
}
HTH
-Brad
Patrick Lebon wrote:
Is there a mysql or array variable for the current row of a query array?
I want to alternate background colours for each row of the query output
so i
need to know the current row number.
Thanks
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Re: [PHP-DB] Current row of query
then add an extra conditional to check if $i is equal to 0, or start $ off as
1so,
for ($i=1, $i$num_rows+1; $i++)
-or-
if ($i==0)
//treat as even
either way woudl work.
-Brad
Hutchins, Richard wrote:
Not sure here, but you might also run into a problem if you start your if
statement with $i=0. If PHP does not treat the value 0 as even or odd, your
first row is most likely going to be purple along with your second row. I
know it's nitpicky, but I could see myself spending half an hour trying to
figure out why the code works, but not the way I want it to.
-Original Message-
From: Brad Bonkoski [mailto:[EMAIL PROTECTED]]
Sent: Thursday, September 26, 2002 11:10 AM
To: Patrick Lebon; [EMAIL PROTECTED]
Subject: Re: [PHP-DB] Current row of query
oops...
I meant:
(if $i is odd)
...
because $i would be the current index in the array.
Brad Bonkoski wrote:
why not this?
$result = mysql_query(Select * from table');
$num_rows = mysql_num_rows($rows);
for ($i=0; $i$num_rows, $i++)
{
$row = mysql_fetch_array($result);
if ($num_rows is odd)
{
print $row with BG color of red;
}
else
{
printf $row with BG color of purple;
}
}
HTH
-Brad
Patrick Lebon wrote:
Is there a mysql or array variable for the current row of
a query array?
I want to alternate background colours for each row of
the query output so i
need to know the current row number.
Thanks
--
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Re: [PHP-DB] Current row of query
Last I checked there was no way to retrieve the current index into the result
array, you can set the index manually with mysql_seek_data(), but I don't think
that is what you want, so the best solution IMHO, is to do what you are doing
and manually keep track of the index.
-Brad
Patrick Lebon wrote:
Thanks, im currently doing something similar to this but I was wondering if
there was an already defined variable that i could use rather then have to
create a value and increment it myself. I guess am being picky, but was just
curious as im new to php.
This is how im currently doing it...
$rowNum = 0;
while ( $row = mysql_fetch_array($result) )
{
$rowNum++;
if ($rowNum % 2) { $bgCol = #EADBC6; } else { $bgCol = #EFE1CE; }
echo ..;
}
Brad Bonkoski [EMAIL PROTECTED] wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
why not this?
$result = mysql_query(Select * from table');
$num_rows = mysql_num_rows($rows);
for ($i=0; $i$num_rows, $i++)
{
$row = mysql_fetch_array($result);
if ($num_rows is odd)
{
print $row with BG color of red;
}
else
{
printf $row with BG color of purple;
}
}
HTH
-Brad
Patrick Lebon wrote:
Is there a mysql or array variable for the current row of a query array?
I want to alternate background colours for each row of the query output
so i
need to know the current row number.
Thanks
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RE: [PHP-DB] Session understanding
-Original Message-
From: Griffiths, Daniel [mailto:[EMAIL PROTECTED]]
Sent: 26 September 2002 16:09
as long as that same session code is present at the top of
all the included files that are put in later. basicaly you
need to put the session code in every page (even if you only
intend use it as an include) you wish to protect otherwise
its contents can be read by directly typing in the url in the
same way that you can read included .js and .css files.
... and this is precisely why all your include files should be in directories which
are not servable by your Web server -- if your Web server can't serve them, then they
can't be accidentally served by someone typing their URL in directly, because they
don't have a URL!
Personally, I don't put *any* files with live code in http-servable directories. All
of my PHP scripts that Apache can serve as top-level scripts look pretty much like
this:
?php
ini_set('include_path', '../../dir-not-in-http-space/include');
require 'the_real_script.php';
?
Cheers!
Mike
-
Mike Ford, Electronic Information Services Adviser,
Learning Support Services, Learning Information Services,
JG125, James Graham Building, Leeds Metropolitan University,
Beckett Park, LEEDS, LS6 3QS, United Kingdom
Email: [EMAIL PROTECTED]
Tel: +44 113 283 2600 extn 4730 Fax: +44 113 283 3211
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RE: [PHP-DB] Current row of query
-Original Message-
From: Patrick Lebon [mailto:[EMAIL PROTECTED]]
Sent: 26 September 2002 16:20
This is how im currently doing it...
