Re: [PHP-DB] Conditional updating...
try this one.
just pass for $_value an array with your table fieldname as your key
function constructUpdate( $_tbl_name, $_where, $_values )
{
$valstr = '';
$firstval = false;
if (is_array($_values)) {
foreach( $_values as $key=$val ) {
if ($val != '') {
if( $firstval )
$valstr.= ',';
if (is_string($val)) {
$valstr.= $key = '$val';
} else {
$valstr.= $key = $val;
}
$firstval = true;
}
}
} else {
$valstr= $_values;
}
$retStr = update $_tbl_name set $valstr;
if( $_where )
$retStr.= where $_where;
return $retStr;
}
[PHP-DB] Count Many Records
Thanks in advance for your help, and forgive me if this is me being bone-headed. :-) The following code works and accomplishes what I need it to do, but I am wondering if there is a better way to accomplish the same task. I have several tables of records and I need to count and then display. Even if I could just combine the first three queries (below) into one that would probably be a lot better than what I am doing now. $data1_query = select id from data1 WHERE status = ''; $data1_results = mysql_query($data1_query); $data1_count = mysql_num_rows($data1_results); $data1p_query = select id from data1 WHERE status = 'p'; $data1p_results = mysql_query($data1p_query); $data1p_count = mysql_num_rows($data1p_results); $data1h_query = select id from data1 WHERE status = 'h'; $data1h_results = mysql_query($data1h_query); $data1h_count = mysql_num_rows($data1h_results); echo tr; echo td align=\center\ valign=\top\$data1_count/td; echo td align=\center\ valign=\top\$data1h_count/td; echo td align=\center\ valign=\top\$data1p_count/td; echo /tr; Then do the same thing for the second table, and so on. $data2_query = select id from data2 WHERE status = ''; $data2_results = mysql_query($data2_query); $data2_count = mysql_num_rows($data2_results); $data2p_query = select id from data2 WHERE status = 'p'; $data2p_results = mysql_query($data2p_query); $data2p_count = mysql_num_rows($data2p_results); $data2h_query = select id from data2 WHERE status = 'h'; $data2h_results = mysql_query($data2h_query); $data2h_count = mysql_num_rows($data2h_results); echo tr; echo td align=\center\ valign=\top\$data2_count/td; echo td align=\center\ valign=\top\$data2h_count/td; echo td align=\center\ valign=\top\$data2p_count/td; echo /tr; -- Kevin Murphy Webmaster: Information and Marketing Services Western Nevada Community College www.wncc.edu 775-445-3326 -- Kevin Murphy Webmaster: Information and Marketing Services Western Nevada Community College www.wncc.edu 775-445-3326
Re: [PHP-DB] Count Many Records
Kevin Murphy asks: The following code works and accomplishes what I need it to do, but I am wondering if there is a better way to accomplish the same task. I have several tables of records and I need to count and then display. Even if I could just combine the first three queries (below) into one that would probably be a lot better than what I am doing now. $data1_query = select id from data1 WHERE status = ''; $data1_results = mysql_query($data1_query); $data1_count = mysql_num_rows($data1_results); $data1p_query = select id from data1 WHERE status = 'p'; $data1p_results = mysql_query($data1p_query); $data1p_count = mysql_num_rows($data1p_results); $data1h_query = select id from data1 WHERE status = 'h'; $data1h_results = mysql_query($data1h_query); $data1h_count = mysql_num_rows($data1h_results); echo tr; echo td align=\center\ valign=\top\$data1_count/td; echo td align=\center\ valign=\top\$data1h_count/td; echo td align=\center\ valign=\top\$data1p_count/td; echo /tr; Then do the same thing for the second table, and so on. $data2_query = select id from data2 WHERE status = ''; $data2_results = mysql_query($data2_query); $data2_count = mysql_num_rows($data2_results); $data2p_query = select id from data2 WHERE status = 'p'; $data2p_results = mysql_query($data2p_query); $data2p_count = mysql_num_rows($data2p_results); $data2h_query = select id from data2 WHERE status = 'h'; $data2h_results = mysql_query($data2h_query); $data2h_count = mysql_num_rows($data2h_results); echo tr; echo td align=\center\ valign=\top\$data2_count/td; echo td align=\center\ valign=\top\$data2h_count/td; echo td align=\center\ valign=\top\$data2p_count/td; echo /tr; Kevin, You haven't said what you want the page to look like, but you could have a html select box of letters (a,b,c,d...) that would allow for the selection of multiple items, then grab the values out of the array created and add them to the select query, and loop through it: $data1_query = select id from data1 WHERE status = '$value_from_letter_array'; Then process as you have done. Or you could use a checkbox array... Does that help any? David -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] Count Many Records
