Here's an example (snip) from a var_dump of that
$BuildPerUniqueDateArray:
(note that the 'aweber_7solar_aw' table does NOT have a record for
the
date '2009-07-28', so I would expect to see that 1 to be a 0
there.)
If a table doesn't have a record for a given date, I wouldn't expect
to
take a look at this:
http://otn.oracle.com/oramag/oracle/04-mar/o24asktom.html
and search for the Analytics to the Rescue example. Instead of 3 seconds
you want 1800 and instead of sum you want count.Don't forget to group by
ip,of course... And you're done. No need for an extra table.
Hope
Whatabout creating a table containing online users,
where you log every activity with IP, BrowserSession and Timestamp.
You also create a table to track the accual unique visits.
So my logic to solve it :
Update the online table like this (Some rough coding below, not tested at
all, read the
I know how to get the results for the total number of records
select count(*) from $table
but how do I put them into a variable for me to use later???
David Robley [EMAIL PROTECTED] wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
In article [EMAIL PROTECTED],
[EMAIL PROTECTED]
In article [EMAIL PROTECTED],
[EMAIL PROTECTED] says...
I know how to get the results for the total number of records
select count(*) from $table
but how do I put them into a variable for me to use later???
David Robley [EMAIL PROTECTED] wrote in message
[EMAIL PROTECTED]">news:[EMAIL
What is the Aliases used for???
Aliases. SELECT COUNT(*) AS howmany FROM table
Then use the variable $howmany
--
David Robley
Temporary Kiwi!
Quod subigo farinam
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In article [EMAIL PROTECTED],
[EMAIL PROTECTED] says...
What is the Aliases used for???
Aliases. SELECT COUNT(*) AS howmany FROM table
Then use the variable $howmany
At this stage I refer you to The Fine (mysql) Manual - or anything on the
SQL language.
--
David Robley
Temporary
Hi Barry!
you can do it like this for example:
$query = SELECT * FROM artist WHERE artist_name LIKE 'b%' ORDER BY artist
ASC;
$count = mysql_query(SELECT COUNT(artist) AS count FROM artist WHERE
artist_name LIKE 'b%',$db);
$x = mysql_fetch_array($count);
$result = mysql_query($query) or
Thank you everyone. The "COUNT(*) AS c" worked great.
---Original Message---
From: Kai Voigt
Date: Friday, 25
January 2002 11:11:06 a.
To: Barry Rumsey
Cc: [EMAIL PROTECTED]
Subject: Re:
Count(*)