$rowNum = 0;
while ( $row = mysql_fetch_array($result) )
{
$rowNum++;
if ($rowNum % 2) { $bgCol = #EADBC6; } else { $bgCol = #EFE1CE; }
echo ..;
}
Looks like a good 'un to me, although I wonder why you're incrementing
$rowNum and then doing a separate access to it, when the ++ operator is
designed precisely to avoid the need for this; the following is identical in
functionality to the above:
$rowNum = 0;
while ( $row = mysql_fetch_array($result) )
{
if ($rowNum++ % 2) { $bgCol = #EADBC6; } else { $bgCol = #EFE1CE; }
echo ..;
}
And, having got this far, I'd probably then go on to rewrite the if line
using the ?: operator instead:
$bgCol = ($rowNum++ % 2) ? #EADBC6 : #EFE1CE;
Cheers!
Mike
-
Mike Ford, Electronic Information Services Adviser,
Learning Support Services, Learning Information Services,
JG125, James Graham Building, Leeds Metropolitan University,
Beckett Park, LEEDS, LS6 3QS, United Kingdom
Email: [EMAIL PROTECTED]
Tel: +44 113 283 2600 extn 4730 Fax: +44 113 283 3211
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RE: [PHP-DB] Current row of query
You can use instead of %, and it may be quicker.
$rowNum = 0;
while ( $row = mysql_fetch_array($result) )
{
$bgcolor = ($rowNum++ 1) ? #EADBC6 : #EFE1CE;
...
---John Holmes...
-Original Message-
From: Ford, Mike [LSS] [mailto:[EMAIL PROTECTED]]
Sent: Thursday, September 26, 2002 11:42 AM
To: 'Patrick Lebon'; [EMAIL PROTECTED]
Subject: RE: [PHP-DB] Current row of query
-Original Message-
From: Patrick Lebon [mailto:[EMAIL PROTECTED]]
Sent: 26 September 2002 16:20
This is how im currently doing it...
$rowNum = 0;
while ( $row = mysql_fetch_array($result) )
{
$rowNum++;
if ($rowNum % 2) { $bgCol = #EADBC6; } else { $bgCol = #EFE1CE;
}
echo ..;
}
Looks like a good 'un to me, although I wonder why you're incrementing
$rowNum and then doing a separate access to it, when the ++ operator
is
designed precisely to avoid the need for this; the following is
identical
in
functionality to the above:
$rowNum = 0;
while ( $row = mysql_fetch_array($result) )
{
if ($rowNum++ % 2) { $bgCol = #EADBC6; } else { $bgCol =
#EFE1CE;
}
echo ..;
}
And, having got this far, I'd probably then go on to rewrite the if
line
using the ?: operator instead:
$bgCol = ($rowNum++ % 2) ? #EADBC6 : #EFE1CE;
Cheers!
Mike
-
Mike Ford, Electronic Information Services Adviser,
Learning Support Services, Learning Information Services,
JG125, James Graham Building, Leeds Metropolitan University,
Beckett Park, LEEDS, LS6 3QS, United Kingdom
Email: [EMAIL PROTECTED]
Tel: +44 113 283 2600 extn 4730 Fax: +44 113 283 3211
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RE: [PHP-DB] Current row of query
Is there a mysql or array variable for the current row of a query array? I want to alternate background colours for each row of the query output so i need to know the current row number. There is a way with SQL variables, but you're better off just letting PHP keep track of it. ---John Holmes... -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP-DB] Valid IP
Hello guys
I know this should be asked in another list but don't want to subcribe just
for a simple question. I apologise in advance if that bothers anyone.
I'm trying to check valid IPs that come from a form filled by a user so I'm
using the following:
function valid_ip($ip)
{
//Check whether it is a valid IP
if (ereg(^[1-9]{2,3}+\.[1-9]{2,3}+\.[1-9]{2,3}+\.[1-9]{2,3}+$, $ip))
return true;
else
return false;
}
However it just accepts IPs such as xxx.xxx.xxx.xxx Errors arise whith IP
such as xxx.xx.xxx.xxx that is every part of the IP should be 3 numbers
lenght to be accepted making the function not very handy.
Any idea?
***
Wilmar Pérez
Network Administrator
Library System
Tel: ++57(4)2105145
University of Antioquia
Medellín - Colombia
2002
***
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[PHP-DB] Need help urgent!!
I'm using PHP4.2.2 Win with MySQL 3.2.52 Win and PHP doesn't pass vars from 1 php to the other how i fix it? Thanks -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] Need help urgent!!
Do you mean passing vars between forms, between functions, or between includes? Ryan -Original Message- From: Thomas omega Henning [mailto:[EMAIL PROTECTED]] Sent: Thursday, September 26, 2002 10:49 AM To: [EMAIL PROTECTED] Subject: [PHP-DB] Need help urgent!! I'm using PHP4.2.2 Win with MySQL 3.2.52 Win and PHP doesn't pass vars from 1 php to the other how i fix it? Thanks -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] Need help urgent!!
