Beyond that excellent answer, this is exactly the kind of situation where
transactions would be helpful (and in a lot of cases, mission critical).
So an expanded quasi-pseudocode rendition of olinux's answer could be:
$result_bt = mysql_query('[whatever it takes to begin a transaction]');
I'm trying to insert data into two separate tables using 1 INSERT. The code
below represents a first crack at it, but I can't seem to figure out how to
get this to work properly.
Thanks.
Steve
?
$db_name=testDB;
$table_name1 = my_contacts;
$table_name2= company;
$connection = @mysql_connect
Not possible.
do this $result_1 = mysql_query($sql1) or die('Insert 1 failed');
do this $result_2 = mysql_query($sql2) or die('Insert 2 failed');
olinux
-Original Message-
From: Steve Fitzgerald [mailto:[EMAIL PROTECTED]]
I'm trying to insert data into two separate tables using 1
