Re: [PHP-DB] Books
1.PHP Objects,Patterns, and Practice 2.Pro PHP Patterns, Frameworks,Testing and More MySQL: 1.MySQL Cookbook html/css no idea, I dont have good ideas of designing even if I become fluent in css.But its handy to know css just how it generally works and its place on the webAnyways, dont listen to me, I am more of a programmer rather than web-developerSo my first starting point was PHP, and along the way I am becoming fluent on the rest of the web-tools. Its nice I think to know your interests Server Side or Frontend.If you intend to be Server Side Dev, then HTML PHP MySQL are the starting point.Frontend you should start off with CSS,HTML , Javascript.etc. Gr Muhsin On 10/18/2010 04:06 PM, Ethan Rosenberg wrote: Dear List - I posted part of this question on the general list. I am posting here just in case this list did not see the post. This should NOT be taken as any type of negative reference to the general list, the members of which have furnished me excellent help. Question: What books would your recommend to learn HTML/CSS, MySQL and PHP? The books should start from the basic level and proceed to the intermediate/advanced level. Thanks. Ethan -- Extra details: OSS:Gentoo Linux profile:x86 Hardware:msi geforce 8600GT asus p5k-se location:/home/muhsin language(s):C/C++,VB,VHDL,bash,PHP,SQL,HTML,CSS Typo:40WPM url:http://www.mzalendo.net url:http://www.zanbytes.com -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] Re: Need help-Send email
Is this related to PHP-DB?
Anyways, if I understands it correctly is that mail() is working but the
client is categorizing the mail received into the SPAM folder.This might
means your issue is not longer on that mail(), but on the your
mail-client filters.
GR
mrfroasty
nagendra prasad wrote:
Hi all,
Below is the code that I have coded after replies from all of you. But
before that I want to thank all of you for your help. I have coded the email
code but still it is giving me an error. Please help me.
?php
//sending email script
$to = exam...@gmail.com;
$subject = Email from admin;
if ($_POST['submit'])
{
//get data from form
$name = $_POST['name'];
$message = $_POST['message'];
if ($name$message)
{
$namelen = 20;
$messagelen = 300;
if (strlen($name)=$namelen strlen($message)=$messagelen)
{
//everything is ok
ini_set(SMTP, smtp.gmail.com);
$to = exam...@gmail.com;
$subject = Email from admin;
$header = from: exam...@gmail.com;
$body = Email from $name \n\n $message;
mail($to,$subject,$body,$header);
die();
}
else
die (Max length of name is $namelen, and max length for message is 300);
}
else
die(you must enter a name);
}
?
html
form action='sendemail.php' method='POST'
Name: input type='text' name='name' maxlenght='20'br
Message: brtextarea name='message'/textareap
input type='submit' name='submit' value='Send an email'
/form
/html
--
Also I have simplified the code by just using the email() function but the
problem is its sending the mail in the SPAM. The code is below :
?php
$to = exam...@gmail.com;
$subject = Test mail;
$message = Hello! This is a simple email message.;
$from = exam...@gmail.com;
$headers = From: $from;
mail($to,$subject,$message,$headers);
echo Mail Sent.;
?
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Re: [PHP-DB] SELECT LIKE with % and without %
Emiliano Boragina wrote: Hello. I am using this: $sql = SELECT * FROM table WHERE ID LIKE '%$_GET[id]%' AND title LIKE '%$_GET[word]%'; This doesnt work? $sql = SELECT * FROM table WHERE ID='some_id' AND title='some_title'; -- Extra details: OSS:Gentoo Linux profile:x86 Hardware:msi geforce 8600GT asus p5k-se location:/home/muhsin language(s):C/C++,VB,VHDL,bash,PHP,SQL,HTML,CSS Typo:40WPM url:http://mambo-tech.net url:http://blog.mambo-tech.net -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] Please help a newbie
Hello,
May be try something like this:
$query1=
CREATE TABLE contacts(
id int(16) NOT NULL auto_increment,
phone varchar(15) NOT NULL,
name varchar(15) NOT NULL,
address varchar(15) NOT NULL,
PRIMARY KEY (id)
);
$query2 = INSERT INTO contacts VALUES ('NULL','$phone', '$name',
'$address');
P:S
id incremented automatically by MYSQL now
GR
mrfroasty
Rij wrote:
Hello,
I am new to the world of PHP and MySQL. My objective is to create a
table, insert values in it and read it back.