What's you register_globals set to? -Original Message- From: Thomas omega Henning [mailto:[EMAIL PROTECTED]] Sent: Thursday, September 26, 2002 12:49 PM To: [EMAIL PROTECTED] Subject: [PHP-DB] Need help urgent!! I'm using PHP4.2.2 Win with MySQL 3.2.52 Win and PHP doesn't pass vars from 1 php to the other how i fix it? Thanks -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] Need help urgent!!
On Thu, 26 Sep 2002 19:48:31 +0300 Thomas \omega\ Henning [EMAIL PROTECTED] wrote: I'm using PHP4.2.2 Win with MySQL 3.2.52 Win and PHP doesn't pass vars from 1 php to the other how i fix it? Read the documentation, register_globals is SET to off by default. http://www.php.net/manual/en/language.variables.external.php pa -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] Need help urgent!!
Check your register_globals value in your PHP.INI!! Dan On Thursday, September 26, 2002, at 11:48 AM, [EMAIL PROTECTED] wrote: I'm using PHP4.2.2 Win with MySQL 3.2.52 Win and PHP doesn't pass vars from 1 php to the other how i fix it? Thanks -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] Valid IP
Try this:
function padIP($ip){
$ar = explode(.,$ip);
$ip = ;
$xt = ;
for ($i = 0; $icount($ar); $i++){
$ip .= $xt.substr(($ar[$i]+1000),1);
$xt = .;
}
return $ip;
}
-Original Message-
From: Wilmar Perez [mailto:[EMAIL PROTECTED]]
Sent: Thursday, September 26, 2002 10:40 AM
To: [EMAIL PROTECTED]
Subject: [PHP-DB] Valid IP
Hello guys
I know this should be asked in another list but don't want to subcribe just
for a simple question. I apologise in advance if that bothers anyone.
I'm trying to check valid IPs that come from a form filled by a user so I'm
using the following:
function valid_ip($ip)
{
//Check whether it is a valid IP
if (ereg(^[1-9]{2,3}+\.[1-9]{2,3}+\.[1-9]{2,3}+\.[1-9]{2,3}+$, $ip))
return true;
else
return false;
}
However it just accepts IPs such as xxx.xxx.xxx.xxx Errors arise whith IP
such as xxx.xx.xxx.xxx that is every part of the IP should be 3 numbers
lenght to be accepted making the function not very handy.
Any idea?
***
Wilmar Pérez
Network Administrator
Library System
Tel: ++57(4)2105145
University of Antioquia
Medellín - Colombia
2002
***
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RE: [PHP-DB] Valid IP
Take out those + in your regular expression and it works fine for me,
for any format.
---John Holmes...
-Original Message-
From: Wilmar Perez [mailto:[EMAIL PROTECTED]]
Sent: Thursday, September 26, 2002 12:40 PM
To: [EMAIL PROTECTED]
Subject: [PHP-DB] Valid IP
Hello guys
I know this should be asked in another list but don't want to subcribe
just
for a simple question. I apologise in advance if that bothers anyone.
I'm trying to check valid IPs that come from a form filled by a user
so
I'm
using the following:
function valid_ip($ip)
{
//Check whether it is a valid IP
if (ereg(^[1-9]{2,3}+\.[1-9]{2,3}+\.[1-9]{2,3}+\.[1-9]{2,3}+$,
$ip))
return true;
else
return false;
}
However it just accepts IPs such as xxx.xxx.xxx.xxx Errors arise
whith IP
such as xxx.xx.xxx.xxx that is every part of the IP should be 3
numbers
lenght to be accepted making the function not very handy.
Any idea?
***
Wilmar Pérez
Network Administrator
Library System
Tel: ++57(4)2105145
University of Antioquia
Medellín - Colombia
2002
***
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RE: [PHP-DB] Valid IP
Shouldn't it be [0-9] for each of the elements, also?
What if I want to put 123.012.123.123 or something similar?
---John Holmes...
-Original Message-
From: Wilmar Perez [mailto:[EMAIL PROTECTED]]
Sent: Thursday, September 26, 2002 12:40 PM
To: [EMAIL PROTECTED]
Subject: [PHP-DB] Valid IP
Hello guys
I know this should be asked in another list but don't want to subcribe
just
for a simple question. I apologise in advance if that bothers anyone.
