[PHP-DB] some data output formatting and grouping question...

2002-12-01 Thread Victor
I just have a fucking mental block; I cannot at all conceive the
necessary syntax to or even the theoretical algorithm that I need, to do
the following:

Consider the following table:

U | X | Y 
--|---|--
me|001|0a
me|002|0a
me|003|0a
me|002|0b
me|003|0b
me|004|0b
..|...|..

then the code says:

SELECT * FROM Y WHERE U = me

So now what?
- remember I do not know the value of Y, so it has to be an automatic
thing; I can't just say ... WHERE U = me AND Y = a.

I want this output:

0a
001
002
003
___ (hr)

0b
002
003
004 

How the hell do I do that? I can't think of the goddamn' syntax!

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[PHP-DB] RE: [PHP] help, array values echoed as Array on loop!

2002-09-02 Thread victor

Ok, if I change $ID_arr[] to $ID_arr I think it gives me what I want.

- Victor  www.argilent.com

-Original Message-
From: Victor [mailto:[EMAIL PROTECTED]] 
Sent: Monday, September 02, 2002 3:39 PM
To: 'PHP'
Subject: [PHP] help, array values echoed as Array on loop!

I have tried both ways to loop through an array and output the data and
verify that the array is an array and I get no erros but I get this
value, which should not be so.


Here I'm checking if it's an array:

if (!is_array($ID_arr)) { # show error if no array
echo '$ID_arr is not an array.';
}

here I'm counting the keys but it only outputs as 1:

$key = count($ID_arr);
echo $key;

here are two loops that do the same thing and they both output Array:

for($i = 0; $i  count($ID_arr); $i++) {
echo $ID_arr[$i];
}

foreach($ID_arr as $ind_picture) {
echo $ind_picture;
}

Why? If it helps, in order to get the array, the values were taken from
a database and exploded from a coma delimited string.

$ID_arr[] = explode(',', $pictures); # make db data into array

This is the string:

15,16,17,18,19

I want each array element to contain 

= 15 
= 16
= 17
etc...

why does it echo as Array?

- Victor  www.argilent.com


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RE: [PHP-DB] RE: [PHP] help, array values echoed as Array on loop!

2002-09-02 Thread victor

Ok, wrong mailing list!

- Victor  www.argilent.com

-Original Message-
From: victor [mailto:[EMAIL PROTECTED]] 
Sent: Monday, September 02, 2002 3:46 PM
To: [EMAIL PROTECTED]
Subject: [PHP-DB] RE: [PHP] help, array values echoed as Array on loop!

Ok, if I change $ID_arr[] to $ID_arr I think it gives me what I want.

- Victor  www.argilent.com

-Original Message-
From: Victor [mailto:[EMAIL PROTECTED]] 
Sent: Monday, September 02, 2002 3:39 PM
To: 'PHP'
Subject: [PHP] help, array values echoed as Array on loop!

I have tried both ways to loop through an array and output the data and
verify that the array is an array and I get no erros but I get this
value, which should not be so.


Here I'm checking if it's an array:

if (!is_array($ID_arr)) { # show error if no array
echo '$ID_arr is not an array.';
}

here I'm counting the keys but it only outputs as 1:

$key = count($ID_arr);
echo $key;

here are two loops that do the same thing and they both output Array:

for($i = 0; $i  count($ID_arr); $i++) {
echo $ID_arr[$i];
}

foreach($ID_arr as $ind_picture) {
echo $ind_picture;
}

Why? If it helps, in order to get the array, the values were taken from
a database and exploded from a coma delimited string.

$ID_arr[] = explode(',', $pictures); # make db data into array

This is the string:

15,16,17,18,19

I want each array element to contain 

= 15 
= 16
= 17
etc...

why does it echo as Array?

- Victor  www.argilent.com


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RE: [PHP-DB] How to pass multiple checkbox values thru form??

2002-08-31 Thread victor

I'm working on the same problem but I need to read the code, not write
it:, here are a few links and my code if you might help me in return:

http://www.experts-exchange.com/Web/Web_Languages/PHP/Q_20117420.html

my code:

mysql_db(); # connects to mysql

for($i = 0; $i  sizeof($check); $i++) {
# echo $i;
# echo 'p';
# $data = $check[$i];
$sql = (SELECT * FROM kodak_user_pictures WHERE ID = '$check[$i]');
$result = mysql_query($sql);
$row = mysql_fetch_array($result);
# $row = mysql_fetch_array($db_data);
$db_ID = $row[ID];
$db_picture_name = $row[picture_name];
echo $db_ID;
echo 'p';
echo $db_picture_name;
echo 'p';
echo $ID;
echo 'p';
echo $picture_name;
echo 'p';
echo $result;
}

so many echoes because I'm trying to figure out what works and what
doesn't.

