[PHP-DB] How can I get in PHP the number of files in a directory
Hi, This is for reading a file: ?php $handle = fopen(/home/rasmus/file.gif, r); ? How can I get in PHP the number of files in the directory (rasmus) and the files names in a loop? Thanks Suad -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] How can I get in PHP the number of files in a directory
suad wrote: This is for reading a file: ?php $handle = fopen(/home/rasmus/file.gif, r); ? How can I get in PHP the number of files in the directory (rasmus) and the files names in a loop? http://php.net/glob or http://php.net/readdir -Stut -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] How can I get in PHP the number of files in a directory
http://www.php.net/manual/en/ref.dir.php suad wrote: Hi, This is for reading a file: ?php $handle = fopen(/home/rasmus/file.gif, r); ? How can I get in PHP the number of files in the directory (rasmus) and the files names in a loop? Thanks Suad -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] allow-url-fopen setting
Manoj Singh wrote: Hello all, Can i change the allow-url-fopen(php.ini variable) setting through php code. If any one knows how to do that, please help me. Regards Manoj http://www.php.net/manual/en/ref.filesystem.php from manual Note: This setting can only be set in php.ini due to security reasons. -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP-DB] Combining Fields
Good Day!
I am trying to use my limited knowledge to create a VERY simple process to
display some of the information in my table, allow a particular record to be
selected, then opened on a page with text boxes to edit the information,
after which the UPDATE command will be used to update the database.
That being said, I have a way that I think this will work, but I don't
have a unique record number in my table for each of the entries. I have
tried getting PHPMyAdmin to set this up, but I cannot seem to make it work.
SO - I need to try to create that ID on the fly. I figured I could just
combine the first and last names to make this ID, but I am not sure what the
syntax should be. Here is the code I have dealing with defining the
variables...
Any help or thoughts would be splendid!
while ($row = mysql_fetch_array($result)) {
$id = $row['last_name'],$row['first_name'];
$fname = $row['first_name'];
$lname = $row['last_name'];
$option_block .= option value=\$id\$lname, $fname/option;
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Re: [PHP-DB] Combining Fields
Grae Wolfe - PHP wrote:
Good Day!
I am trying to use my limited knowledge to create a VERY simple process to
display some of the information in my table, allow a particular record to be
selected, then opened on a page with text boxes to edit the information,
after which the UPDATE command will be used to update the database.
That being said, I have a way that I think this will work, but I don't
have a unique record number in my table for each of the entries. I have
tried getting PHPMyAdmin to set this up, but I cannot seem to make it work.
SO - I need to try to create that ID on the fly. I figured I could just
combine the first and last names to make this ID, but I am not sure what the
syntax should be. Here is the code I have dealing with defining the
variables...
Any help or thoughts would be splendid!
while ($row = mysql_fetch_array($result)) {
$id = $row['last_name'],$row['first_name'];
$fname = $row['first_name'];
$lname = $row['last_name'];
$option_block .= option value=\$id\$lname, $fname/option;
Use the dot (.) for appending variables...
so it would be:
$id = $row['last_name'].$row['first_name'];
...or course if you want that would look like this: 'SmithAdam'
if you want 'Smith,Adam' as your id then:
$id = $row['last_name'].,.$row['first_name'];
-Brad
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Re: [PHP-DB] Combining Fields
Thank you Brad - That is what I was looking for, but now that I see how it
behaves, I am thinking that it isn't going to work the way I wanted. I need
to then be able to pass the ID back to MySQL so that it will retrieve just
the one record for editing.
I guess I need to go back to making the DB create an auto-incrementing ID
number. Hmmm...
Thanks!!
Brad Bonkoski [EMAIL PROTECTED] wrote in message
news:[EMAIL PROTECTED]
Grae Wolfe - PHP wrote:
Good Day!
I am trying to use my limited knowledge to create a VERY simple process
to display some of the information in my table, allow a particular record
to be selected, then opened on a page with text boxes to edit the
information, after which the UPDATE command will be used to update the
database.
That being said, I have a way that I think this will work, but I don't
have a unique record number in my table for each of the entries. I have
tried getting PHPMyAdmin to set this up, but I cannot seem to make it
work. SO - I need to try to create that ID on the fly. I figured I could
just combine the first and last names to make this ID, but I am not sure
what the syntax should be. Here is the code I have dealing with defining
the variables...
Any help or thoughts would be splendid!
while ($row = mysql_fetch_array($result)) {
$id = $row['last_name'],$row['first_name'];
$fname = $row['first_name'];
$lname = $row['last_name'];
$option_block .= option value=\$id\$lname, $fname/option;
Use the dot (.) for appending variables...
so it would be:
$id = $row['last_name'].$row['first_name'];
...or course if you want that would look like this: 'SmithAdam'
if you want 'Smith,Adam' as your id then:
$id = $row['last_name'].,.$row['first_name'];
-Brad
--
PHP Database Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] Combining Fields
Grae Wolfe - PHP wrote:
Thank you Brad - That is what I was looking for, but now that I see how it
behaves, I am thinking that it isn't going to work the way I wanted. I need
to then be able to pass the ID back to MySQL so that it will retrieve just
the one record for editing.
I guess I need to go back to making the DB create an auto-incrementing ID
number. Hmmm...