I'm trying to check valid IPs that come from a form filled by a user
so
I'm
using the following:
function valid_ip($ip)
{
//Check whether it is a valid IP
if (ereg(^[1-9]{2,3}+\.[1-9]{2,3}+\.[1-9]{2,3}+\.[1-9]{2,3}+$,
$ip))
return true;
else
return false;
}
However it just accepts IPs such as xxx.xxx.xxx.xxx Errors arise
whith IP
such as xxx.xx.xxx.xxx that is every part of the IP should be 3
numbers
lenght to be accepted making the function not very handy.
Any idea?
***
Wilmar Pérez
Network Administrator
Library System
Tel: ++57(4)2105145
University of Antioquia
Medellín - Colombia
2002
***
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Re: [PHP-DB] Valid IP
On Thu, 26 Sep 2002 11:39:40 -0500 Wilmar Perez [EMAIL PROTECTED] wrote: Hello guys I know this should be asked in another list but don't want to subcribe just for a simple question. I apologise in advance if that bothers anyone. I'm trying to check valid IPs that come from a form filled by a user so I'm using the following: If you do not need to check the range, why do not simply use ip2long ? http://www.php.net/manual/en/function.ip2long.php pa -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP-DB] MySQL Server Problem
Hi, I don't know if I'm right at this list. I have installed the mysql server on my debian Linux Server and it runs perfectly if I'm connecting it from my Puretec Webspace. But if I'm connecting from Apache with PHP4 running on localhost with the same script it won't run but no Error are logged in /var/log/mysql.log or /var/log/mysql/mysql.err. Can anybody help me to fix the problem. mfG Peter ([EMAIL PROTECTED]) http://www.reknet.de http://www.rektorschek.de http://www.petershomepage.de http://www.klo-papier.de ;-)
[PHP-DB] Re:[PHP-DB] php and javascript
heyyy i got the solution for this !!(after spending whole
day...)
in my code, javascript was not accepting the statement :
document.subj_frm.chk_id[i].checked=true
cos in php script i was using :
input type=checkbox name=chk_id[] value=.$row[subj_id]. /td
i changed the javascript code to :
var max = document.forms[0].elements.length ;
for(i=3; i=max; i=i+4)
{
document.forms[0].elements[i].checked=true
}
value of i initialised to 3 and incremented with 4 as per requirement of
my script. since 3rd, 7th, 11th elements are checkbox elements in my
form. its little bit hard coded. but could solve the conflict problem for
php array and javascript.
i got the clue from : http://www.php.net/manual/en/language.types.array.php
thanks to php.net
smita.
From: To: Smita Manohar , Subject: Re:[PHP-DB] php and javascript Date:
Thu, 26 Sep 2002 8:17:39 +0300
hy, if you have found the answer plz send me a copy... i'm having the same
type of problems... I want to modify or to create a new select option when
someone clicks a button. 1. I extract some values from a database 2. i want
when someone clicks a button, in the same page, to load other values from
the database and put them there
it's a sort of dynamic loading ... thanks for reading and i will help you
if could solve this problem.. the part with inserting values from database
to the form is done but the rest of the part is done in a javascript
function that does not works...
From: Smita Manohar Date: 2002/09/25 Wed PM 06:20:48 GMT+03:00
To: [EMAIL PROTECTED] Subject: [PHP-DB] php and javascript hii
all, in my php script, im havin one form, in which having checkboxes.
values for which are coming from database, and i want to do some action
for checked vales. so i create array of that checkbox. now i want to
include one link for Check All which helps user to check all boxes in
single click. since that form is too big, i dont want to reload the
entire page. hence trying to use javascript for this stuff. i've
included one more check box for Check All which is used as,
onclick=javascript : func_select_all() which when clicked invokes
function to select all checkboxes. the function func_select_all has
been defined in the as,the phpscript where i print checkboxes is,
while ($row = mysql_fetch_array($result)) { . . . echo
value=.$row[subj_id]. ; // values for which are coming from
database . . . } now in the above line (in phpscript) name of
the checkbox is chk_id[] i should define it as array, since i have to
pass array of all checked values. but when i select the check box named,
chk_select_all (see above code) it goes to the function defined in
javascript func_select_all but there it gives error for checkbox name,
since i've defined it as an array(in phpscript), instead if in my
phpscript i dont specify it as an array, ie, echo
value=.$row[subj_id]. ; javascript function works fine, and it
selects all checkbox values. but in that case, my php code doesn't work
fine, since checkbox value is not array, it cant remeber checked values.
can anyone pls suggest something? of can give other solution to check
all values without reloading the page thanks in advance smita.
_
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[PHP-DB] binary data?
