RE: [PHP-DB] Resource id #5
Been a positive integer, it jeans that the SQL query was succesfully
executed, read the function description.
__
Miguel Guirao Aguilera, Linux+, ITIL
Sistemas de Información
Informática R8
Ext. 7540
-- -Original Message-
-- From: Richard Dunne [mailto:[EMAIL PROTECTED]
-- Sent: Thursday, March 27, 2008 11:51 AM
-- To: php-db@lists.php.net
-- Subject: [PHP-DB] Resource id #5
--
-- Can someone explain how I can translate Resource id #5 which is what I
-- am getting from the code below?
--
-- $result = mysql_query(Select answer from answers) or
-- die(mysql_error());
-- $resultArray = explode(',',$result);
-- for ($i=0;$isizeof($resultArray);$i++)
-- {
-- echo $resultArray[$i];
-- }
--
--
--
-- --
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Re: [PHP-DB] Resource id #5
On 27 Mar 2008, at 17:51, Richard Dunne wrote:
Can someone explain how I can translate Resource id #5 which is what
I am getting from the code below?
$result = mysql_query(Select answer from answers) or
die(mysql_error());
$resultArray = explode(',',$result);
for ($i=0;$isizeof($resultArray);$i++)
{
echo $resultArray[$i];
}
For the love of $DEITY, please read the frickin' manual: http://php.net/mysql
. You've been asking similar questions around this topic for the past
few days and you clearly haven't moved forward in your understanding.
The mysql_query function returns a resource. If you print a resource
you get the text Resource id #n where n is replaced with its ID. To
make use of this resource you need to use functions like
mysql_fetch_array, mysql_fetch_assoc or one of the many others
detailed in, you guessed it, the manual. Try it, you might like it.
-Stut
--
http://stut.net/
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