Here's the partial code to create a table from a PHP file:
if (!$table_exists) {
$query=CREATE TABLE contacts (id int(20) NOT NULL, name
varchar(15) NOT NULL, address varchar(15),PRIMARY KEY(id)
if (mysql_query($query, $con)) echo Table contacts created;
else die('Unable to create table : '.mysql_error());
}
I input the values from a HTML form. Here is the partial code.
$phone = $_POST['phone'];
$name = $_POST['name'];
$address = $_POST['address'];
$query = INSERT INTO contacts VALUES ('$phone', '$name', '$address');
if (mysql_query($query, $con)) echo Values inserted;
else die('Unable to create table : '.mysql_error());
Now the problem that I am facing is that when I make my first insert,
the id field shows a garbage value and not the number that I entered.
Subsequent entries into the table show up just fine. It's only the
first one.
What am I doing wrong?
Thanks, Rij
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Re: [PHP-DB] Retrieving Image Location in MySQL
Hello,
Does something like this work on your php script?
$location=..\..\Bldgs_lots\Burruss.jpg
OR
$location=..\Bldgs_lots\Burruss.jpg
GR
Muhsin
Sashikanth Gurram wrote:
This is the location where I have saved my images.
/C:\Users\Sashikanth\Desktop\Bldgs_lots\Burruss.jpg
/I have loaded the above location exactly into my database. But when I
call it using
/echo img src='$location' border='1' height='150' width='200'
alt='$build' ;/
It is simply giving me some blank empty space, with the name of the
picture in the blank space (Since I am using alt). So, as I see it,
the retrieval part is working fine, but the displaying of the image is
not functioning properly. I am using a WAMP server. Any kind of
suggestions are welcome.
Thanks,
Sashi
PS: For Reference, I am posting my entire code below again. The image
retrieval part is towards the end of the code.
/html
body
form action=mysqli.php method=post
br
div align=center
Building Name:select name=name
option value= Select a Building/option
option value=Military BuildingMilitary Building/option
option value=Monteith HallMonteith Hall/option
option value=New Residence Hall-Career Services SiteNew
Residence Hall-Career Services Site/option
option value=Williams HallWilliams Hall/option
option value=Women's Softball FieldWomen's Softball
Field/option
option value=Wright HouseWright House/option
/select
/div
input type=submit /
/form
img src=mysqli.php?