Hi there everyone, How can I import binary data - say from a gif file, into a string or array in PHP? I can do text files/csv etc . but using the same method it won't do binary (I'm sure for some obvious reason). Thanks for your help Chris
RE: [PHP-DB] Valid IP
You're right, thanks. Shouldn't it be [0-9] for each of the elements, also? *** Wilmar Pérez Network Administrator Library System Tel: ++57(4)2105145 University of Antioquia Medellín - Colombia 2002 *** -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP-DB] Return Array from Function
Can somebody tell me what I might be doing wrong in the code below? I'm
trying to use a function to perform an often-used db query and return the
resulting resource to the calling script. I keep getting this error though:
Parse error: parse error, unexpected T_LNUMBER, expecting T_VARIABLE or '$'
in c:\spidey\public\addleveltwo.php on line 51
I've looked and looked, but I can't find what could be causing a parse
error. Most likely, I've just been looking at it for too long. Any fresh
eyes available?
?php
include(../protected/getContent.php);
getLevelOnes($docnum); //user-defined function from included file.
Definition appears after this snippet.
$num=mysql_num_rows($levelones);
if($num1)
{
echo(There is no level one (Section) content for this
document in the database.);
exit();
}
while($row=mysql_fetch_array($levelones))
{
$1contentID=$row[1contentID];
$parentID=$row[parentID];
$1child=$row[childID];
$1content=$row[1content];
$1ordinal=$row[ordinal];
echo(trtd.$1content./tdtda
href=\contentMgr.php?docnum=.$docnum.\
target=\_right\Add/a/td/tr);
}
?
?php
function getLevelOnes($docnum)
{
$sql=SELECT 1contentID, parentID, childID, 1content, 1ordinal FROM
levelone WHERE 1contentID='$docnum';
$levelones=mysql_query($sql)
or die(mysql_error());
return $levelones;
}
?
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RE: [PHP-DB] Return Array from Function
Sorry, line 51 is the one that reads:
$1contentID=$row[1contentID];
-Original Message-
From: Hutchins, Richard [mailto:[EMAIL PROTECTED]]
Sent: Thursday, September 26, 2002 4:19 PM
To: [EMAIL PROTECTED]
Subject: [PHP-DB] Return Array from Function
Can somebody tell me what I might be doing wrong in the code
below? I'm
trying to use a function to perform an often-used db query
and return the
resulting resource to the calling script. I keep getting this
error though:
Parse error: parse error, unexpected T_LNUMBER, expecting
T_VARIABLE or '$'
in c:\spidey\public\addleveltwo.php on line 51
I've looked and looked, but I can't find what could be causing a parse
error. Most likely, I've just been looking at it for too
long. Any fresh
eyes available?
?php
include(../protected/getContent.php);
getLevelOnes($docnum); //user-defined function from
included file.
Definition appears after this snippet.
$num=mysql_num_rows($levelones);
if($num1)
{
echo(There is no level one (Section) content for this
document in the database.);
exit();
}
while($row=mysql_fetch_array($levelones))
{
$1contentID=$row[1contentID];
$parentID=$row[parentID];
$1child=$row[childID];
$1content=$row[1content];
$1ordinal=$row[ordinal];
echo(trtd.$1content./tdtda
href=\contentMgr.php?docnum=.$docnum.\
target=\_right\Add/a/td/tr);
}
?
?php
function getLevelOnes($docnum)
{
$sql=SELECT 1contentID, parentID, childID, 1content,
1ordinal FROM
levelone WHERE 1contentID='$docnum';
$levelones=mysql_query($sql)
or die(mysql_error());
return $levelones;
}
?
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Re: [PHP-DB] Return Array from Function
You can't start variables with a number.
---John Holmes...
- Original Message -
From: Hutchins, Richard [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Thursday, September 26, 2002 4:18 PM
Subject: [PHP-DB] Return Array from Function
Can somebody tell me what I might be doing wrong in the code below? I'm
trying to use a function to perform an often-used db query and return the
resulting resource to the calling script. I keep getting this error
though:
Parse error: parse error, unexpected T_LNUMBER, expecting T_VARIABLE or
'$'
in c:\spidey\public\addleveltwo.php on line 51
I've looked and looked, but I can't find what could be causing a parse
error. Most likely, I've just been looking at it for too long. Any fresh
eyes available?
?php
include(../protected/getContent.php);
getLevelOnes($docnum); //user-defined function from included file.
Definition appears after this snippet.
$num=mysql_num_rows($levelones);
if($num1)
{
echo(There is no level one (Section) content for this
document in the database.);
exit();
}
while($row=mysql_fetch_array($levelones))
{
$1contentID=$row[1contentID];
$parentID=$row[parentID];
$1child=$row[childID];
$1content=$row[1content];
$1ordinal=$row[ordinal];
echo(trtd.$1content./tdtda
href=\contentMgr.php?docnum=.$docnum.\
target=\_right\Add/a/td/tr);
}
?
