Hello,
I have a query on a page that used to work fine, but is now generating an
error.
I assume that the version of php or mysql was updated on the webhost server
or something like that?
Here is the query:
select count(places_data.place_id) as areacount, boroughs.borough_name as
boroname,
you have renamed places_data table to 'a'
2011/1/13 Harvey har...@harveyk.com:
Hello,
I have a query on a page that used to work fine, but is now generating an
error.
I assume that the version of php or mysql was updated on the webhost server
or something like that?
Here is the query:
Thanks, I got it working now, had to use the a/b/c thing a few times
-Original Message-
From: jose [mailto:jojap...@gmail.com]
Sent: Thursday, January 13, 2011 9:52 AM
Cc: php-db@lists.php.net
Subject: Re: [PHP-DB] Query syntax error?
you have renamed places_data table to 'a'
2011/1
$query=SELECT * FROM table WHERE listing_type LIKE '%$listing_type%' AND
listing_approved = '1' OR listing_approved = '2' ORDER BY name ASC;
My question is how can I search for records where listing_approved has a
value of either 1 or 2 (while in the same search I am searching for
%'
AND listing_approved IN ('1', '2')
ORDER BY name ASC
Good luck!
-TG
- Original Message -
From: ron.php [EMAIL PROTECTED]
To: php-db@lists.php.net
Date: Sat, 15 Sep 2007 15:04:59 -0400
Subject: [PHP-DB] Query syntax
$query=SELECT * FROM table WHERE listing_type LIKE '%$listing_type