?php
// Connects to your Database
$host=**;
$user=***;
$password=;
$dbname=*;
$cxn=mysqli_connect($host, $user, $password, $dbname) ;
if (!$cxn=mysqli_connect($host, $user, $password, $dbname))
{
$error=mysqli_error($cxn);
echo $error;
die();
}
else
{
echo Connection established successfully;
}
//Define the variables for Day and Month
$Today=date(l);
$Month=date(F);
$build=$_POST[name];
$low_speed=2.5;
$high_speed=4;
$hour=date(G);
$minute=date(i);
if ($minute=00 $minute=14)
{
$minute=00;
}
elseif ($minute=15 $minute=29)
{
$minute=15;
}
elseif ($minute=30 $minute=44)
{
$minute=30;
}
else
{
$minute=45;
}
$times=10:$minute;
$sql=SELECT buildingname, parking_lot_name, empty_spaces, distance,
round(distance/($low_speed*60),1) AS low_time,
round(distance/($high_speed*60),1) AS high_time, Location FROM
buildings, buildings_lots, parkinglots, occupancy2, Image where
(buildings.buildingcode=occupancy2.building AND
buildings.buildingcode=buildings_lots.building_code AND
parkinglots.parking_lot_code=buildings_lots.parking_lot_code AND
parkinglots.parking_lot_code=occupancy2.parking_lot AND
Buildings.BuildingCode=Image.BuildingCode) AND buildingname='$build'
AND month='$Month' AND day='Monday' AND Time='$times';
$data = mysqli_query($cxn,$sql);
if (!$data=mysqli_query($cxn,$sql))
{
$error=mysqli_error($cxn);
echo $error;
die();
}
else
{
echo br;
echo Query sent successfully;
}
echo br;
echo h1 PARKING LOT INFORMATION h1;
echo table border='1' cellspacing='5' cellpadding='2';
echo tr\n
thBuilding/th\n
thParking Lot/th\n
thEstimated Number of Empty Spaces/th\n
thDistance (Feet)/th\n
thEstimated walking time to the building/th\n
/tr\n;
while ($row=mysqli_fetch_array($data))
{
extract($row);
$building = $row[0];
$parking_lot = $row[1];
$Number_of_Empty_Spaces = $row[2];
$Distance = $row[3];
$time_l = $row[4];
$time_h=$row[5];
$location=$row[6]; echo tr\n
td$building/td\n
td$parking_lot/td\n
td$Number_of_Empty_Spaces/td\n
td$Distance/td\n
td$time_h - $time_l mins/td\n
td$location/td\n
/tr\n;
}
echo /table\n;
echo img src='$location' border='1' height='150' width='200'
alt='$build' ;
?
/body
/html/
mrfroasty wrote:
Hello,
It might be something with location where the script is located and the
image.I think is normally the case if they arent on the same
directory...
If not you might want to try saving your image locations with something
like ../../image_folder/image.jpg
I am not sure though as I have seen this issue on one application but
it runs on LAMP
P:S
../ One step back from the script location
GR
Muhsin
Sashikanth Gurram wrote:
Hi,
Thanks a lot for the suggestion. It is working fine but there is some
problem. When I introduced the piece of code you have suggested into
my code, I am getting a space for the picture but nothing is there in
that space. It is just blank. I do not know the reason for this. I am
just attaching a picture just in case it might give you a better idea.
Further, this is the piece of code I have written to display the pic.
/echo img src='$location
Re: [PHP-DB] Retrieving Image Location in MySQL
Hello,
Storing only location of the image in dB wouldnt be any different than
other string/data retrieved from the dB.That means if you have something
like this in html documents whereby $image_location comes from the dB
It should work without header stuffs
Example
img src=$image_location border=1 height=150 width=200
alt=Image ISMAP
P:S
Replace $image_location with image location from your dB.
GR
Muhsin
Sashikanth Gurram wrote:
Dear all,
I have been trying to retrieve the location of a image from database
and display the image in the browser using PHP. I have written a sort
of code for the purpose. All I am getting in my browser after using
the code is a long set of ASCII characters with the following warning
*Warning*: Cannot modify header information - headers already sent by
(output started at C:\wamp\www\mysqli.php:65) in
*C:\wamp\www\mysqli.php* on line *237
*
I am herewith attaching my code. If anyone can point out the error or
give some kind of advice that would be really great. The location of
the image is stored in a table by the name IMAGE under the column name
Location and here in the code, the location is retrieved under the
varibale name $Location.
thanks,
Sashi
/html
body
form action=mysqli.php method=post
br
div align=center
Building Name:select name=name
option value= Select a Building/option
option value=Agnew HallAgnew Hall/option
option value=Rector Field HouseRector Field House/option
option value=Richard B. Talbot Educational Resources
CenterRichard B. Talbot Educational Resources Center/option
option value=Robeson HallRobeson Hall/option
option value=Sandy HallSandy Hall/option
option value=Saunders hallSaunders hall/option
option value=Seitz HallSeitz Hall/option
option value=Shanks HallShanks Hall/option
option value=Shultz HallShultz Hall/option
option value=Skelton Conference CenterSkelton Conference
Center/option
option value=Williams HallWilliams Hall/option
option value=Women's Softball FieldWomen's Softball
Field/option
option value=Wright HouseWright House/option
/select
/div
input type=submit /
/form
img src=mysqli.php?
