[PHP-DB] 'Page can not be displayed' when hitting the back button

2005-02-13 Thread Jason Walker
 
 
I have a shopping cart that is working completely fine in Firefox. In I.E.,
I can not get the page to display when hitting the back button. This may not
necessarily be a PHP problem, but since moving to PHP session variables and
not cookies, this error has popped up.
 
In Firefox, I get the POST DATA message stating that post data has already
been sent, blah blah blah. In IE, I get the Page Can Not Be Display.
 
I am just curious if anyone else has come across this and if they found a
solution/cause.
 
Thanks.
 
Jason Walker
 


RE: [PHP-DB] 'Page can not be displayed' when hitting the back button

2005-02-13 Thread Jason Walker
In case anyone comes across this in the future, I finally found a solution
to this:

php.ini 

Find session.cache_limiter and make sure the setting is set to public or
private. nocache was the problem.

Does anyone have any concerns about this setting? I am looking around to see
if this causes any security issues. I did find some stuff about this
affecting downloads, but there are no downloads through PHP pages.

Thanks.

-Original Message-
From: Jason Walker [mailto:[EMAIL PROTECTED] 
Sent: Sunday, February 13, 2005 7:17 PM
To: php-db@lists.php.net
Subject: [PHP-DB] 'Page can not be displayed' when hitting the back button

 
 
I have a shopping cart that is working completely fine in Firefox. In I.E.,
I can not get the page to display when hitting the back button. This may not
necessarily be a PHP problem, but since moving to PHP session variables and
not cookies, this error has popped up.
 
In Firefox, I get the POST DATA message stating that post data has already
been sent, blah blah blah. In IE, I get the Page Can Not Be Display.
 
I am just curious if anyone else has come across this and if they found a
solution/cause.
 
Thanks.
 
Jason Walker
 

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RE: [PHP-DB] PHP query to mysql database returns emtpy data, but Query Browser shows records

2005-01-06 Thread Jason Walker


Graeme - you were moving in the right direction. Since the data in the field
is varchar(250), the only thing that changes is the fact that the last
number is 3 digits. Other page queries were also affected with 4 x 2 digit
numbers in the category field (eg. '37 48 49 52').

By adding '%' between each number and using 'LIKE' as opposed to '=', the
queries through PHP return the correct value.

I think is very strange as 3x numbers work fine when using spaces (' ')
between each criteria (as in '37 48 53').

The change would look something like:

SELECT description from cpProducts where category like '39%47%48%172'

There is something between each element, but PHP can not seem to handle the
third empty space.

Thanks to all for your help and ideas!


Jason Walker
[EMAIL PROTECTED]
http://www.desktophero.com
-Original Message-
From: graeme [mailto:[EMAIL PROTECTED] 
Sent: Thursday, January 06, 2005 7:55 PM
To: Jochem Maas
Cc: Jason Walker; php-db@lists.php.net
Subject: Re: [PHP-DB] PHP query to mysql database returns emtpy data, but
Query Browser shows records

Sorry I was in a hurry for lunch.. I meant category='39 ' OR category 
'47' etc...  which of course the IN clause would address.

But if it is a character string '39 47 48 172' that is required then 
double check the number of spaces that are required against those that 
are produced. Maybe is is a double digit and two spaces trip[le digit 
and one? Without an example of the data and what is produced it's hard 
to help.

graeme

Jochem Maas wrote:

 graeme wrote:

 Hi,

 You have:

 $query example = SELECT description from cpProducts where 
 category='39 47 48 172'

 don't you want to add a logical operator such as OR, possibly AND

 $query example = SELECT description from cpProducts where 
 category='39 OR 47 OR 48 OR 172'

 graeme.


 whatever it is that he is trying to do - I doubt he wants to put 'OR's 
 in the character string, besides which AFAIK you can't do something like:

 SELECT description from cpProducts where category=39 OR 47 OR 48 OR 172;

 (possibly the SQL above will actually return all rows because any 
 number greater than zero will evaluate to true - e.g. ($x = true || 1) 
 is always true regardless of the value of $x, I am assuming the same 
 general logic goes for SQL or'ing)
 it should be:

 SELECT description from cpProducts where category=39 OR 47 OR 48 OR 172;

 Jason, read on for more (possible) help (well I gave it a shot but I 
 don't think it will be any help, sorry):


 Jason Walker wrote:

  

 Here is the query:

  function ReturnPackageDescriptions($pack, $cat, $hotcat, $hotid){
  $comIB = $cat .   . $pack .   . $hotcat .   . 
 $hotid;
   $catLength = strlen($comIB);
   echo $catLength;
   $query = SELECT description from cpProducts where 
 category=' . $cat .   . $pack .   . $hotcat .   . $hotid . ';
   echo bR . $query . br;
  echo combined package number =  . $comIB . br;
$retval = ;
   $link = 
 mysql_connect($config['host'],$config['user'],$config['pass']) or 
 die(Could not connect);
   mysql_select_db('stc_store') or die(Unable to connect 
 to the default database);
   $result = mysql_query($query) or die(Unable to 
 pull the menu objects for main event details);
   echo mysql_affected_rows() . br;
 while ($results = mysql_fetch_array($result, 
 MYSQL_ASSOC)){
  extract($results);
echo $description;
$retval = $description;
   }
mysql_free_result($result);
  mysql_close($link);
   return $retval;
   }

 I have some extra 'echo' statements to see the progress on the web 
 page. If I remove the 'where' clause within the SQL statement, I get 
 rows. But when I add the 'where' portion, no records are returned.

