[PHP-DB] ummm i am confused

2004-06-26 Thread water_foul
i get the following error:
Parse error: parse error, unexpected ';' in
C:\Inetpub\localroot\aichlmayr.net\sites\aaron\module\runescape\runerunner\s
ervices.php on line 4
from the following code:
?php
//Database Querys
$dbconn = mysql_connect($dbHost , $dbName , $dbPassword)
   or die(Could not connect to server, incorrect username,
password or host : .mysql_error();
$connection=Mysql_connect($dbHost , $dbName , $dbPassword)
//function zone

//creates table
function tablecreate($num,$connection){
$items=mysql_query('SELECT Row_Decription, Required_Items, Misc FROM
RuneRunner WHERE ID = $num',$connection);
$item=mysql_fetch_array($items);
$users1=mysql_query('SELECT RuneRunner.rune, RuneRunnerprices.price FROM
RuneRunner INNER JOIN RuneRunnerprices ON RuneRunner.User_Id =
RuneRunnerprices.User_Id WHERE RuneRunnerprices.ID = $num AND
RuneRunnerPrices.user_id = 1',$connection);
$user1=mysql_fetch_array($users1);
$users2=mysql_query('SELECT RuneRunner.rune, RuneRunnerprices.price FROM
RuneRunner INNER JOIN RuneRunnerprices ON RuneRunner.User_Id =
RuneRunnerprices.User_Id WHERE RuneRunnerprices.ID = $num AND
RuneRunnerPrices.user_id = 2',$connection);
$user2=mysql_fetch_array($users2);
print ('trtd' . $item[1] . '/tdtdimg
src=module/runescape/Runerunner/' . $user1[1] . '.gif' . $user1[2].
'brimg src=module/runescape/Runerunner/' . $user2[1] . '.gif' .
$user2[2]. '/tdtd' . $item[2] . '/td/tr');
};

//this function is called by another
function picscreate($Rune,$username,$num){
print('img src=module/runescape/Runerunner/' . $Rune . '.gif' . $username
. 'br');
${'' . $num . ''}=$Rune;
};

//gets data form database and sends it to pics()
Function picspprep($usernum,$connection){
$pict=mysql_query('SELECT username,rune FROM RuneRunner WHERE User_ID =
$usernum',$connection);
$pic=mysql_fetch_array($pict);
picscreate($pic[1],$pic[2],$usernum);
};
?
iubWelcome to the RuneRunners Runescape service page/b/u/ibr
iThe currrent Runerunners are:br
!--begin Database Data--
?php
picspprep(1,$connection);
picspprep(2,$connection);
?
!--end Database Data--
hr
To order a service, click on the running rune below that matches the one on
the player you want to buy from above
/i
table cellspacing=2 cellpadding=2 border=1
tr
tdService/td
tdPrices/td
tdRequired Items/td
/tr
!--loop database data to create table--
?php
$id=1;
while($id=296){
tablecreate($id,$connection);
$id=$id+1;
};
?
!-- end loop --
/table

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Re: [PHP-DB] ummm i am confused

2004-06-26 Thread water_foul
oh... duh why didn't i see that
Mikhail U. Petrov [EMAIL PROTECTED] wrote in message
news:[EMAIL PROTECTED]
 Hi!
 Insert one more bracket!
 ?php
 //Database Querys
 $dbconn = mysql_connect($dbHost , $dbName , $dbPassword)
or die(Could not connect to server, incorrect username,
 password or host : .mysql_error()); -this bracket!!!
 $connection=Mysql_connect($dbHost , $dbName , $dbPassword)



 Saturday, June 26, 2004, 7:23:30 PM, water_foul wrote:

 w i get the following error:
 w Parse error: parse error, unexpected ';' in
 w
C:\Inetpub\localroot\aichlmayr.net\sites\aaron\module\runescape\runerunner\s
 w ervices.php on line 4
 w from the following code:
 w ?php
 w //Database Querys
 w $dbconn = mysql_connect($dbHost , $dbName , $dbPassword)
 wor die(Could not connect to server, incorrect username,
 w password or host : .mysql_error();
 w $connection=Mysql_connect($dbHost , $dbName , $dbPassword)
 w //function zone