?php
// Connects to your Database
$host=***;
$user=*;
$password=**;
$dbname=***;
$cxn=mysqli_connect($host, $user, $password, $dbname) ;
if (!$cxn=mysqli_connect($host, $user, $password, $dbname))
{
$error=mysqli_error($cxn);
echo $error;
die();
}
else
{
echo Connection established successfully;
}
//Define the variables for Day and Month
$Today=date(l);
$Month=date(F);
$build=$_POST[name];
$low_speed=2.5;
$high_speed=4;
$hour=date(G);
$minute=date(i);
if ($minute=00 $minute=14)
{
$minute=00;
}
elseif ($minute=15 $minute=29)
{
$minute=15;
}
elseif ($minute=30 $minute=44)
{
$minute=30;
}
else
{
$minute=45;
}
$times=$hour:$minute;
$sql=SELECT buildingname, parking_lot_name, empty_spaces, distance,
round(distance/($low_speed*60),1) AS low_time,
round(distance/($high_speed*60),1) AS high_time, Location FROM
buildings, buildings_lots, parkinglots, occupancy2, Image where
(buildings.buildingcode=occupancy2.building AND
buildings.buildingcode=buildings_lots.building_code AND
parkinglots.parking_lot_code=buildings_lots.parking_lot_code AND
parkinglots.parking_lot_code=occupancy2.parking_lot AND
Buildings.BuildingCode=Image.BuildingCode) AND buildingname='$build'
AND month='$Month' AND day='$Today' AND Time='$times';
$data = mysqli_query($cxn,$sql);
if (!$data=mysqli_query($cxn,$sql))
{
$error=mysqli_error($cxn);
echo $error;
die();
}
else
{
echo br;
echo Query sent successfully;
}
echo br;
echo h1 PARKING LOT INFORMATION h1;
echo table border='1' cellspacing='5' cellpadding='2';
echo tr\n
thBuilding/th\n
thParking Lot/th\n
thEstimated Number of Empty Spaces/th\n
thDistance (Feet)/th\n
thEstimated walking time to the building/th\n
/tr\n;
while ($row=mysqli_fetch_array($data))
{
extract($row);
$building = $row[0];
$parking_lot = $row[1];
$Number_of_Empty_Spaces = $row[2];
$Distance = $row[3];
$time_l = $row[4];
$time_h=$row[5];
$location=$row[6]; echo tr\n
td$building/td\n
td$parking_lot/td\n
td$Number_of_Empty_Spaces/td\n
td$Distance/td\n
td$time_h - $time_l mins/td\n
td$location/td\n
/tr\n;
}
echo /table\n;
$err=1;
if ($img = file_get_contents($location, FILE_BINARY))
{
if ($img = imagecreatefromstring($img)) $err = 0;
}
if ($err)
{
header('Content-Type: text/html');
echo 'htmlbodyp style=font-size:9pxError getting
image.../p/body/html';
}
else
{
header('Content-Type: image/jpeg');
imagejpeg($img);
[PHP-DB] re:looking for SQL documentation tool
Hello guysis there any tool that can create data relation from sql document?I have seen phpmyadmin, but still I am looking for other software to see what they have to offer... Thanks -- Extra details: OSS:Gentoo Linux-2.6.25-r8 profile:x86 Hardware:msi geforce 8600GT asus p5k-se location:/home/muhsin language(s):C/C++,VB,VHDL,bash Typo:40WPM url:http://mambo-tech.net -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] re:looking for SQL documentation tool[solved]
