Re: [PHP-DB] SQL question!

2004-05-03 Thread Larry E . Ullman
I have these tables.
Users ( id,name,etc )
Coments : ( id , comment )
How do I do this kind of query:
I thought in one thing like this but I cant figure it out.
Example: Select * from users order by id desc in (select count (id) 
from
comments)
Expected result:
List of users:
* User1
  See comments ( 32 comment in database )

* User2
  See coments (13 comments in database )
You need to add a user_id column to comments, which records what user 
entered each comment. Then you can do
SELECT u.name, COUNT(c.id) FROM users u, comments c WHERE 
u.id=c.user_id GROUP BY (c.user_id)

The syntax may not be exactly right but that's the basic idea. Adding a 
user ID foreign key to the comments table is the important part.

Hope that helps,
Larry
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Re: [PHP-DB] SQL question

2003-12-11 Thread Muhammed Mamedov
I am sorry without equal "=" sign

SELECT * FROM x_table WHERE name Like "%part_of_name%"

there are actually three ways to do this:
"%part_of_name%"  part_of_name appears anywhere
"%part_of_name"part_of_name appears at the end
"art_of_name%"   part_of_name appears at the begining
 
M.Mamedov


- Original Message - 
From: "Muhammed Mamedov" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Thursday, December 11, 2003 2:00 PM
Subject: Re: [PHP-DB] SQL question


> It should be as follows:
> SELECT * FROM x_table WHERE name Like = "%part_of_name%"
> 
> Hope this helps,
> M.Mamedov
> 
> - Original Message - 
> From: "Constantin Brinzoi" <[EMAIL PROTECTED]>
> To: <[EMAIL PROTECTED]>
> Sent: Thursday, December 11, 2003 1:51 PM
> Subject: [PHP-DB] SQL question
> 
> 
> > I know it is  possible to search a database like this:
> > 
> > SELECT * FROM x_table WHERE name="%part_of_name%"
> > 
> > but I don't know for sure the correct command.
> > 
> > Could you tell me the right syntax?
> > 
> > TIA
> > Aurel.
> > 
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> > PHP Database Mailing List (http://www.php.net/)
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> > 
> 
> 
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RE: [PHP-DB] SQL question

2003-12-11 Thread brettking
try 

SELECT * FROM x_table WHERE name LIKE "%part_of_name%"

-Original Message-
From: Constantin Brinzoi [mailto:[EMAIL PROTECTED]
Sent: 11 December 2003 11:52
To: [EMAIL PROTECTED]
Subject: [PHP-DB] SQL question


I know it is  possible to search a database like this:

SELECT * FROM x_table WHERE name="%part_of_name%"

but I don't know for sure the correct command.

Could you tell me the right syntax?

TIA
Aurel.

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RE: [PHP-DB] SQL question

2003-12-11 Thread Ford, Mike [LSS]
On 11 December 2003 11:52, Constantin Brinzoi wrote:

> I know it is  possible to search a database like this:
> 
>   SELECT * FROM x_table WHERE name="%part_of_name%"
> 
> but I don't know for sure the correct command.
> 
> Could you tell me the right syntax?

SELECT * FROM x_table WHERE name LIKE "%part_of_name%"

Cheers!

Mike

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Re: [PHP-DB] SQL question

2003-12-11 Thread Muhammed Mamedov
It should be as follows:
SELECT * FROM x_table WHERE name Like = "%part_of_name%"

Hope this helps,
M.Mamedov

- Original Message - 
From: "Constantin Brinzoi" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Thursday, December 11, 2003 1:51 PM
Subject: [PHP-DB] SQL question


> I know it is  possible to search a database like this:
> 
> SELECT * FROM x_table WHERE name="%part_of_name%"
> 
> but I don't know for sure the correct command.
> 
> Could you tell me the right syntax?
> 
> TIA
> Aurel.
> 
> -- 
> PHP Database Mailing List (http://www.php.net/)
> To unsubscribe, visit: http://www.php.net/unsub.php
> 


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Checked by AVG anti-virus system (http://www.grisoft.com).
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RE: [PHP-DB] SQL Question

2002-03-13 Thread Gurhan Ozen

you can do it by using distinct function ..
Do:
SELECT DISTINCT(city) FROM addresses;


Gurhan


-Original Message-
From: Kevin Diffily [mailto:[EMAIL PROTECTED]]
Sent: Wednesday, March 13, 2002 2:05 PM
To: [EMAIL PROTECTED]
Subject: [PHP-DB] SQL Question


Hello,

I have a simple SQL Question.  I would like to take the column city in
database addresses and find out which cities are available in it.  In other
words if the following values are in there:

city
El Paso
Burlington
New York
New York
El Paso
Burlington

I would like it to return
El Paso
New York
Burlington

I know that it would something like
SELECT `city`
FROM `addresses`
WHERE ??


Thanks

Kevin Diffily
InterNetWorkingSolutions
Enterprise Class Solutions for All Enterprises

318 Last Road, Cabot, VT 05647 USA
VOICE: 1.866.inetws.net (Toll Free)
FAX:   1.888.726.9030?  (Toll Free)

Sales:  [EMAIL PROTECTED]
General Information:[EMAIL PROTECTED]
Website Hosting:[EMAIL PROTECTED]
Systems Administration Services:   [EMAIL PROTECTED]
Technical Support & Training Services:  [EMAIL PROTECTED]
Shop For it On Amazon:http://kevin.inetws.net/amazon
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AIM, IRC, Jabber, MSN, Yahoo:  inetwsnet
ICQ: 120778694



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RE: [PHP-DB] SQL Question

2002-03-13 Thread Rick Emery

SELECT DISTINCT city FROM addresses;

-Original Message-
From: Kevin Diffily [mailto:[EMAIL PROTECTED]]
Sent: Wednesday, March 13, 2002 1:05 PM
To: [EMAIL PROTECTED]
Subject: [PHP-DB] SQL Question


Hello,

I have a simple SQL Question.  I would like to take the column city in
database addresses and find out which cities are available in it.  In other
words if the following values are in there:

city
El Paso
Burlington
New York
New York
El Paso
Burlington

I would like it to return
El Paso
New York
Burlington

I know that it would something like
SELECT `city`
FROM `addresses` 
WHERE ??


Thanks

Kevin Diffily
InterNetWorkingSolutions
Enterprise Class Solutions for All Enterprises

318 Last Road, Cabot, VT 05647 USA
VOICE: 1.866.inetws.net (Toll Free)
FAX:   1.888.726.9030?  (Toll Free)

Sales:  [EMAIL PROTECTED]
General Information:[EMAIL PROTECTED]
Website Hosting:[EMAIL PROTECTED]
Systems Administration Services:   [EMAIL PROTECTED]
Technical Support & Training Services:  [EMAIL PROTECTED]
Shop For it On Amazon:http://kevin.inetws.net/amazon
Instant Messaging Username:
AIM, IRC, Jabber, MSN, Yahoo:  inetwsnet
ICQ: 120778694


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