Re: [PHP-DB] DB will INSERT wont UPDATE..error in code?

2004-10-12 Thread Matthew Kiehne
"Jason Wong" <[EMAIL PROTECTED]> wrote in message news:[EMAIL PROTECTED] > If you look up the manual entry for UPDATE, you'll find that you're missing > the commas separating the columns. > > -- > Jason Wong -> Gremlins Associates -> www.gremlins.biz > Open Source Software Systems Integrators > * W

Re: [PHP-DB] DB will INSERT wont UPDATE..error in code?

2004-10-12 Thread Jason Wong
Please do not top-post. On Wednesday 13 October 2004 10:26, Matthew Kiehne wrote: > sorry this is the output i meant to post > SQL statement = UPDATE badges SET staff = '1' ttlpst = '1' mnthpst = '1' > ttlicon = '/trophies' mnthicon = '/ribbons' WHERE fid = 61 > > and this is the error i getye

Re: [PHP-DB] DB will INSERT wont UPDATE..error in code?

2004-10-12 Thread Matthew Kiehne
sorry this is the output i meant to post SQL statement = UPDATE badges SET staff = '1' ttlpst = '1' mnthpst = '1' ttlicon = '/trophies' mnthicon = '/ribbons' WHERE fid = 61 and this is the error i getyet i still cant for the life of me find a problem Update query = UPDATE badges SET staff = '

Re: [PHP-DB] DB will INSERT wont UPDATE..error in code?

2004-10-12 Thread Jason Wong
On Wednesday 13 October 2004 04:08, Matthew Kiehne wrote: > database, however when i want to update the SQL query returns an output > like this 'SQL statement = UPDATE badges > (staff,ttlpst,mnthpst,ttlicon,mnthicon) VALUES > ('1','1','1','/ribbons','/ribbons') WHERE fid=2' but when i try to pull

RE: [PHP-DB] DB will INSERT wont UPDATE..error in code?

2004-10-12 Thread Graham Cossey
pdated!\n"; } } The echos will at least show the SQL being executed which could give a clue to the problem. You could even just set the $sql within the if...else... and use the same mysql_query($sql) for both instances: if (condition1) { $sql = "query statement 1"; }

[PHP-DB] DB will INSERT wont UPDATE..error in code?

2004-10-12 Thread Matthew Kiehne
forgive the poor structure of my code, im pretty new at this and havent figured out exactly what it should be formed like to look its best, anyway whenever i run this code it works on inserting new information into the database, however when i want to update the SQL query returns an output like thi