Re: [PHP-DB] Individual Array Entries

[James Gadrow]

Here's how you can fill a multi-dimensional array:

$days = array(); //Declare $days
to be an array
while ($row = mysql_fetch_assoc($result)) //set variable $row to be an
associative array containing a row of results from your mysql query
   array_push($days, $row);  //Inserts a new record
into $days and stores $row in it. This creates a multi-dimensional array

Or, if you want it associative:

$days = array();
while ($row = mysql_fetch_assoc($result))
   $days['whatever here'] = $row;

Hope that helps!

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Re: [PHP-DB] Individual Array Entries

[Keith Spiller]

I am using a mini calendar script which uses the following array to enter 
event dates.


 $days = array(
   3=>array("/weblog/archive/2004/Jan/03","linked-day"),
   8=>array("/weblog/archive/2004/Jan/08","linked-day"),
   22=>array("/weblog/archive/2004/Jan/22","linked-day")
 );
 // 3, 8 & 22 = the day
 // weblog/archive... = the link
 // linked-day = the CSS class.

Because I get the event data from a database and loop through the results 
of a query, I need to be able to insert each entry individually instead of 
as a group.


The following code fails in that it only lists the last entry:

 $days = array($theday[$y]=>array("#$thelink[$y]","linked-day"));

Using a concatenation fails altogether:

 $days.= array($theday[$y]=>array("#$thelink[$y]","linked-day"));

I just do not know the proper syntax to individually insert entries into 
this multidimensional array...  Please help.  Thank you.



I tried:
   $days[$theday] = array("$thelink","linked-day");

But it only displays the last event.

Keith 


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