Hi!
I think I have solved your problem...
I have attached an sql file to create the sample DB I created for my test
and a PHP file for you to run to see how I have implemented it.
First create the tables with the .sql file an then execute the .php file
from your browser.
Hope these help.
I think I forgot something usefull...
- Original Message -
From: Beau Lebens [EMAIL PROTECTED]
To: PHP DB (E-mail) [EMAIL PROTECTED]
Sent: Thursday, February 21, 2002 3:59 AM
Subject: [PHP-DB] SELECT where something exists but something else does not
Hey guys,
I am a little stuck
You can use:
if ( ($var == 1) or ($var == 2) or ($var == 3))
{
...
}
- Original Message -
From: Dave Carrera [EMAIL PROTECTED]
To: php List [EMAIL PROTECTED]
Sent: Thursday, February 21, 2002 12:40 PM
Subject: [PHP-DB] How do I add multiple var to a if clause ?
Hi All
I forgot somthing
?
if (isset($submit) ) // this )
{
IF ($submit) // this is line 8
{
.
}
}
?
- Original Message -
From: George Lioumis [EMAIL PROTECTED]
To: chris [EMAIL PROTECTED]; PHP Mailing List
[EMAIL PROTECTED]
Sent: Friday, February 08, 2002 3
Good day to all.
I tried the following code from PHP's manual
if (isset($submit))
{
if ($submit == Save)
{
echo $im_fileBR;
$tok = strtok($im_file, \\);
while ($tok)
{
echo $tokBR;
$tok = strtok (\\);
}
}
}
I have the string $im_file =C:\\a_path\\image.jpg and I want to
- Original Message -
From: George Lioumis
To: B.J.Rumsey
Sent: Wednesday, January 30, 2002 11:47 AM
Subject: Re: [PHP-DB] Drop down list
Try the following:
?php
$option_block = ;
$get_list = select * from table_name;
$res = mysql_query($get_list) or die (mysql_error());
while
Hello everyone!
I have the following table:
|name
|--
|n_id
|n_name
|ns_id
---
I do a select: SELECT n_name from name and I want to put all selected n_name
values into an array (say it names)
How can this be done??
Thanx in advance.
Hello everyone!
In my mySQL DB I have the tables:
| po_product | and | products|
|--| | -|
| po_id | | product_id |
| product_id | | product_name |
Try the following:
?php
mysql_connect(firstDB,username,password) or die (Unable to connect to
Server);
mysql_select_db(DB) or die (Unable to select DB);
---GET THE INFO YOU WANT AND PLACE IT IN AN APPROPRIATE VARIABLES
--FOR LATER COMPARISON
mysql_connect(secondDB,username,password) or die
Good day to all!
Consider the following code:
FORM ...
INPUT type=Text name=criteria size=50
BR
INPUT type=Button name=Find value=Find
/FORM
I want to get the text that the user writes into the text field into a php variable to
use it in the same page.
I want to use this text as a criteria to
OR post action=?php echo $PHP_SELF?
Then in your page have a php tag that checks for the presence of $Find (in
your case), e.g.
if ($Find) {
sql = (SELECT * FROM table WHERE $criteria = value);
then the rest...
}
-torrent
George Lioumis [EMAIL PROTECTED] wrote in message
I think that you MUST retype the whole URL.
George.
- Original Message -
From: J-E-N [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Saturday, October 20, 2001 2:22 PM
Subject: [PHP-DB] https
hello,
how can i switch from http to https without typing the whole url?
thanks
--
PHP
Yes, but mySQL 4.0 is alpha Release and Apache 1.3.22 for Win32 is not as
stable as for Unix platforms
So, let's wit a bit more!
- Original Message -
From: suraj [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Thursday, October 18, 2001 10:55 AM
Subject: [PHP-WIN] released
Hello
Il faut tu ecrire:
if ($colonne[LIV_TYPE_EVT] == 21)
{
$couleur = yellow;
}
else if ($colonne[LIV_TYPE_EVT] == 1)
{
$couleur = 009933;
}
else
{
$couleur = FF;
}
Georges Lioumis.
-
main.php?sectionName=homevariable_2=value...variable_n=value
- Original Message -
From: Tony Leach [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Wednesday, October 17, 2001 5:11 PM
Subject: [PHP-WIN] variables in URL
How do I construct a URL to pass more than one variable to a php
15 matches
Mail list logo
