Re: [PHP-DB] SQL Query - Using variable from another SQL Query
Thanks Everyone...
After I sent that...I got thinking about doing both queries in one statement.
So thats what I did.
Its working fine...
Here is the updated code:
'$tstamp' and
egw_cal.cal_id=egw_cal_dates.cal_id", $db);
if ($event = mysql_fetch_array($events)) {
echo "\n";
echo "\n";
do {
echo "$event[cal_title]- $event[cal_location]\n";
echo "\n";
$start = date('F jS\, Y \a\t g:ia', $event[cal_start]);
echo "Starting Date/Time: $start";
echo "\n";
echo "\n";
echo "$event[cal_description]";
echo "\n";
echo "\n";
} while ($event = mysql_fetch_array($events));
} else {
echo "No Public Events Are Currently Scheduled...";
}
?>
- Original Message -
From: "Matthew Ferry" <[EMAIL PROTECTED]>
To:
Sent: Monday, February 12, 2007 11:14 AM
Subject: [PHP-DB] SQL Query - Using variable from another SQL Query
Hello Everyone
Got a simple / stupid question.
Worked on this all night. I'm over looking something very basic here.
The query "event_time" brings back the calendar id for each event that is
pending in the future.
ie 12, 13, 14, 26 (There could be 100 of them out there)
The second query "events" needs to meet both reqirements.
1 - cal_category='501'
2 - cal_id= a number from the "event_time" query
I think i need to do a loop inside of a loop
Thanks...
Matt
Here is my code:
$tstamp", $db);
$events = mysql_query("SELECT * FROM egw_cal WHERE cal_category='501' and
cal_id='$event_time'\n", $db);
if ($event = mysql_fetch_array($events)) {
echo "\n";
echo "\n";
do {
echo "$event[cal_title]- $event[cal_location]\n";
echo "\n";
echo "$event[cal_description]";
echo "\n";
echo "\n";
} while ($event = mysql_fetch_array($events));
} else {
echo "No Public Events Are Currently Scheduled...";
}
?>
Re: [PHP-DB] SQL Query - Using variable from another SQL Query
This is a join - Read up on them, they're very useful and don't require
the overhead of a sub-query.
SELECT egw_cal.* FROM egw_cal_dates
LEFT JOIN egw_cal using (cal_id)
where egw_cal_dates.cal_start > $tstamp
AND egw_cal.cal_category = '501'
-Micah
On 02/12/2007 08:14 AM, Matthew Ferry wrote:
Hello Everyone
Got a simple / stupid question.
Worked on this all night. I'm over looking something very basic here.
The query "event_time" brings back the calendar id for each event that is
pending in the future.
ie 12, 13, 14, 26 (There could be 100 of them out there)
The second query "events" needs to meet both reqirements.
1 - cal_category='501'
2 - cal_id= a number from the "event_time" query
I think i need to do a loop inside of a loop
Thanks...
Matt
Here is my code:
$tstamp", $db);
$events = mysql_query("SELECT * FROM egw_cal WHERE cal_category='501' and
cal_id='$event_time'\n", $db);
if ($event = mysql_fetch_array($events)) {
echo "\n";
echo "\n";
do {
echo "$event[cal_title]- $event[cal_location]\n";
echo "\n";
echo "$event[cal_description]";
echo "\n";
echo "\n";
} while ($event = mysql_fetch_array($events));
} else {
echo "No Public Events Are Currently Scheduled...";
}
?>
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Re: [PHP-DB] SQL Query - Using variable from another SQL Query
Try this as your SQL. It should give you all the results, then you can use PHP
to sort it all out.
SELECT * FROM egw_cal WHERE cal_category='501' and cal_id in (SELECT cal_id
FROM egw_cal_dates where cal_start > $tstamp)
-TG
= = = Original message = = =
Hello Everyone
Got a simple / stupid question.
Worked on this all night. I'm over looking something very basic here.
The query "event_time" brings back the calendar id for each event that is
pending in the future.
ie 12, 13, 14, 26 (There could be 100 of them out there)
The second query "events" needs to meet both reqirements.
1 - cal_category='501'
2 - cal_id= a number from the "event_time" query
I think i need to do a loop inside of a loop
Thanks...
Matt
Here is my code:
$tstamp", $db);
$events = mysql_query("SELECT * FROM egw_cal WHERE cal_category='501' and
cal_id='$event_time'\n", $db);
if ($event = mysql_fetch_array($events))
echo "\n";
echo "\n";
do
echo "$event[cal_title]- $event[cal_location]\n";
echo "\n";
echo "$event[cal_description]";
echo "\n";
echo "\n";
while ($event = mysql_fetch_array($events));
else
echo "No Public Events Are Currently Scheduled...";
?>
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Re: [PHP-DB] SQL Query - Using variable from another SQL Query
Matthew Ferry wrote:
Hello Everyone
Got a simple / stupid question.
Worked on this all night. I'm over looking something very basic here.
The query "event_time" brings back the calendar id for each event that is
pending in the future.
ie 12, 13, 14, 26 (There could be 100 of them out there)
The second query "events" needs to meet both reqirements.
1 - cal_category='501'
2 - cal_id= a number from the "event_time" query
I think i need to do a loop inside of a loop
Thanks...
Matt
Here is my code:
$tstamp", $db);
This returns a mysql result set...not the actual data...
search php.net for the function mysql_fetch_array or others to actually
*get* the data.
(Some good examples there will help you sort this out!)
$events = mysql_query("SELECT * FROM egw_cal WHERE cal_category='501' and
cal_id='$event_time'\n", $db);
if ($event = mysql_fetch_array($events)) {
echo "\n";
echo "\n";
do {
echo "$event[cal_title]- $event[cal_location]\n";
echo "\n";
echo "$event[cal_description]";
echo "\n";
echo "\n";
} while ($event = mysql_fetch_array($events));
} else {
echo "No Public Events Are Currently Scheduled...";
}
?>
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