Thanks guys for the input...really appreciated :-) -- Extra details: OSS:Gentoo Linux-2.6.25-r8 profile:x86 Hardware:msi geforce 8600GT asus p5k-se location:/home/muhsin language(s):C/C++,VB,VHDL,bash Typo:40WPM url:http://mambo-tech.net -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP-DB] re:FOREIGN KEY{ERROR:1005/150}
Hello, I have been browsing on mysql manual http://dev.mysql.com/doc/refman/5.1/en/innodb-foreign-key-constraints.html with not much of success.I am trying to put 2 foreign keys(from different external table) on my table, but if I put the 2nd one it fails.here is my table CREATE TABLE pack_accomodation ( id int(16) NOT NULL auto_increment, pack_id int(16) NOT NULL , hotel_id int(16) NOT NULL , PRIMARY KEY (id), INDEX (pack_id), FOREIGN KEY (pack_id) REFERENCES pack(items_no) ON DELETE CASCADE ON UPDATE CASCADE, INDEX (hotel_id), FOREIGN KEY (hotel_id) REFERENCES hotel(items_no) )ENGINE=INNODB; I can get rid of the 2nd foreign key with programming, but I think it should be possible to have them both...I just I cant figure out why it fails with this error: ERROR 1005 (HY000): Can't create table './tabasam/pack_accomodation.frm' (errno: 150) For description of the error http://dev.mysql.com/doc/refman/5.0/en/innodb-error-codes.html Thanks guys, any help would really appreciate it. -- Extra details: OSS:Gentoo Linux-2.6.25-r8 profile:x86 Hardware:msi geforce 8600GT asus p5k-se location:/home/muhsin language(s):C/C++,VB,VHDL,bash Typo:40WPM url:http://mambo-tech.net
Re: [PHP-DB] re:store html codes in text field (mysql)-SOLVED
Chris wrote:
mrfroasty wrote:
Sorry if this has been asked before but I cant seem to find anything
useful via google..
I have a text fields which stores my textarea input from a user, my
design is meant to allow user to submit html codes...but mysql seem to
replace all html tags with something else...
Example:
$title=some text;
$html_code=h1heading 1/h1
INSERT INTO $db_table VALUES(null,'$title','$html_code');
Result in my dB:
1]some text
2]lt;h1gt;heading lt;h1gt;
How can I solve this problem of mysql replacing the html tags.?This
is probably something familiar to webdev, but I am kind of a noob in web
programming...
mysql is 100% not doing it. If you did that manually in mysql, you
would get the right results.
mysql create table test (html text);
Query OK, 0 rows affected (0.01 sec)
mysql insert into test(html) values ('h1heading 1/h1');
Query OK, 1 row affected (0.00 sec)
mysql select * from test;
++
| html |
++
| h1heading 1/h1 |
++
1 row in set (0.00 sec)
You have a htmlspecialchars or htmlentities call between $html_code
being set and where you're doing the insert.
N:B
The only way I can think of is replacing them after pulling them out of
the dB, but I am not sure if this is the way to go...
