[PHP-DB] Re: An old question...

2004-09-06 Thread Javier Mestre
Look at http://www.php.net/docs.php , there is a version in spanish.
(mira en http://www.php.net/docs.php , hay una copia en español)

Javier Mestre

Lic. Daniel Alfredo Betancourt Reboso [EMAIL PROTECTED] wrote in
message news:[EMAIL PROTECTED]
Hi everyone!!

Certainly it is an old question. How can I start learning PHP?. I need to
use it
with MySQL. Any suggestions?

I´m a none English speaker.

Thank´s
Daniel..




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[PHP-DB] Re: Name searches for the spelling impaired

2004-09-06 Thread Zareef Ahmed
HI ,

Following php  functions may be usefull

http://www.php.net/soundex
http://www.php.net/similar_text


Just try to make good algoritham ;)

Zareef Ahmed




Pete Holsberg [EMAIL PROTECTED] wrote in message
news:[EMAIL PROTECTED]
 Is there a way to program MySQL so that it can find the
 name Smyth if the user looks for Smith? And similar
 mispellings that are similar in sound.

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[PHP-DB] how to show this querry

2004-09-06 Thread peppe
 Hi ,
I have a problem with showing a query I have a table project with start date
end date and project title
I want to show only the projects that they are given in table for that
month, for example project that starts 06-09-04 and ends 09-09-04 or ends
12-02-05
but nt the projects that starts 06-10-04

Any help will be appreciated

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RE: [PHP-DB] how to show this querry

2004-09-06 Thread balwantsingh
try this
SELECT start_date, end_date, project_title from tablename where
month(start_date)=09 and year(start_date)=04

this will show only the data pertaining to 09 month and 04 year.

hope this will resolve your problem.

with best wishes
balwant

-Original Message-
From: peppe [mailto:[EMAIL PROTECTED]
Sent: Monday, September 06, 2004 2:45 PM
To: [EMAIL PROTECTED]
Subject: [PHP-DB] how to show this querry


 Hi ,
I have a problem with showing a query I have a table project with start date
end date and project title
I want to show only the projects that they are given in table for that
month, for example project that starts 06-09-04 and ends 09-09-04 or ends
12-02-05
but nt the projects that starts 06-10-04

Any help will be appreciated

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Re: [PHP-DB] how to show this querry

2004-09-06 Thread peppe
Hi Balwant your answer helpd me only I have a problem showing the projects
starting 06-05-2004 and ending 09-09-2005 I need to show also those projects
beacuse of end date is 2005

Balwantsingh [EMAIL PROTECTED] wrote in message
news:[EMAIL PROTECTED]
 try this
 SELECT start_date, end_date, project_title from tablename where
 month(start_date)=09 and year(start_date)=04

 this will show only the data pertaining to 09 month and 04 year.

 hope this will resolve your problem.

 with best wishes
 balwant

 -Original Message-
 From: peppe [mailto:[EMAIL PROTECTED]
 Sent: Monday, September 06, 2004 2:45 PM
 To: [EMAIL PROTECTED]
 Subject: [PHP-DB] how to show this querry


  Hi ,
 I have a problem with showing a query I have a table project with start
date
 end date and project title
 I want to show only the projects that they are given in table for that
 month, for example project that starts 06-09-04 and ends 09-09-04 or ends
 12-02-05
 but nt the projects that starts 06-10-04

 Any help will be appreciated

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[PHP-DB] functions via event handlers

2004-09-06 Thread Yemi Obembe
i'd just luv to ask if it is possibble to call a function in PHP by using event 
handlers (like onmouseover, onload) as done in javascript? if its possible, i'd 
appreciate someone to tutor me on it.



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www.opeyemi.tk





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Re: [PHP-DB] Re: Name searches for the spelling impaired

2004-09-06 Thread Pete Holsberg
On Mon, 6 Sep 2004, David Robley wrote:

 On Mon, 6 Sep 2004 11:09, Pete Holsberg wrote:
 
  Is there a way to program MySQL so that it can find the
  name Smyth if the user looks for Smith? And similar
  mispellings that are similar in sound.
 