Thanks!!
Well, the unique ID would probably be the *best* way to go, but you
could also get the record with the below solution, of course this
requires every combination of first and last name is unique...
if you do:
$id = Smith,Adam
Then:
list($fname, $lname) = explode(,,$id);
select * from table where first_name = '$fname' and last_name='$lname'
would do the trick...
Of course this has many what-ifs asociated with it...all of which
would be taken care of with an auto-incrementing/primary key ID field
for wach record ;-)
-Brad
Brad Bonkoski [EMAIL PROTECTED] wrote in message
news:[EMAIL PROTECTED]
Grae Wolfe - PHP wrote:
Good Day!
I am trying to use my limited knowledge to create a VERY simple process
to display some of the information in my table, allow a particular record
to be selected, then opened on a page with text boxes to edit the
information, after which the UPDATE command will be used to update the
database.
That being said, I have a way that I think this will work, but I don't
have a unique record number in my table for each of the entries. I have
tried getting PHPMyAdmin to set this up, but I cannot seem to make it
work. SO - I need to try to create that ID on the fly. I figured I could
just combine the first and last names to make this ID, but I am not sure
what the syntax should be. Here is the code I have dealing with defining
the variables...
Any help or thoughts would be splendid!
while ($row = mysql_fetch_array($result)) {
$id = $row['last_name'],$row['first_name'];
$fname = $row['first_name'];
$lname = $row['last_name'];
$option_block .= option value=\$id\$lname, $fname/option;
Use the dot (.) for appending variables...
so it would be:
$id = $row['last_name'].$row['first_name'];
...or course if you want that would look like this: 'SmithAdam'
if you want 'Smith,Adam' as your id then:
$id = $row['last_name'].,.$row['first_name'];
-Brad
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PHP Database Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] Combining Fields
Again, my many thanks - I didn't know about the 'explode' function - that
may be a huge help.
Hopefully, I am on the right track now... thanks!
Brad Bonkoski [EMAIL PROTECTED] wrote in message
news:[EMAIL PROTECTED]
Grae Wolfe - PHP wrote:
Thank you Brad - That is what I was looking for, but now that I see how it
behaves, I am thinking that it isn't going to work the way I wanted. I
need to then be able to pass the ID back to MySQL so that it will
retrieve just the one record for editing.
I guess I need to go back to making the DB create an auto-incrementing ID
number. Hmmm...
Thanks!!
Well, the unique ID would probably be the *best* way to go, but you could
also get the record with the below solution, of course this requires every
combination of first and last name is unique...
if you do:
$id = Smith,Adam
Then:
list($fname, $lname) = explode(,,$id);
select * from table where first_name = '$fname' and last_name='$lname'
would do the trick...
Of course this has many what-ifs asociated with it...all of which would
be taken care of with an auto-incrementing/primary key ID field for wach
record ;-)
-Brad
Brad Bonkoski [EMAIL PROTECTED] wrote in message
news:[EMAIL PROTECTED]
Grae Wolfe - PHP wrote:
Good Day!
I am trying to use my limited knowledge to create a VERY simple process
to display some of the information in my table, allow a particular
record to be selected, then opened on a page with text boxes to edit
the information, after which the UPDATE command will be used to update
the database.
That being said, I have a way that I think this will work, but I don't
have a unique record number in my table for each of the entries. I
have tried getting PHPMyAdmin to set this up, but I cannot seem to make
it work. SO - I need to try to create that ID on the fly. I figured I
could just combine the first and last names to make this ID, but I am
not sure what the syntax should be. Here is the code I have dealing
with defining the variables...
Any help or thoughts would be splendid!
while ($row = mysql_fetch_array($result)) {
$id = $row['last_name'],$row['first_name'];
$fname = $row['first_name'];
$lname = $row['last_name'];
$option_block .= option value=\$id\$lname, $fname/option;
Use the dot (.) for appending variables...
so it would be:
$id = $row['last_name'].$row['first_name'];
...or course if you want that would look like this: 'SmithAdam'
if you want 'Smith,Adam' as your id then:
$id = $row['last_name'].,.$row['first_name'];
-Brad
--
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[PHP-DB] Re: Open a file?
Well You may try this: First you can make a form and add the option to write to the file hidden in the form... just like that: form method=post action=Action_File.php input type=hidden name=theText Value=The Page has been visited at ?php $today = getdate(); print_r($today); ? br input type=submit value=Post Data /form - Then the Action File should be contain some thing like that: ?php // Here we get the information in about when the page visited. $theText = $_POST[theText]; $theText = stripslashes($theText); // Here we open the file... Of course you will change the $filename with the name of your file that you want the text to be written in it. $data = fopen($filename, a); // And here we write the data. fwrite($data,$theText); // And here we close the file. fclose($data); ? That's All. Of course you can modify and enhance the code to meet your needs I wish this help you. The Panister! Wim Van Geyt [EMAIL PROTECTED] wrote in message news:[EMAIL PROTECTED] Hi, I want to send a choice to a textfile in php. Now i don't know how to let the button communicate with the php script? And do i have to write the script in the same page as the page where i have writed the radiobuttons? Does anyone knows an answer ? Thanks Crazydj - Mail.be, WebMail and Virtual Office http://www.mail.be -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