See http://au.php.net/manual/en/function.html-entity-decode.php
Thanks for the repliesI did have htmlentities in one of my methods,
so html-entity-decode did the job...fixed now... :-)
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[PHP-DB] re:store html codes in text field (mysql)
Sorry if this has been asked before but I cant seem to find anything useful via google.. I have a text fields which stores my textarea input from a user, my design is meant to allow user to submit html codes...but mysql seem to replace all html tags with something else... Example: $title=some text; $html_code=h1heading 1/h1 INSERT INTO $db_table VALUES(null,'$title','$html_code'); Result in my dB: 1]some text 2]lt;h1gt;heading lt;h1gt; How can I solve this problem of mysql replacing the html tags.?This is probably something familiar to webdev, but I am kind of a noob in web programming... Thanks alot for your time... muhsin N:B The only way I can think of is replacing them after pulling them out of the dB, but I am not sure if this is the way to go... -- Extra details: OSS:Gentoo Linux-2.6.25-r8 profile:x86 Hardware:msi geforce 8600GT asus p5k-se location:/home/muhsin language(s):C/C++,VB,VHDL,bash Typo:40WPM url:http://mambo-tech.net
[PHP-DB] re:database tables relations advice
I am quite new to database designs, I have a problem in my design...I can actually feel it, but I am not quite sure if there is a feature in mysql or I have to solve it with programming. Example: CREATE TABLE A ( user_id int(16) NOT NULL auto_increment, ..other datas PRIMARY KEY (user_id) ); CREATE TABLE B ( user_id int(16) NOT NULL auto_increment, ..other datas PRIMARY KEY (contact_id) ); Question: How can I declare that the user_id in my 1st table is related to user_id in the 2nd table...actually I prefer to have it exactly the same user_id in both tablesI think if those 2 entries are the same it will be great, but I am not sure how to achieve this. P:S -Ofcourse I know that I can extract it from TABLE A and save it in TABLE Bbut is that a way to go???Because this issue arise in couple of tables in my data structure that I am tending to use in my application(web). -I also know that its possible to make just 1 big table with lots of columnsbut I read its not a good database design... -please advice, running out of ideas :-( Thanks.. -- Extra details: OSS:Gentoo Linux-2.6.25-r8 profile:x86 Hardware:msi geforce 8600GT asus p5k-se location:/home/muhsin language(s):C/C++,VB,VHDL,bash Typo:40WPM url:http://mambo-tech.net -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] re:database tables relations advice
maruti wrote: hey lemme knoe, how many columns are you planning for? y not put table B columns in table A?? if you are least bothered about data normalizations, simply go the way you want to. userId Name Age Age Sex Occupation Location all the data which has correspondence with userid can be put in a single table.. the case is if you dont've many related tables.. pavan puligandla Microsoft has no beef with OpenSource. 2008/11/27 mrfroasty [EMAIL PROTECTED] mailto:[EMAIL PROTECTED] maruti wrote: hii,, who said table with more no:of columns is a bad database design? coming to your tables, what do you wanna do?? if you want to pull out the data of 'X' userid from table B, then you can use left join. make sure that user ID of table A and userID of table B have same data. to use joins, atleast one column(s) should be the same in both tables. let me know whether userID of table B is a foreign key of UserID of table A or not? normalization in all cases doesnt work. i'm using spreadsheet as my front end, so my tables are not even in the second normal form.. here are some excellent tutorials for joins; http://www.tutorialspoint.com/mysql/mysql-using-joins.htm http://dev.mysql.com/tech-resources/articles/intro-to-normalization.html hope these might help u alot.. pavan puligandla Microsoft has no beef with OpenSource. 