 The SOUNDEX string function in mysql may be what you want.
 
 http://dev.mysql.com/doc/mysql/en/String_functions.html
 
 Something like
 
 SELECT fields FROM table WHERE SOUNDEX(name) = SOUNDEX('searchvalue')
 
 Cheers
 -- 
 David Robley

Thanks!

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Re: [PHP-DB] Re: Name searches for the spelling impaired

2004-09-06 Thread Pete Holsberg
On Mon, 6 Sep 2004, Zareef Ahmed wrote:

 HI ,
 
 Following php  functions may be usefull
 
 http://www.php.net/soundex
 http://www.php.net/similar_text
 
 
 Just try to make good algoritham ;)
 
 Zareef Ahmed

Thanks!

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Re: [PHP-DB] Re: Newbie Questions

2004-09-06 Thread anirudh dutt
  Well, I have this:
  
  $result=mysql_query('SELECT * FROM $table ORDER BY lastname, street, housenum 
  ASC');
 

if u're trying to use variables like $table in the query (which i
think u are), they need to be in double quotes :  not single
quotes. so the line should be:
$result=mysql_query(SELECT * FROM $table ORDER BY lastname, street,
housenum ASC);

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[PHP-DB] Reload page on after sending data to mysql database

2004-09-06 Thread Javier Carlos Viegas
Hi, i´ve got a flash form that send inserted data to a
page called insert.php and after sending data to the
mysql database the page reloads the flash form for a
new entry, but it reloads it on a new page i want to
reloadit on the same page that i ´ve enter the
previous entry. I´m posting the relevant parts of the
php code:

?php

//defino variables
$apellidoclientesnuevos = $_POST['apellido'];
$nombreclientesnuevos = $_POST['nombre'];
$telefonoclientesnuevos = $_POST['telefono'];
$dniclientesnuevos = $_POST['dni'];
$fechacitaclientesnuevos = $_POST['fecha'];
$horacitaclientesnuevos = $_POST['hora'];
$abogadoclientesnuevos = $_POST['abogado'];
$asuntoclientesnuevos = $_POST['asunto'];
$dondeclientesnuevos = $_POST['donde'];
$URL=http://www.myform.php;;

//establece conección con el servidor y abre la base
de datos

$db = mysql_connect(90.0.0.2, javier, 315/95);

mysql_select_db(clientes,$db);

//manda query a la base de datos

$sql = INSERT INTO clientesnuevos (1,2,3,4,5,6)
VALUES ('$1','$2','$3','$4','$5','$6');
$result = mysql_query($sql) or die(Error in query:  
. mysql_error()); 

header (Location: $URL);
exit;
?

Any idea how can i do this??

Thanks
Javier





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[PHP-DB] Another newbie question

2004-09-06 Thread Pete Holsberg
The following code results in the error message Couldn't execute query.

---
?php
  /* Program: ShowDir.php
   * Desc:Displays results of the search.
   */
?
html
headtitleSearch Results/title/head
body topmargin=0 marginheight=0
?php
  include(login.inc);

  $connection = mysql_connect($host,$user,$password)
   or die (Couldn't connect to server);

  $db = mysql_select_db($database,$connection)
   or die (Couldn't select database);

$sql = SELECT * FROM $table ;
$sql .= WHERE `LastName` LIKE $search_string ;
$sql .= OR `FirstName` LIKE $search_string ;
$sql .= OR `Spouse` LIKE $search_string ;
$sql .= OR `Street` LIKE $search_string ;
$sql .= OR `Email` LIKE $search_string LIMIT 0, 30 ;
$sql .= ORDER BY Street, HouseNum, LastName;

  $result = mysql_query($sql)
   or die (Couldn't execute query.);
 ...

-

Why is that?

Also, how do I make LIKE insensitive to case?

And finally, how do I use the % wildcard with a variable?

Thanks.

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Re: [PHP-DB] Another newbie question

2004-09-06 Thread Pete Holsberg
On Mon, 6 Sep 2004 [EMAIL PROTECTED] wrote:

 you should copy/paste that into a command-line msyql
 session and see if that works.