Actually the design is in the code below I need to display the counts from all of those queries in a grid. Basically, its just a summary of a bunch of information. Another way to look at it would be a several lines that say something like this: You have $data1_count NEW records in data1, You have $data1p_count PROCESSED records in data1, etc. -- Kevin Murphy Webmaster: Information and Marketing Services Western Nevada Community College www.wncc.edu 775-445-3326 On Jun 28, 2006, at 1:56 PM, [EMAIL PROTECTED] wrote: Kevin Murphy asks: The following code works and accomplishes what I need it to do, but I am wondering if there is a better way to accomplish the same task. I have several tables of records and I need to count and then display. Even if I could just combine the first three queries (below) into one that would probably be a lot better than what I am doing now. $data1_query = select id from data1 WHERE status = ''; $data1_results = mysql_query($data1_query); $data1_count = mysql_num_rows($data1_results); $data1p_query = select id from data1 WHERE status = 'p'; $data1p_results = mysql_query($data1p_query); $data1p_count = mysql_num_rows($data1p_results); $data1h_query = select id from data1 WHERE status = 'h'; $data1h_results = mysql_query($data1h_query); $data1h_count = mysql_num_rows($data1h_results); echo tr; echo td align=\center\ valign=\top\$data1_count/ td; echo td align=\center\ valign=\top\ $data1h_count/td; echo td align=\center\ valign=\top\ $data1p_count/td; echo /tr; Then do the same thing for the second table, and so on. $data2_query = select id from data2 WHERE status = ''; $data2_results = mysql_query($data2_query); $data2_count = mysql_num_rows($data2_results); $data2p_query = select id from data2 WHERE status = 'p'; $data2p_results = mysql_query($data2p_query); $data2p_count = mysql_num_rows($data2p_results); $data2h_query = select id from data2 WHERE status = 'h'; $data2h_results = mysql_query($data2h_query); $data2h_count = mysql_num_rows($data2h_results); echo tr; echo td align=\center\ valign=\top\$data2_count/ td; echo td align=\center\ valign=\top\ $data2h_count/td; echo td align=\center\ valign=\top\ $data2p_count/td; echo /tr; Kevin, You haven't said what you want the page to look like, but you could have a html select box of letters (a,b,c,d...) that would allow for the selection of multiple items, then grab the values out of the array created and add them to the select query, and loop through it: $data1_query = select id from data1 WHERE status = '$value_from_letter_array'; Then process as you have done. Or you could use a checkbox array... Does that help any? David
RE: [PHP-DB] Converting to Decimal
$val = number_format($row['val'],2); Bastien From: Mark Bomgardner [EMAIL PROTECTED] Reply-To: [EMAIL PROTECTED] To: Php-Db php-db@lists.php.net Subject: [PHP-DB] Converting to Decimal Date: Wed, 28 Jun 2006 17:20:21 -0500 I am query a database and pulling some decimal values out of the table, but when I display whole numbers in php, it drops the decimal places. It takes a value of 12.00 in the database and makes it 12, where I need 12.00. I am having trouble finding ways to cast this value. markb -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] Converting to Decimal
You could actually do (int) $var or use the sprintf(%d, $var); -Original Message- From: John Meyer [mailto:[EMAIL PROTECTED] Sent: Miércoles, 28 de Junio de 2006 06:04 p.m. To: [EMAIL PROTECTED] Cc: Php-Db Subject: Re: [PHP-DB] Converting to Decimal Mark Bomgardner wrote: I am query a database and pulling some decimal values out of the table, but when I display whole numbers in php, it drops the decimal places. It takes a value of 12.00 in the database and makes it 12, where I need 12.00. I am having trouble finding ways to cast this value. First, off, when you directly query the database, does it come back as a floating number. And secondly, have you checked this out: http://www.php.net/manual/en/function.sprintf.php -- Online library -- http://pueblonative.110mb.com 138 books and counting. -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php Este mensaje es exclusivamente para el uso de la persona o entidad a quien esta dirigido; contiene informacion estrictamente confidencial y legalmente protegida, cuya divulgacion es sancionada por la ley. Si