 w //creates table
 w function tablecreate($num,$connection){
 w $items=mysql_query('SELECT Row_Decription, Required_Items, Misc
FROM
 w RuneRunner WHERE ID = $num',$connection);
 w $item=mysql_fetch_array($items);
 w $users1=mysql_query('SELECT RuneRunner.rune, RuneRunnerprices.price
FROM
 w RuneRunner INNER JOIN RuneRunnerprices ON RuneRunner.User_Id =
 w RuneRunnerprices.User_Id WHERE RuneRunnerprices.ID = $num AND
 w RuneRunnerPrices.user_id = 1',$connection);
 w $user1=mysql_fetch_array($users1);
 w $users2=mysql_query('SELECT RuneRunner.rune, RuneRunnerprices.price
FROM
 w RuneRunner INNER JOIN RuneRunnerprices ON RuneRunner.User_Id =
 w RuneRunnerprices.User_Id WHERE RuneRunnerprices.ID = $num AND
 w RuneRunnerPrices.user_id = 2',$connection);
 w $user2=mysql_fetch_array($users2);
 w print ('trtd' . $item[1] . '/tdtdimg
 w src=module/runescape/Runerunner/' . $user1[1] . '.gif' . $user1[2].
 w 'brimg src=module/runescape/Runerunner/' . $user2[1] . '.gif' .
 w $user2[2]. '/tdtd' . $item[2] . '/td/tr');
 w };

 w //this function is called by another
 w function picscreate($Rune,$username,$num){
 w print('img src=module/runescape/Runerunner/' . $Rune . '.gif' .
$username
 w . 'br');
 w ${'' . $num . ''}=$Rune;
 w };

 w //gets data form database and sends it to pics()
 w Function picspprep($usernum,$connection){
 w $pict=mysql_query('SELECT username,rune FROM RuneRunner WHERE User_ID =
 w $usernum',$connection);
 w $pic=mysql_fetch_array($pict);
 w picscreate($pic[1],$pic[2],$usernum);
 w };
 ?
 w iubWelcome to the RuneRunners Runescape service
page/b/u/ibr
 w iThe currrent Runerunners are:br
 w !--begin Database Data--
 w ?php
 w picspprep(1,$connection);
 w picspprep(2,$connection);
 ?
 w !--end Database Data--
 w hr
 w To order a service, click on the running rune below that matches the
one on
 w the player you want to buy from above
 w /i
 w table cellspacing=2 cellpadding=2 border=1
 w tr
 w tdService/td
 w tdPrices/td
 w tdRequired Items/td
 w /tr
 w !--loop database data to create table--
 w ?php
 w $id=1;
 w while($id=296){
 w tablecreate($id,$connection);
 w $id=$id+1;
 w };
 ?
 w !-- end loop --
 w /table



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 Best regards,
 Mikhail U. Petrov
 mailto:[EMAIL PROTECTED]

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[PHP-DB] access denied

2004-06-26 Thread water_foul
i get this error:
Warning: Access denied for user: '[EMAIL PROTECTED]' (Using
password: YES) in
C:\Inetpub\localroot\aichlmayr.net\sites\aaron\module\runescape\runerunner\s
ervices.php on line 3
and the code up to line 3 is:
?php
//Database Querys
$connection=Mysql_connect($dbHost , $dbName , $dbPassword);

i have included this in another script that sets $dbHost, $dbName and,
$dbPassword to the correct things to connect to the db

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[PHP-DB] Re: access denied

2004-06-26 Thread water_foul
oh... one request, no replying to sender
Water_foul [EMAIL PROTECTED] wrote in message
news:[EMAIL PROTECTED]
 i get this error:
 Warning: Access denied for user: '[EMAIL PROTECTED]' (Using
 password: YES) in

C:\Inetpub\localroot\aichlmayr.net\sites\aaron\module\runescape\runerunner\s
 ervices.php on line 3
 and the code up to line 3 is:
 ?php
 //Database Querys
 $connection=Mysql_connect($dbHost , $dbName , $dbPassword);
 
 i have included this in another script that sets $dbHost, $dbName and,
 $dbPassword to the correct things to connect to the db

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Re: [PHP-DB] access denied

2004-06-26 Thread water_foul
I did set the veriables just in another script that includes this swcript
Mikhail U. Petrov [EMAIL PROTECTED] wrote in message
news:[EMAIL PROTECTED]
 Hi!
 I think you not set this variables. Try to read your full errorlog but
 not only one part.


