then protect the directories/scripts from anyone wanting to have a look
(not that they're worth much!).
Thanks
Mick Lloyd
[EMAIL PROTECTED]
Tel: +44 (0)1684 560224
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/a
but I would love to be corrected on this by a PHP expert!
Regards
Mick Lloyd
[EMAIL PROTECTED]
Tel: +44 (0)1684 560224
- Original Message -
From: Mark Collin [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Tuesday, March 20, 2001 9:44 PM
Subject: [PHP-DB] Transmitting Arrays
I have a fo
Gary
Thanks for the advice. I had checked the string length to make sure there
were no "hidden" spaces (which there aren't in the specific field I am
selecting) and have now tried trim() but to no avail. Still fiddling with
it!
Regards
Mick Lloyd
[EMAIL PROTECTED]
Tel: +44 (0)1
Code =
'".$row['Primaryexpertise']."'") or die (mysql_error());
$resultp = mysql_query("select Primaryid from primarycodes where Code like
'%$row[Primaryexpertise]%'") or die (mysql_error());
$pcodeid = mysql_fetch_array($resultp) or die("No pcodeid");
Regards
Mi
l_query("select Primaryid from primarycodes where Code like
'%$row[Primaryexpertise]%'")
but I need greater accuracy because some codes contain similar data. String
manipulation has me baffled most of the time!
Thanks.
Mick Lloyd
[EMAIL PROTECTED]
Tel: +44 (0)1684 560224
ot;;
$result=mysql_query("update $TA set P1description = load_file($cvfile)") or
die (mysql_error());
Output shows File exists 1 (which I assume menas True) and the table is
being read because $rows equals 2.
P1
Then I get the "You have an error in your SQL syntax near '(.txt)'
Zend, etc but with little success.
Thanks
Mick Lloyd
[EMAIL PROTECTED]
Tel: +44 (0)1684 560224
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