el lector de este mensaje no es a quien esta dirigido, ni se trata del empleado o agente responsable de esta informacion, se le notifica por medio del presente, que su reproduccion y distribucion, esta estrictamente prohibida. Si Usted recibio este comunicado por error, favor de notificarlo inmediatamente al remitente y destruir el mensaje. Todas las opiniones contenidas en este mail son propias del autor del mensaje y no necesariamente coinciden con las de Radiomovil Dipsa, S.A. de C.V. o alguna de sus empresas controladas, controladoras, afiliadas y subsidiarias. Este mensaje intencionalmente no contiene acentos. This message is for the sole use of the person or entity to whom it is being sent. Therefore, it contains strictly confidential and legally protected material whose disclosure is subject to penalty by law. If the person reading this message is not the one to whom it is being sent and/or is not an employee or the responsible agent for this information, this person is herein notified that any unauthorized dissemination, distribution or copying of the materials included in this facsimile is strictly prohibited. If you received this document by mistake please notify immediately to the subscriber and destroy the message. Any opinions contained in this e-mail are those of the author of the message and do not necessarily coincide with those of Radiomovil Dipsa, S.A. de C.V. or any of its control, controlled, affiliates and subsidiaries companies. No part of this message or attachments may be used or reproduced in any manner whatsoever. -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] Converting to Decimal
Are you just displaying the value with the decimal places? If so, check out the function number_format($var,2) Skip Miguel Guirao wrote: You could actually do (int) $var or use the sprintf(%d, $var); -Original Message- From: John Meyer [mailto:[EMAIL PROTECTED] Sent: Miércoles, 28 de Junio de 2006 06:04 p.m. To: [EMAIL PROTECTED] Cc: Php-Db Subject: Re: [PHP-DB] Converting to Decimal Mark Bomgardner wrote: I am query a database and pulling some decimal values out of the table, but when I display whole numbers in php, it drops the decimal places. It takes a value of 12.00 in the database and makes it 12, where I need 12.00. I am having trouble finding ways to cast this value. First, off, when you directly query the database, does it come back as a floating number. And secondly, have you checked this out: http://www.php.net/manual/en/function.sprintf.php -- Online library -- http://pueblonative.110mb.com 138 books and counting. -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php Este mensaje es exclusivamente para el uso de la persona o entidad a quien esta dirigido; contiene informacion estrictamente confidencial y legalmente protegida, cuya divulgacion es sancionada por la ley. Si el lector de este mensaje no es a quien esta dirigido, ni se trata del empleado o agente responsable de esta informacion, se le notifica por medio del presente, que su reproduccion y distribucion, esta estrictamente prohibida. Si Usted recibio este comunicado por error, favor de notificarlo inmediatamente al remitente y destruir el mensaje. Todas las opiniones contenidas en este mail son propias del autor del mensaje y no necesariamente coinciden con las de Radiomovil Dipsa, S.A. de C.V. o alguna de sus empresas controladas, controladoras, afiliadas y subsidiarias. Este mensaje intencionalmente no contiene acentos. This message is for the sole use of the person or entity to whom it is being sent. Therefore, it contains strictly confidential and legally protected material whose disclosure is subject to penalty by law. If the person reading this message is not the one to whom it is being sent and/or is not an employee or the responsible agent for this information, this person is herein notified that any unauthorized dissemination, distribution or copying of the materials included in this facsimile is strictly prohibited. If you received this document by mistake please notify immediately to the subscriber and destroy the message. Any opinions contained in this e-mail are those of the author of the message and do not necessarily coincide with those of Radiomovil Dipsa, S.A. de C.V. or any of its control, controlled, affiliates and subsidiaries companies. No part of this message or attachments may be used or reproduced in any manner whatsoever. -- Skip Evans Big Sky Penguin, LLC 61 W Broadway Butte, Montana 59701 406-782-2240 -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