- Victor  www.argilent.com

-Original Message-
From: Smita Manohar [mailto:[EMAIL PROTECTED]] 
Sent: Friday, August 30, 2002 12:19 AM
To: [EMAIL PROTECTED]
Subject: [PHP-DB] How to pass multiple checkbox values thru form??

hii
i have one form in which i print records from mysql database. while 
displyaing those records i display one checkbox with each record. i want
the 
user should select the checkbox corresponding to the record which s/he
wants 
to delete.

i display those records after running one query. hence each time no.of 
records are diff. so its difficult to hard code names for check boxes.
for 
name attribute in input type=checkbox tag, i define one array. having
same 
name as the key field in the table. and value for which is also set 
dynamically.

FORM NAME = act_qmd_subj_frm METHOD = POST ACTION = 
confirm_delete.php

while ($row = mysql_fetch_array($result))
 {

..
 echo tr;

   //call function to display the contents of $row in table
print_entry($row,subj_id,subj_name,subj_desc);


print   td valign=top align=centerinput type=checkbox  
name=\subj_id[]\ value=\.$row[subj_id].\ Yes, delete entry 
#.$row[subj_id]./td\n;

  ...

 }

 INPUT TYPE=submit NAME=del_but VALUE=Delete nbsp nbsp
 INPUT TYPE=submit NAME=modify_but VALUE=Modify nbsp nbsp
 INPUT TYPE=reset NAME=clear_but VALUE=Clear nbsp nbsp

/FORM

when i submit the form to confirm_delete.php i run one code there to
print 
the array subj_id[]  which is supposed to contain values of the
checkboxes 
which are selected to delete or to modify. but the array subj_id[]
contains 
no value at all. echo count($subj_id) gives 0.

is there any other way to pass multiple checkbox values from the form???

i got the above trick from the book MySQL/PHP Database Applications
(By, 
Jay Grrenspan and Brad Bulger) in one script they have passed checkbox
value 
thru array by this way, and its working fine.

can anyone PLS figure out what wrong im doing???

thnx and regds,
smita.



_
MSN Photos is the easiest way to share and print your photos: 
http://photos.msn.com/support/worldwide.aspx


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[PHP-DB] newest entry in db

2002-08-31 Thread Victor

How can I use php to get the newest entry from  mysql database? Ie, if I
make a timestamp and then I want to retrieve the last timestamp I made
how do I go about doing it? Any php or mysql documentation?

- Victor  www.argilent.com


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[PHP-DB] why do i get this error please tell me?

2002-08-31 Thread Victor

for($i = 0; $i  sizeof($check); $i++) { # start repating query
# turn pictures in order delete capability off
mysql_query(UPDATE kodak_user_pictures 
SET order=1 
WHERE ID='$check[$i]') # turn off pictures
or die ('Unable to turn bit off '.mysql_error());
} # end repeat

You have an error in your SQL syntax near 'order=1 WHERE ID='2'' at line
2

- Victor  www.argilent.com


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[PHP-DB] RE: [PHP] why do i get this error please tell me?

2002-08-31 Thread victor

Yep, figured it just now, thanks anyway, ahhh.. You'd thing they put
reserved names right besides the damn mysql command in the manual. Alas
it shall not be so.

- Victor  www.argilent.com

-Original Message-
From: Chris Knipe [mailto:[EMAIL PROTECTED]] 
Sent: Saturday, August 31, 2002 1:30 PM
To: [EMAIL PROTECTED]; [EMAIL PROTECTED]; [EMAIL PROTECTED]
Subject: Re: [PHP] why do i get this error please tell me?

 
 You have an error in your SQL syntax near 'order=1 WHERE ID='2'' at
line
 2

ORDER is a reserved word in MySQL.

Change the query and escape order aswell

'order'='1' WHERE ID='2'

Or, rename the order column to something else.



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RE: [PHP-DB] RE: [PHP] why do i get this error please tell me?

2002-08-31 Thread victor

I meant besides the UPDATE or SELECT or any filed that those words might
interfere with...

- Victor  www.argilent.com

-Original Message-
From: Mark Charette [mailto:[EMAIL PROTECTED]] 
Sent: Saturday, August 31, 2002 2:18 PM
To: [EMAIL PROTECTED]; [EMAIL PROTECTED]
Subject: [PHP-DB] RE: [PHP] why do i get this error please tell me?

Ahem. Why not check out the MySQL docs for reserved words (they _are_
right
there ...):

http://www.mysql.com/doc/en/Reserved_words.html

PHP Docs are for PHP. MySQL Docs are for MySQL. PHP != MySQL.

-Original Message-
From: victor [mailto:[EMAIL PROTECTED]]
Sent: Saturday, August 31, 2002 1:35 PM
To: 'Chris Knipe'; [EMAIL PROTECTED]; [EMAIL PROTECTED];
[EMAIL PROTECTED]
Subject: RE: [PHP] why do i get this error please tell me?


