RE: [PHP-DB] Unsure of how to perform query and results..

2003-11-21 Thread Aaron Wolski
Hi John,

Thanks for taking the time to respond.

What am I trying to do?

Well...I am trying to build a mailing list of previous customers WHO
purchased product_id 1 but not product_id 14.

I have the product items (id's) stored in the CartTable and I have
customer info stored in the OrderTable.

Using the same column of cart_id in both CartTable and OrderTable I am
able to reference which cart items (id's) belong to each record in the
OrderTable.

What I did originally (that didn't work) was to select all records in
the CartTable that matched product_id=1 and product_id!=14 then I used
that information to reference against the OrderTable to grab the
customer information I needed.

The problem with my logic is that I did not take into account those who
purchased one of the product_id's on ONE purchase and then came back the
next day, week, year, etc and made another purchase for the other
product_id which.

I NEED to make sure that a customer HAS purchased product_id=1 and NOT
product_id=14 at ANY time, regardless of a single or multiple orders.

Does this make any sense? *sigh*

Thanks again.

Aaron

 -Original Message-
 From: CPT John W. Holmes [mailto:[EMAIL PROTECTED]
 Sent: November 20, 2003 4:34 PM
 To: Aaron Wolski; [EMAIL PROTECTED]
 Subject: Re: [PHP-DB] Unsure of how to perform query and results..
 
 From: Aaron Wolski [EMAIL PROTECTED]
 
  I have data in a Db that looks something like:
 
  14,[EMAIL PROTECTED],Andrew,Smith
  1,[EMAIL PROTECTED],Andrew,Smith
  14,[EMAIL PROTECTED],Barbara,Richardson
  1,[EMAIL PROTECTED],Barbara,Richardson
 
  The number represents a product_id that was purchased by the
customer in
  question. As you can see from this example.. I have a two customers
who
  purchased two different products.
 
  What I NEED to do is have one entry for each customer but with both
  their product_id in the same result. For example:
 
  14,1,[EMAIL PROTECTED],Andrew,Smith
 
  ANY clue how I could go about getting this to work? I'm very
desperate
  and running out of time :-(
 
 Sorry, it's not going to happen and besides, there isn't any reason
you
 should need to return a row like that. How about you tell us what
you're
 actually trying to do and someone can help you clean up your method...
 
 ---John Holmes...
 
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[PHP-DB] Unsure of how to perform query and results..

2003-11-20 Thread Aaron Wolski
Hi Guys,
 
I have data in a Db that looks something like:
 
14,[EMAIL PROTECTED],Andrew,Smith
1,[EMAIL PROTECTED],Andrew,Smith
14,[EMAIL PROTECTED],Barbara,Richardson
1,[EMAIL PROTECTED],Barbara,Richardson
 
The number represents a product_id that was purchased by the customer in
question. As you can see from this example.. I have a two customers who
purchased two different products.
 
What I NEED to do is have one entry for each customer but with both
their product_id in the same result. For example:
 
14,1,[EMAIL PROTECTED],Andrew,Smith
 
ANY clue how I could go about getting this to work? I'm very desperate
and running out of time :-(
 
Thanks so much!
 
Aaron
 
 


Re: [PHP-DB] Unsure of how to perform query and results..

2003-11-20 Thread CPT John W. Holmes
From: Aaron Wolski [EMAIL PROTECTED]

 I have data in a Db that looks something like:

 14,[EMAIL PROTECTED],Andrew,Smith
 1,[EMAIL PROTECTED],Andrew,Smith
 14,[EMAIL PROTECTED],Barbara,Richardson
 1,[EMAIL PROTECTED],Barbara,Richardson

 The number represents a product_id that was purchased by the customer in
 question. As you can see from this example.. I have a two customers who
 purchased two different products.

 What I NEED to do is have one entry for each customer but with both
 their product_id in the same result. For example:

 14,1,[EMAIL PROTECTED],Andrew,Smith

 ANY clue how I could go about getting this to work? I'm very desperate
 and running out of time :-(

Sorry, it's not going to happen and besides, there isn't any reason you
should need to return a row like that. How about you tell us what you're
actually trying to do and someone can help you clean up your method...

---John Holmes...

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