Re: [PHP-DB] Problem with SQL

2002-09-10 Thread Maureen
Most likely the datatype you are using for the id field is tinyint, auto increment. The tinyint datatype only goes to 127, so once you get to 127, it tries to assign the same value for the next one. Try changing your id datatype to int. HTH Maureen Brtosz Matosiuk [EMAIL PROTECTED]

RE: [PHP-DB] Problem with SQL

2002-09-08 Thread Peter Lovatt
hi It is trying to insert the value '127' into a key field (or indexed field) when it already has a record with '127' in that field. You may know it as a key violation It means you are trying to insert a record with a duplicate primary key HTH Peter

Re: [PHP-DB] Problem with SQL query on several tables

2001-11-27 Thread Rosen
Thanks, but I want wo JOIN data from three tables and then to order all data by datestamp. Can I Do It ? Thanks, Rosen Andrey Hristov wrote in message 071401c17759$f5873c80$0b01a8c0@ANDreY... Mysql says that in the join there are some columns with namer datestamp so you have to choose by

Re: [PHP-DB] Problem with SQL query on several tables

2001-11-27 Thread Indioblanco
It sounds to me like what you're trying to do is APPEND data from three similarly structured tables into one entity ordered by a column common to all 3 tables called datestamp. If I'm mistaken, then please ignore all of the following: Approach #1 (mysql) Create a temporary table with the

RE: [PHP-DB] Problem with SQL query on several tables

2001-11-27 Thread Matt Williams
Thanks, but I want wo JOIN data from three tables and then to order all data by datestamp. There must be more than one column called datestamp, this is why mysql is telling you it's ambiguous. So you need to tell it which table's datestamp column you wish to use. for example your new