RE: [PHP-DB] PHP and table/view names with '$'
I find that using single quotes rather than double quotes prevents variable substitution. I don't know if this is an undocumented feature, as the documentation says that both have the same functionality. Regards, Neil -Original Message- From: Mark Casson [mailto:confu...@icube.co.uk] Sent: 23 April 2009 11:04 To: php-db@lists.php.net Subject: [PHP-DB] PHP and table/view names with '$' Hi, I am trying to access some of the v$ views using php on iis, with admin privileges. However, using: $stmt = OCIParse($conn, SELECT * FROM v$sql); gives me this error: PHP Notice: undefined variable: sql . . . Is there a way around this? Thanks Mark -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] PHP and table/view names with '$'
What if you use back-quotes `` around the table/view name? $stmt = OCIParse($conn, SELECT * FROM `v$sql`); - Original Message - From: n.a.mor...@bton.ac.uk To: Mark Casson confu...@icube.co.uk; php-db@lists.php.net Sent: Thursday, April 23, 2009 5:25 AM Subject: RE: [PHP-DB] PHP and table/view names with '$' I find that using single quotes rather than double quotes prevents variable substitution. I don't know if this is an undocumented feature, as the documentation says that both have the same functionality. Regards, Neil -Original Message- From: Mark Casson [mailto:confu...@icube.co.uk] Sent: 23 April 2009 11:04 To: php-db@lists.php.net Subject: [PHP-DB] PHP and table/view names with '$' Hi, I am trying to access some of the v$ views using php on iis, with admin privileges. However, using: $stmt = OCIParse($conn, SELECT * FROM v$sql); gives me this error: PHP Notice: undefined variable: sql . . . Is there a way around this? Thanks Mark -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] PHP and table/view names with '$'
Hi, For reference, this didn't work, but just using single quotes instead of double quotes did. Mark Yves Sucaet yves.suc...@usa.net wrote in message news:006201c9c3ff$4896f7e0$0402a...@rincewind... What if you use back-quotes `` around the table/view name? $stmt = OCIParse($conn, SELECT * FROM `v$sql`); - Original Message - From: n.a.mor...@bton.ac.uk To: Mark Casson confu...@icube.co.uk; php-db@lists.php.net Sent: Thursday, April 23, 2009 5:25 AM Subject: RE: [PHP-DB] PHP and table/view names with '$' I find that using single quotes rather than double quotes prevents variable substitution. I don't know if this is an undocumented feature, as the documentation says that both have the same functionality. Regards, Neil -Original Message- From: Mark Casson [mailto:confu...@icube.co.uk] Sent: 23 April 2009 11:04 To: php-db@lists.php.net Subject: [PHP-DB] PHP and table/view names with '$' Hi, I am trying to access some of the v$ views using php on iis, with admin privileges. However, using: $stmt = OCIParse($conn, SELECT * FROM v$sql); gives me this error: PHP Notice: undefined variable: sql . . . Is there a way around this? Thanks Mark -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] PHP and table/view names with '$'
Sorry Mark, It's early in the morning... Neil is right. It's a PHP error you're getting after all, not a SQL Server error. And yes, this is by design: double quotes allow for variable insertion/substitution . Single quotes don't ' '. However, if you don't want the $ to be interpreted within the double quotes, you should be able to prevent this by using the backslash \ character. So, we get: $name = Yves; $name2 = $name Sucaet;// Yves Sucaet $name3 = '$name Sucaet';// $name Sucaet $name4 = \$name Sucaet;// $name Sucaet hth, Yves - Original Message - From: n.a.mor...@bton.ac.uk To: Mark Casson confu...@icube.co.uk; php-db@lists.php.net Sent: Thursday, April 23, 2009 5:25 AM Subject: RE: [PHP-DB] PHP and table/view names with '$' I find that using single quotes rather than double quotes prevents variable substitution. I don't know if this is an undocumented feature, as the documentation says that both have the same functionality. Regards, Neil -Original Message- From: Mark Casson [mailto:confu...@icube.co.uk] Sent: 23 April 2009 11:04 To: php-db@lists.php.net Subject: [PHP-DB] PHP and table/view names with '$' Hi, I am trying to access some of the v$ views using php on iis, with admin privileges. However, using: $stmt = OCIParse($conn, SELECT * FROM v$sql); gives me this error: PHP Notice: undefined variable: sql . . . Is there a way around this? Thanks Mark -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