I cut the query back to

SELECT * FROM Directory WHERE `LastName` LIKE Joe  ORDER BY Street, HouseNum, LastName

and ran it manually. I got

---
SQL-query :  

SELECT * 
FROM Directory
WHERE LastName 
LIKE Joe
ORDER BY Street, HouseNum, LastName
LIMIT 0 , 30 

MySQL said: 

Unknown column 'Joe' in 'where clause'


Perhaps I don't understand LIKE. LastName is a column; Joe
is a value. ???

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Re: [PHP-DB] Another newbie question

2004-09-06 Thread Stuart Felenstein
I think you need to put '' around joe 'joe'

Stuart
--- Pete Holsberg [EMAIL PROTECTED] wrote:

 On Mon, 6 Sep 2004
 [EMAIL PROTECTED] wrote:
 
  you should copy/paste that into a command-line
 msyql
  session and see if that works.
 
 
 I cut the query back to
 
 SELECT * FROM Directory WHERE `LastName` LIKE Joe 
 ORDER BY Street, HouseNum, LastName
 
 and ran it manually. I got
 
 ---
 SQL-query :  
 
 SELECT * 
 FROM Directory
 WHERE LastName 
 LIKE Joe
 ORDER BY Street, HouseNum, LastName
 LIMIT 0 , 30 
 
 MySQL said: 
 
 Unknown column 'Joe' in 'where clause'
 
 
 Perhaps I don't understand LIKE. LastName is a
 column; Joe
 is a value. ???
 
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 To unsubscribe, visit: http://www.php.net/unsub.php
 
 

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Re: [PHP-DB] Another newbie question

2004-09-06 Thread Pete Holsberg
 --- Pete Holsberg [EMAIL PROTECTED] wrote:
 
  On Mon, 6 Sep 2004
  [EMAIL PROTECTED] wrote:
  
   you should copy/paste that into a command-line
  msyql
   session and see if that works.
  
  
  I cut the query back to
  
  SELECT * FROM Directory WHERE `LastName` LIKE Joe 
  ORDER BY Street, HouseNum, LastName
  
  and ran it manually. I got
  
  ---
  SQL-query :  
  
  SELECT * 
  FROM Directory
  WHERE LastName 
  LIKE Joe
  ORDER BY Street, HouseNum, LastName
  LIMIT 0 , 30 
  
  MySQL said: 
  
  Unknown column 'Joe' in 'where clause'
  
  
  Perhaps I don't understand LIKE. LastName is a
  column; Joe
  is a value. ???

On Mon, 6 Sep 2004, Stuart Felenstein wrote:

 I think you need to put '' around joe 'joe'
 
 Stuart

Tried that. It said that 'Joe' was an unknown column!

Besides, Joe is the value of a variable passed by another
script.

Thanks.





  
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[PHP-DB] php Form Validation help

2004-09-06 Thread Vincent Jordan
have a form that I would like to validate before it is submitted to the DB.

I am having trouble with a couple of sections. 

 

I have a select box with a listing of all the states, the first option is
Choose One with a value of 0. Would this be the correct way to
validate this field?

 

CODE

$state = $_POST['state'];

if ($state = 0) {

print 'pPlease select your State/p';

}

/CODE

 

Second, another part of the same form I have fields for phone numbers, once
the field is submitted I would like to join the 3 sections of areacode, nxx
and prefix. I have done this to join them, is this correct?

CODE

$phone = $_POST['p-areacode'] . - . $_POST['p-prefix']. - .
$_POST['p-suffix'];

/CODE

 

The next question id for both phone number and area code. 

 

If I want to validate the zip code and ensure a minimum of X characters in
the field, numbers only how would I do this?

 

Would this be somewhat on the right track?

CODE

If ($zip str 5) {

print 'pPlease enter your Zip Code (EX. 77662)/p';

}

/CODE

And for the phone number I would assume I could use:

CODE

If ($_POST['p-areacode'] str 3 ) {

print 'pPlease enter your Area Code (EX. 77662)/p';

}

/CODE

 

I am still new with PHP, any help would be appreciated. Below is the code I
have sofar:

 



Re: [PHP-DB] php Form Validation help

2004-09-06 Thread Peter Ellis
See below for point-by-point.