?php
function getLevelOnes($docnum)
{
$sql=SELECT 1contentID, parentID, childID, 1content, 1ordinal FROM
levelone WHERE 1contentID='$docnum';
$levelones=mysql_query($sql)
or die(mysql_error());
return $levelones;
}
?
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Re: [PHP-DB] Return Array from Function
Try single-quotes instead of double (' instead of ). Could be an
interpolation issue.
--Dave
On Thu, 26 Sep 2002, Hutchins, Richard wrote:
Can somebody tell me what I might be doing wrong in the code below? I'm
trying to use a function to perform an often-used db query and return the
resulting resource to the calling script. I keep getting this error though:
Parse error: parse error, unexpected T_LNUMBER, expecting T_VARIABLE or '$'
in c:\spidey\public\addleveltwo.php on line 51
I've looked and looked, but I can't find what could be causing a parse
error. Most likely, I've just been looking at it for too long. Any fresh
eyes available?
?php
include(../protected/getContent.php);
getLevelOnes($docnum); //user-defined function from included file.
Definition appears after this snippet.
$num=mysql_num_rows($levelones);
if($num1)
{
echo(There is no level one (Section) content for this
document in the database.);
exit();
}
while($row=mysql_fetch_array($levelones))
{
$1contentID=$row[1contentID];
$parentID=$row[parentID];
$1child=$row[childID];
$1content=$row[1content];
$1ordinal=$row[ordinal];
echo(trtd.$1content./tdtda
href=\contentMgr.php?docnum=.$docnum.\
target=\_right\Add/a/td/tr);
}
?
?php
function getLevelOnes($docnum)
{
$sql=SELECT 1contentID, parentID, childID, 1content, 1ordinal FROM
levelone WHERE 1contentID='$docnum';
$levelones=mysql_query($sql)
or die(mysql_error());
return $levelones;
}
?
--
,-._.-._.-._.-._.-.
`-. ,-'
.--. | |
| Cool nerds use ASCII | | |
| art at the bottom of | | |
| their emails. | | |
|| ,';..-.
|| ;';_' )]
||; `-|
|`.`T-|
`--._ \| |
`-; | |
|....-|
/\/ |..|
,'`./ ,( |
\_.-|_/,-/ ii | |
`.' `-/ .-|||
/`^-; ||||
/ / `.__/ | ||
/ | ||
| ||
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RE: [PHP-DB] Return Array from Function - SOLVED
John Holmes pointed out to me that I had made a stupid error by starting my
variable names with a number. Cardinal no-no. I know better. Really.
That solved the parse error. Another error popped up after that stating that
the variable $levelones was not a valid resource whenever I tried to
manipulate it. I assigned the results of the function call to another
variable ($stuff=getLevelOnes($docnum)) and the script works now. Must be
that $levelones is an out-of-scope variable on the calling page, thus the
need to assign the results of the function call to a local variable.
Maybe my pain can save you some. ;)
Thanks for the help.
-Original Message-
From: Dave Smith [mailto:[EMAIL PROTECTED]]
Sent: Thursday, September 26, 2002 4:31 PM
To: Hutchins, Richard
Cc: [EMAIL PROTECTED]
Subject: Re: [PHP-DB] Return Array from Function
Try single-quotes instead of double (' instead of ). Could be an
interpolation issue.
--Dave
On Thu, 26 Sep 2002, Hutchins, Richard wrote:
Can somebody tell me what I might be doing wrong in the
code below? I'm
trying to use a function to perform an often-used db query
and return the
resulting resource to the calling script. I keep getting
this error though:
Parse error: parse error, unexpected T_LNUMBER, expecting
T_VARIABLE or '$'
in c:\spidey\public\addleveltwo.php on line 51
I've looked and looked, but I can't find what could be
causing a parse
error. Most likely, I've just been looking at it for too
long. Any fresh
eyes available?
?php
include(../protected/getContent.php);
getLevelOnes($docnum); //user-defined function from
included file.
Definition appears after this snippet.
$num=mysql_num_rows($levelones);
if($num1)
{
echo(There is no level one (Section) content for this
document in the database.);
exit();
}
while($row=mysql_fetch_array($levelones))
{
$1contentID=$row[1contentID];
$parentID=$row[parentID];
$1child=$row[childID];
$1content=$row[1content];
$1ordinal=$row[ordinal];
echo(trtd.$1content./tdtda
href=\contentMgr.php?docnum=.$docnum.\
target=\_right\Add/a/td/tr);
}
?
?php
function getLevelOnes($docnum)
{
$sql=SELECT 1contentID, parentID, childID, 1content,
1ordinal FROM
levelone WHERE 1contentID='$docnum';
$levelones=mysql_query($sql)
or die(mysql_error());
return $levelones;
}
?
