first query?
Also, you should avoid extract, it litters your code with dead and untraceable
variables. Use $array['msg_Passowrd'] instead.
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the php variables.
img src=bandingGraph.php?$datax=$row[Distance]$datay=$row[MBusage];
// I think this is where I am having issues.
try instead
?php
echo 'img
src=bandingGraph.php?datax='.$row[Distance].'datay='.$row[MBusage].'';
?
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Simcha Younger sim...@syounger.com
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PHP Database
need double-quotes here,
\%s\,
parseNull($_POST['Company']).,
'$_POST[Phone]',
'$_POST[Email]'
), mysql_real_escape_string($_POST['Registrant']));
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level.
Any ideas how I can get this to work? In the end there will be 5 levels.
Thanks
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'
group by taggings.id
You probably awnt a LEFT JOIN instead of a
Simcha Younger
-Original Message-
From: Catharsis [mailto:[EMAIL PROTECTED]
Sent: Thursday, September 11, 2008 1:41 PM
To: php-db@lists.php.net
Subject: [PHP-DB] Delicious style Tags table
So I am having difficulty
I did a little testing, and this should work better:
Select...
From...
group by taggings.id
HAVING GROUP_CONCAT('name') like 'soup'
AND GROUP_CONCAT('name') like 'vegetarian'
Simcha Younger
-Original Message-
From: Catharsis [mailto:[EMAIL PROTECTED]
Sent: Thursday, September 11
Select * FROM ... WHERE DAYOFWEEK(datecol)=7
-Original Message-
From: Ben Miller [mailto:[EMAIL PROTECTED]
Sent: Tuesday, August 05, 2008 8:10 PM
To: PHP. DB Mail List
Subject: [PHP-DB] Date Translation in MySQL
I'm looking for a quick and simple way to query a MySQL database by date,