...
 
 
 CODE
 
 $state = $_POST['state'];
 
 if ($state = 0) {

= is an assignment operator.  This will always test true, because $state
is set to 0 every time this is called.  You want ==, which is a
comparison operator.

 print 'pPlease select your State/p';
 
 }
 
 /CODE
 



 CODE
 
 $phone = $_POST['p-areacode'] . - . $_POST['p-prefix']. - .
 $_POST['p-suffix'];
 
 /CODE

More like:

$phone = $_[PST[area] . - ..

You get the idea -- dashes need to be surrounded by quotes.

 
 The next question id for both phone number and area code. 
 
  
 
 If I want to validate the zip code and ensure a minimum of X characters in
 the field, numbers only how would I do this?

You can check the string length and see if it's within the bounds you
want.  Look at the Strings section of the PHP manual for the proper
function (str_len, I think).

 
 Would this be somewhat on the right track?
 
 CODE
 
 If ($zip str 5) {
 
 print 'pPlease enter your Zip Code (EX. 77662)/p';
 
 }
 
 /CODE

Nope.  If someone entered 98115, then this would be  5, since there's a
difference of 98110 integers :)

 
 And for the phone number I would assume I could use:
 
 CODE
 
 If ($_POST['p-areacode'] str 3 ) {
 
 print 'pPlease enter your Area Code (EX. 77662)/p';
 
 }
 
 /CODE
 

See comment on string length above.

  
 
 I am still new with PHP, any help would be appreciated. Below is the code I
 have sofar:
 
  


Hope this helps.
-- 
Peter Ellis - [EMAIL PROTECTED]
Web Design and Development Consultant
naturalaxis | http://www.naturalaxis.com/

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Re: [PHP-DB] functions via event handlers

2004-09-06 Thread Philip Thompson
Yemi,
On Sep 6, 2004, at 7:14 AM, Yemi Obembe wrote:
i'd just luv to ask if it is possibble to call a function in PHP by 
using event handlers (like onmouseover, onload) as done in javascript? 
if its possible, i'd appreciate someone to tutor me on it.

As far as I know, this is not possible. Since PHP is server-side 
scripting (not client-side like JavaScript), all the code-processing is 
done before it ever reaches the client's computer. Because of this, you 
will never be able to use the code via event handlers.

If anyone knows something different, please let me and Yemi know.
~Philip
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Re: [PHP-DB] functions via event handlers

2004-09-06 Thread Joseph Crawford
the closest you could come is to make javascript functions call php
pages basically redirects that would call the php functions.

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Codebowl Solutions
[EMAIL PROTECTED]
802-558-5247

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Re: [PHP-DB] functions via event handlers

2004-09-06 Thread zareef ahmed
Hi, 

A small example

script language=javascript
function call_me()
{
window.location=script.php;
}
/script

div onmouseover=call_me() click me/div



If you are thinking about some live experience like
javascirpt with PHP you can go for flash and php.

In Flash Event calls php scripts and get the value
without reloading the flash movie.


Zareef Ahmed


--- Yemi Obembe [EMAIL PROTECTED] wrote:

 i'd just luv to ask if it is possibble to call a
 function in PHP by using event handlers (like
 onmouseover, onload) as done in javascript? if its
 possible, i'd appreciate someone to tutor me on it.
 
 
 
 -
 
 A passion till tomorrow,
 www.opeyemi.tk
 
 
 
 
   
 -
 Do you Yahoo!?
 Win 1 of 4,000 free domain names from Yahoo! Enter
now.


=
Zareef Ahmed :: A PHP Developer in Delhi(India).
Homepage :: http://www.zasaifi.com



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[PHP-DB] mySQL searching through serialized arrays

2004-09-06 Thread rolando g
I am storing array of user IDs as TEXT using the serialize() function
on the array, since several users, one or none can be part of each
record...

and I noticed that the serialized array has the values in double
quotes  like :21;  for example... so since I know that the values
will be enclosed,  i am using the sql statement, with 21 as the
example variable:

SELECT FROM table WHERE userarray LIKE '%\21\%'

is there a better way or a built-in mySQL function to filter through
the serialized array

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