2008/11/27 mrfroasty [EMAIL PROTECTED] mailto:[EMAIL PROTECTED] mailto:[EMAIL PROTECTED] mailto:[EMAIL PROTECTED] I am quite new to database designs, I have a problem in my design...I can actually feel it, but I am not quite sure if there is a feature in mysql or I have to solve it with programming. Example: CREATE TABLE A ( user_id int(16) NOT NULL auto_increment, ..other datas PRIMARY KEY (user_id) ); CREATE TABLE B ( user_id int(16) NOT NULL auto_increment, ..other datas PRIMARY KEY (contact_id) ); Question: How can I declare that the user_id in my 1st table is related to user_id in the 2nd table...actually I prefer to have it exactly the same user_id in both tablesI think if those 2 entries are the same it will be great, but I am not sure how to achieve this. P:S -Ofcourse I know that I can extract it from TABLE A and save it in TABLE Bbut is that a way to go???Because this issue arise in couple of tables in my data structure that I am tending to use in my application(web). -I also know that its possible to make just 1 big table with lots of columnsbut I read its not a good database design... -please advice, running out of ideas :-( Thanks.. -- Extra details: OSS:Gentoo Linux-2.6.25-r8 profile:x86 Hardware:msi geforce 8600GT asus p5k-se location:/home/muhsin language(s):C/C++,VB,VHDL,bash Typo:40WPM url:http://mambo-tech.net -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php Quote: make sure that user ID of table A and userID of table B have same data. #That is actually what I am looking for, but I dunno how to achieve that.If I can have those 2 user_id columns with the same data, my problem is technically solved.But as I said earlier I am limited to database skills, its my first application that involves mysql phpdo I need those foreign key stuffs, to have those 2 columns with the same data?? -- Extra details: OSS:Gentoo Linux-2.6.25-r8 profile:x86 Hardware:msi geforce 8600GT asus p5k-sehave location:/home/muhsin language(s):C/C++,VB,VHDL,bash Typo:40WPM url:http://mambo-tech.net That issue arise like 3 times in my data structurehaving all related data in one table I might ended up with a table of ~20 columns, it will be too much and probably bad programming practise.I will have a look over the net about FOREIGN KEYdidnt know what it is, may be its the solution... Thanks for the input -- Extra details: OSS:Gentoo Linux-2.6.25-r8 profile:x86 Hardware:msi geforce 8600GT asus p5k-se location:/home/muhsin language(s):C/C++,VB,VHDL,bash Typo:40WPM url:http://mambo-tech.net -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit
Re: [PHP-DB] re:database tables relations advice {solved}
danaketh wrote: This is solved by using FOREIGN KEY but I'm not sure if MySQL have them present or just planned for some future release. mrfroasty napsal(a): I am quite new to database designs, I have a problem in my design...I can actually feel it, but I am not quite sure if there is a feature in mysql or I have to solve it with programming. Example: CREATE TABLE A ( user_id int(16) NOT NULL auto_increment, ..other datas PRIMARY KEY (user_id) ); CREATE TABLE B ( user_id int(16) NOT NULL auto_increment, ..other datas PRIMARY KEY (contact_id) ); Question: How can I declare that the user_id in my 1st table is related to user_id in the 2nd table...actually I prefer to have it exactly the same user_id in both tablesI think if those 2 entries are the same it will be great, but I am not sure how to achieve this. P:S -Ofcourse I know that I can extract it from TABLE A and save it in TABLE Bbut is that a way to go???Because this issue arise in couple of tables in my data structure that I am tending to use in my application(web). -I also know that its possible to make just 1 big table with lots of columnsbut I read its not a good database design... -please advice, running out of ideas :-( Thanks.. -- S pozdravem Daniel Tlach Freelance webdeveloper Email: [EMAIL PROTECTED] ICQ: 160914875 MSN: [EMAIL PROTECTED] Jabber: [EMAIL PROTECTED] Thanks for the input...after some small research I came across this link http://articles.techrepublic.com.com/5100-10878_11-6035435.html after that I changed my database to something similar to : CREATE TABLE user_profile ( user_id int(16) NOT NULL auto_increment, other datas PRIMARY KEY (user_id) )ENGINE=INNODB; CREATE TABLE user_contact ( user_id int(16) NOT NULL auto_increment, ..other datas INDEX (user_id), FOREIGN KEY (user_id) REFERENCES user_profile (user_id), PRIMARY KEY (user_id) ) ENGINE=INNODB; That I think problem solved for now...thanks alot :-) -- Extra details: OSS:Gentoo Linux-2.6.25-r8 profile:x86 Hardware:msi geforce 8600GT asus p5k-se location:/home/muhsin language(s):C/C++,VB,VHDL,bash Typo:40WPM url:http://mambo-tech.net -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