 Here is an example of what the query looks like:

 $query example = SELECT description from cpProducts where 
 category='39 47 48 172'


 I'll assume that your table has a field named 'category' - otherwise 
 the statement should throw you a big error :-) BUT is it a character 
 data field (i.e. does it contain text)? AND do you actually have rows 
 where the value of the category field is '39 47 48 172' - in order to 
 get rows returned when running your example query the value needs to 
 match this string EXACTLY.

 Given the fact that using mysql control center give you the desired 
 result the above probably was a waste of time typing. Given that fact 
 the only thing I can think of is that you have a extra space floating 
 about (but I can't see it in the code your provided)

 does the output of mysql_error() provide any feedback?

 (what an odd problem!)



 When I run the same query in MYSQL Control center or Query Browser, 
 no problem. I use this function template for my SELECT statements.

 Please let me know if there is something missing from

RE: [PHP-DB] SQL statement

2005-01-06 Thread Jason Walker

First off - $_POST['CompanyName'] is valid, right?

Can you do something like this?:
if (isset($_POST['CompanyName'])){
$sqlCompanyName = $_POST['CompanyName'];
} else {
return them back to the form, or something?
}


$query_company_listing = SELECT CompanyID, CompanyName,
CompanyOrDepartment, BillingAddress, City, PostalCode, PhoneNumber FROM
company WHERE company.CompanyName='$sqlCompanyName' ORDER BY
CompanyName ASC;


Also, what datatype is CompanyName? If it is varchar - or really anything
else - I have had better look single quote encapsulation on the VALUE
portion of the query (company.CompanyName='VALUE' vs.
company.CompanyName=VALUE)

Not knowing the datatypes may make this an irrelevant point though.



-Original Message-
From: PHPDiscuss - PHP Newsgroups and mailing lists
[mailto:[EMAIL PROTECTED] 
Sent: Thursday, January 06, 2005 12:09 PM
To: php-db@lists.php.net
Subject: [PHP-DB] SQL statement

Hello everybody,
I'm building a small application and I have trouble passing a POST
variable form one page to another inside the SQL statement.

The query displayed below works great without the
.$_POST['CompanyName']. 

$query_company_listing = SELECT CompanyID, CompanyName,
CompanyOrDepartment, BillingAddress, City, PostalCode, PhoneNumber FROM
company WHERE company.CompanyName=.$_POST['CompanyName'].  ORDER BY
CompanyName ASC;

But it messes up if I include it because the first  is considered as the
end of the previous one and so on, so the code gets messed up.

I'll really appreciate any/all help!
Have you all an excellent year!
Jorge

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[PHP-DB] PHP query to mysql database returns emtpy data, but Query Browser shows records

2005-01-05 Thread Jason Walker










Here is the query:

function ReturnPackageDescriptions($pack, $cat,
$hotcat, $hotid){
  $comIB =
$cat .   . $pack .   . $hotcat .   .
$hotid;
 $catLength =
strlen($comIB);
 echo $catLength;
 $query = SELECT
description from cpProducts where category=' . $cat .   .
$pack .   . $hotcat .   . $hotid . ';
 echo
bR . $query . br;
echo combined
package number =  . $comIB . br;
  
$retval = ;
 $link =
mysql_connect($config['host'],$config['user'],$config['pass']) or
die(Could not connect);

mysql_select_db('stc_store') or die(Unable to
connect to the default database);
  
$result = mysql_query($query) or die(Unable to pull the menu objects for
main event details);
 echo
mysql_affected_rows() . br;
while ($results =
mysql_fetch_array($result, MYSQL_ASSOC)){
   
extract($results);
  
echo $description;

$retval = $description;
 }
 
   
mysql_free_result($result);
mysql_close($link);
 return $retval; 
 }

I have some extra 'echo' statements to see the progress on the web page. If I
remove the 'where' clause within the SQL statement, I get rows. But when I add
the 'where' portion, no records are returned.

Here is an example of what the query looks like:

$query example = SELECT description from cpProducts where category='39 47 48
172'

When I run the same query in MYSQL Control center or Query Browser, no problem.
I use this function template for my SELECT statements. 

Please let me know if there is something missing from the code.

Thanks.





Jason Walker

[EMAIL PROTECTED]

http://www.desktophero.com








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RE: [PHP-DB] MYSQL Maximum Time Exceeded

2004-12-15 Thread Jason Walker


This not be what you need, but I think there are some squiggle brackets
missing.

$conexion = mysql_connect(servername,username,password);

?php

If (!$conexion){
Echo Error connecting.;
}

?

Again, I don't think this is the root of the problem but it's the first
thing that popped out to me without knowing much more about your system.

Have you been able to connect to your mySQL instance with PHP before? With
no root password?

BTW - I have installed PHP and mySQL on WinXP in the past and it worked
fine. One caveat is that I recall using Apache not IIS. 

-Original Message-
From: PHPDiscuss - PHP Newsgroups and mailing lists
[mailto:[EMAIL PROTECTED] 
Sent: Wednesday, December 15, 2004 9:20 AM
To: [EMAIL PROTECTED]
Subject: [PHP-DB] MYSQL Maximum Time Exceeded

Hi.

I am running MySQL 4.0 and PHP 4.3.9 (MySQL Client Version 3.9.23) in
Windows XP.  I get this error when I try to connect to mysql:

Fatal error: Maximum execution time of 60 seconds exceeded in
c:\inetpub\wwwroot\index.php on line 4

My PHP script is:

html
body
?php
$conexion = mysql_connect( localhost, root,  );
if (!$conexion )
  echo Error Connecting.

?
/body
/html

I also tried installing newer PHP versios and newer MySQL but it's the
same.  Can anybody help me, please ?  Is WinXP incomaptible with MySQL or
what ?

Thanks in advance.

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