Yep, figured it just now, thanks anyway, ahhh.. You'd thing they put
reserved names right besides the damn mysql command in the manual. Alas
it shall not be so.


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[PHP-DB] List

2001-12-14 Thread Victor Bogdan C.

list



Re: [PHP-DB] Passing parameters to a PHP file.

2001-09-13 Thread Victor Espina

Thanks Leo, i solved the problem using $HTTP_GET_VARS[].

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http://mitrompo.com/vespina
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Leo G. Divinagracia III [EMAIL PROTECTED] wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
 u quick question, does VAR1 contain a value before the call???

 could be null to begin with...

 Victor Espina wrote:
 
  I want to call a PHP file with some parameters. I tried this sintax:
 
  HREF=MyPage.PHP?Var1=Value1
 
  But i don't seem to be receiving any value for Var1. I tested it with:
 
  print Var1: $Var1;
 
  and the output is Var1:
 
  What i'm missing here?
 
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  http://mitrompo.com/vespina
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[PHP-DB] ODBC connection under Win32 + Apache + SQL Server

2001-09-11 Thread Victor Espina

Hi, i'm new using PHP i'm trying to run some basic PHP scripts to retrieve a
show data coming from a SQL Server database. The problem is that when i try
to run this:

$conn=odbc_connect(MQIS,sa,);

PHP returns the following warning:

Warning: SQL error: [Microsoft][ODBC Driver Manager] Data source name not
found and no default driver specified

I test the DSN with VFP using:

SQLStringConnect(dsn=MQIS;usr=sa;pwd=;)

and it works pretty fine. ¿What could be the problem here?

TIA

Victor

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Re[2]: [PHP-DB] OCI_DEFAULT

2001-04-19 Thread Victor Foitzik

Hello Johannes,
on 19.04.2001 you wrote:

 hi,

 OCIExecute() executes a previously parsed statement. (see OCIParse(). The
 optional mode allows you to specify the execution-mode (default is
 OCI_COMMIT_ON_SUCCESS). If you don't want statements to be committed
 automaticly specify OCI_DEFAULT as your mode.

that's right, but had anyone of you the same problem i had ? consider
the following situation: using persistent connections and specifying
OCI_DEFAULT works quite okay, but subsequent calls to OCIExecute
remain in the OCI_DEFAULT state, whether or not you specify
OCI_COMMIT_ON_SUCCESS. this means that executes made with this call
remain uncommitted. Even more, scripts that reuse the connection are
not able to do normal queries with this connection.

Am I doing something really nasty, or is this just a feature i don't
understand ? Tested PHP versions were 4.0.3pl and 4.0.4pl1 both on
FreeBSD and Debian ...

Hope somebody knows about ...

Victor



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Re: [PHP-DB] Advice On Building Dynamic MySQL Queries

2001-04-19 Thread Victor Foitzik

Hello JD,
on 19.04.2001 you wrote:

 I am building a query from a search form. This is the code I have now:

 if (!empty($whereclause))
  {
 $whereclause=urldecode($whereclause);
  $whereclause=stripslashes($whereclause);
  }

  extract($HTTP_POST_VARS);

  if (!empty($Price))
  {
 if(empty($whereclause))

--- blah blah blah ---

 It Just became apparent that I am going to need to add a whole bunch more
 search criteria.. Does anyone have any advice/suggestions for getting rid of
 all those if statements?

 JD

what about using a foreach statement and going through all the
variables you need like this ?

$myvars = array('Price', 'Stuff', 'Thing');
foreach ($myvars as $varname) {
if (!empty($$varname)) {
   // do funky stuff here
}
}

HTH
Victor



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Re[2]: [PHP-DB] Display data begin with A

2001-04-08 Thread Victor Foitzik

Hi,

if you're using MySQL, the simpliest method is using RLIKE

SELECT stuff FROM table WHERE stuff RLIKE '^[0-9]+';

see
http://www.mysql.com/doc/S/t/String_comparison_functions.html
http://www.mysql.com/doc/R/e/Regexp.html
for more info

HTH
Victor

 Okay it's working now..
 How if I want to display all the data begin with NUMBERS. like "1,2,3,...,0"



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Re: [PHP-DB] newbie question

2001-02-04 Thread Victor Foitzik

Hi Lisa,

Can search engines index any HTML pages that have .php as its extension (any
.php pages without a '?' or '' in the URL) ? For example:
http://www.blablabla.com/blabla.php

Thanks,
Lisa E

yes they can, but my experience is, that most search engine robots do _not_ 
index pages ending in .php and .php3 due to their dynamic nature (please 
correct me or give me a hint how to change this). We had to change the 
extensions to .html to avoid being not indexed by search engines.

Hope this helps
Victor


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