Ok here is my question... I have a form that reads the contents of a
directory, places the resulting files into a select box within a form for
further processing, code is as follows:
?php
$dir_name = /virtual/path/to/images/directory/;
$dir = opendir($dir_name);
$file_list .= pFORM METHOD=\post\ ACTION=\index_done.php3\
SELECT NAME=\files\OPTION VALUE=\--\
NAME=\--\--/OPTION;
while ($file_name = readdir($dir)) {
if (($file_name != .) ($file_name !=..)) {
$file_list .= OPTION VALUE=\$file_name\
NAME=\$file_name\$file_name/OPTION;
}
}
$file_list .= /SELECTbrbrINPUT TYPE=\submit\ NAME=\submit\
VALUE=\select\/FORM/p;
closedir($dir);
?
This portion works great... now on index_done.php3 it takes the resulting
selection and places it into the db table, code is as follows:
?php
$file_var = http://localhost/images/;;
$db_name = database;
$table_name = image_path;
$connection = mysql_connect(localhost, user_name, password) or die
(Could not connect to database. Please try again later.);
$db = mysql_select_db($db_name,$connection) or die (Could not select
database table. Please try again later.);
$sql = UPDATE $table_name SET image01_t=\$file_var$files\;
$result = mysql_query($sql, $connection) or die (Could not execute query.
Please try again later.);
?
What I need to know is if there is a way to create an if statement that
would either update or not update a selected field in the database. Below
is a piece I would assume would work however I am not sure of the mysql
command to not update anything. Any help would be great.
Jas
if( $file_name = '--' ) $sql = dont update table;
else $sql = UPDATE $table_name SET image01_t = \$files\;
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