--
,-._.-._.-._.-._.-.
`-. ,-'
.--. | |
| Cool nerds use ASCII | | |
| art at the bottom of | | |
| their emails. | | |
|| ,';..-.
|| ;';_' )]
||; `-|
|`.`T-|
`--._ \| |
`-; | |
|....-|
/\/ |..|
,'`./ ,( |
\_.-|_/,-/ ii | |
`.' `-/ .-|||
/`^-; ||||
/ / `.__/ | ||
/ | ||
| ||
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[PHP-DB] Update involving a list field
Hi, Im using a form that updates a database entry. In it one of my fields is a drop down/list field. Whenever the value in this field is changed, instead of updating it to the new item, it is deleted entirely. I have the same field in my entry page that inserts just fine, but for some reason the update deletes the info. Is there something special about updating a recordset off of a dropdown field that I am missing? if it matters, im pulling the initial value of the field from the value in the database row.I can send the code for the page to anyone who needs more info. Shiloh
[PHP-DB] Categorized list?
I'm trying to create a system to store virtual objects. Each object will be in a category, and the categories may be in other categories. The categorie list might look something like: Food Candy Healthy Food Vegeterian food Organic food Gross food I'm thinking of a datbase structure for the categorys something like: id (int, auto_inc, primary) name (text) insideof(int, id of other catrgory which this one is inside of) The problem is, I need to generate an indented list such as I showed before. I know how to do this with a lot of colors (selecting what each category contains, etc.), but is there a more effieient way? I use mysql. Thanks for any ideas. -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] Categorized list?
Leif, You may want to look over the system I am creating. It is for neurobiology, but it uses categories. The URL is http://brancusi.usc.edu/bkms I am using both trees and colors. Regarding your specific problem, you have to have an indexing table, which will make the necessary relations between the different objects. Mihai On Thu, 26 Sep 2002, Leif K-Brooks wrote: I'm trying to create a system to store virtual objects. Each object will be in a category, and the categories may be in other categories. The categorie list might look something like: Food Candy Healthy Food Vegeterian food Organic food Gross food I'm thinking of a datbase structure for the categorys something like: id (int, auto_inc, primary) name (text) insideof(int, id of other catrgory which this one is inside of) The problem is, I need to generate an indented list such as I showed before. I know how to do this with a lot of colors (selecting what each category contains, etc.), but is there a more effieient way? I use mysql. Thanks for any ideas. -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] Current row of query
Thanks for your help. As i said im quite new to php so all your help in simplifying my code has been appeciated. -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP-DB] New Question...tables
Thanks to Micah Ive resolved my old problem, but now im working on something new and fairly gnarly...i ahve a data entry form and one of the textareas on the form needs to have the ability to take a table...from users who dont know html. does anyone know any possible solutions to this dilemma? It would be easy if the field would always have a table with specific properties, but that is not the case, there may or may not be a table and the number of rows and colums used and data input into the table if it does exist will vary from record to record. Is there any way to accomplish this tha tyou can think of? Im almost certain that there is nothing quick and easy but i was wondering if anyone out there had ideas. Just FYI i plan on having a seperat page to view data with that will pull the data out of a table, and, ideally format the html into a table for display.
[PHP-DB] Re: [PHP] New Question...tables
Hi, Friday, September 27, 2002, 10:20:32 AM, you wrote: SM Thanks to Micah Ive resolved my old problem, but now im working on something new and fairly gnarly...i ahve a data entry form and one of the textareas on the form needs to have the ability to SM take a table...from users who dont know html. does anyone know any possible solutions to this dilemma? It would be easy if the field would always have a table with specific properties, but that SM is not the case, there may or may not be a table and the number of rows and colums used and data input into the table if it does exist will vary from record to record. Is there any way to SM accomplish this tha tyou can think of? Im almost certain that there is nothing quick and easy but i was wondering if anyone out there had ideas. Just FYI i plan on having a seperat page to view SM data with that will pull the data out of a table, and, ideally format the html into a table for display. Have them enter the data as a comma delimited list like this: [table] Name,Address,City,Country Tom,Home,Brisbane,Australia ... [/table] Then you could parse looking for [table] and work on the data after till [/table] The first row would be the column headers. -- regards, Tom -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP-DB] query fails with mysql_query but success with direct SQL from command line
Hello everybody,
This command fails when ran with mysql_query but succeeds when ran command
line. Have verified connection good... a simple mysql_query(SELECT * FROM
{$user}_tickets); returns true. Any ideas?