 Saturday, June 26, 2004, 7:37:36 PM, water_foul wrote:

 w i get this error:
 w Warning: Access denied for user: '[EMAIL PROTECTED]' (Using
 w password: YES) in
 w
C:\Inetpub\localroot\aichlmayr.net\sites\aaron\module\runescape\runerunner\s
 w ervices.php on line 3
 w and the code up to line 3 is:
 w ?php
 w //Database Querys
 w $connection=Mysql_connect($dbHost , $dbName , $dbPassword);
 w 
 w i have included this in another script that sets $dbHost, $dbName and,
 w $dbPassword to the correct things to connect to the db



 -- 
 Best regards,
 Mikhail U. Petrov
 mailto:[EMAIL PROTECTED]

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[PHP-DB] problem....

2004-06-22 Thread water_foul
why doesn't this work:
$pic=mysql_query('SELECT Rune, username FROM RuneRunner
RuneRunner_1 WHERE (User_ID = 3)',$connection);
$pic=mysql_fetch_array($pic);

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Re: [PHP-DB] problem....

2004-06-22 Thread water_foul
I tried that it didn't work
Cole S. Ashcraft [EMAIL PROTECTED] wrote in message
news:[EMAIL PROTECTED]
 Just from looking at it, it seems to be because you are redefining a
 variable, which destroys it, then calling for a mysql resource that has
 been destroyed. What is the error?

 I can't gaurantee that that is what is happening.

 Cole

  why doesn't this work:
  $pic=mysql_query('SELECT Rune, username FROM RuneRunner
  RuneRunner_1 WHERE (User_ID = 3)',$connection);
  $pic=mysql_fetch_array($pic);
 
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Re: [PHP-DB] problem....

2004-06-22 Thread water_foul
I checked em all they were right
Daniel Clark [EMAIL PROTECTED] wrote in message
news:[EMAIL PROTECTED]
 Sounds like it doesn't like your SQL statement.  Perhaps a field or table
 name is incorrect?

  Warning: mysql_fetch_array(): supplied argument is not a valid MySQL
  result
  resource in ...
  Daniel Clark [EMAIL PROTECTED] wrote in message
  news:[EMAIL PROTECTED]
  What error are you getting?
 
   why doesn't this work:
   $pic=mysql_query('SELECT Rune, username FROM RuneRunner
   RuneRunner_1 WHERE (User_ID = 3)',$connection);
   $pic=mysql_fetch_array($pic);

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Re: [PHP-DB] problem....

2004-06-22 Thread water_foul
i fixed those things and it didn't fix it :( :( :( :( :( :( :( :( :( is
there a icq chatroom for php?)
Shahmat Bin Dahlan [EMAIL PROTECTED] wrote in message
news:[EMAIL PROTECTED]
 Your SQL statement:

 'SELECT Rune, username FROM RuneRunner
 RuneRunner_1 WHERE (User_ID = 3)'

 What is RuneRunner and RuneRunner_1? Are these two different tables.
 If it is, you might want to separate them with a comma.

 Why not try getting rid of the brackets surrounding User_ID=3? And
 also wrap single quotes around the digit 3.


 - Original Message -
 From: water_foul [EMAIL PROTECTED]
 Date: Wednesday, June 23, 2004 8:58 am
 Subject: Re: [PHP-DB] problem

  I checked em all they were right
  Daniel Clark [EMAIL PROTECTED] wrote in message
  news:[EMAIL PROTECTED]
   Sounds like it doesn't like your SQL statement.  Perhaps a field
  or table
   name is incorrect?
  
Warning: mysql_fetch_array(): supplied argument is not a valid
  MySQL  result
resource in ...
Daniel Clark [EMAIL PROTECTED] wrote in message
   
  news:[EMAIL PROTECTED]
  What error are you getting?
   
 why doesn't this work:
 $pic=mysql_query('SELECT Rune, username FROM
  RuneRunner   RuneRunner_1 WHERE (User_ID = 3)',$connection);
 $pic=mysql_fetch_array($pic);
 
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[PHP-DB] Hi I am new

2004-04-23 Thread water_foul
I am new to databases and php and I was wondering if any one would point me
to a good guide
anything would help :)
thanks in advance,
water_foul

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