$query=mysql_query(
SELECT *, UNIX_TIMESTAMP(date_submitted) AS n,
UNIX_TIMESTAMP(date_updated) AS out FROM {$user}_tickets
WHERE (
((UNIX_TIMESTAMP(date_submitted)-0)259200 AND
issue='LSR' AND date_updated IS NULL) OR
((UNIX_TIMESTAMP(date_submitted)-UNIX_TIMESTAMP(date_updated))259200 AND
issue='LSR' AND date_updated IS NOT NULL)
) OR (
((UNIX_TIMESTAMP(date_submitted)-0)86400 AND
issue='LSR' AND date_updated IS NULL) OR
((UNIX_TIMESTAMP(date_submitted)-UNIX_TIMESTAMP(date_updated))86400 AND
issue='LSR' and date_updated IS NOT NULL)
);
);
Cheers,
-Peter
##
Peter Thoenen - Systems Programmer
Commercial Communications
Camp Bondsteel, Kosovo
##
Stumbled Upon...heh (Score:5, Funny) /.
by $carab on 23:00 23 August 2002 (#4131637)
ForensicTec officials said they stumbled upon the military networks about
two months ago, while checking on network security for a private-sector
client.
Someone new to a Dvorak probably tried to type in lynx
http://www.google.com; but instead got nmap -v -p 1-1024 -sS -P0 army.mil
-T paranoid.
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[PHP-DB] [PHP-MySQL] Locking record
I'm a newbie of PHP and MySQL. Would anyone tell me that how to lock and unlock a record of MySQL from PHP? And how other can detect whether this record is locked or not? Thanks for your help. Regards, Michael Wai -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP-DB] [PHP-MySQL] lock a record of MySQL from PHP
I'm a newbie of PHP and MySQL. Would anyone tell me that how to lock and unlock a record of MySQL from PHP? And how other can detect whether this record is locked or not? Thanks for your help. Regards, Michael Wai -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] query fails with mysql_query but success with direct SQL from command line
How do you know if fails? What does mysql_error() say?
---John Holmes...
-Original Message-
From: Thoenen, Peter Mr. EPS
[mailto:[EMAIL PROTECTED]]
Sent: Thursday, September 26, 2002 10:13 PM
To: [EMAIL PROTECTED]
Subject: [PHP-DB] query fails with mysql_query but success with direct
SQL
from command line
Hello everybody,
This command fails when ran with mysql_query but succeeds when ran
command
line. Have verified connection good... a simple mysql_query(SELECT *
FROM
{$user}_tickets); returns true. Any ideas?
$query=mysql_query(
SELECT *, UNIX_TIMESTAMP(date_submitted) AS n,
UNIX_TIMESTAMP(date_updated) AS out FROM {$user}_tickets
WHERE (
((UNIX_TIMESTAMP(date_submitted)-0)259200 AND
issue='LSR' AND date_updated IS NULL) OR
((UNIX_TIMESTAMP(date_submitted)-UNIX_TIMESTAMP(date_updated))259200
AND
issue='LSR' AND date_updated IS NOT NULL)
) OR (
((UNIX_TIMESTAMP(date_submitted)-0)86400 AND
issue='LSR' AND date_updated IS NULL) OR
((UNIX_TIMESTAMP(date_submitted)-UNIX_TIMESTAMP(date_updated))86400
AND
issue='LSR' and date_updated IS NOT NULL)
);
);
Cheers,
-Peter
##
Peter Thoenen - Systems Programmer
Commercial Communications
Camp Bondsteel, Kosovo
##
Stumbled Upon...heh (Score:5, Funny) /.
by $carab on 23:00 23 August 2002 (#4131637)
ForensicTec officials said they stumbled upon the military networks
about
two months ago, while checking on network security for a
private-sector
client.
Someone new to a Dvorak probably tried to type in lynx
http://www.google.com; but instead got nmap -v -p 1-1024 -sS -P0
army.mil
-T paranoid.
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To unsubscribe, visit: http://www.php.net/unsub.php
--
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[PHP-DB] o mica problema cu PHP
Salut, te-am vazut in lista PHP si m-am gandit ca poate m-ai putea ajuta intr-o problema. interoghez o baza de date si extrag anumite campuri pe care le asez intr-o pagina. Vreau ca in functie de valorile existente si selectate de catre user sa reinteroghez baza de date si in cadrul aceleasi pagini sa apara noi campuri cu informatiile cerute. Mai tehnic vorbind nu stiu cum sa fac ca o functie scrisa special pentru reinterogarea bazei sa se activeze la un moment dat si sa refac pagina, un fel de creare dinamica...partea cu reintroducerea datelor am rezolvat-o dar functia nu se executa la acel eveniment... multumesc Free Email Account at www.flash.ro -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
