Re: [PHP-DB] difference between two dates
On Sun, Jan 19, 2003 at 09:34:02AM -0500, John W. Holmes wrote:
>> I tried this :
>>
>> $dobtimestamp = mktime(0,0,0,$cboMM,$cboDD,$cboYY);
>> $todaytimestamp = time();
>> $txtAge = ($todaytimestamp - $dobtimestamp)/86400;
>>
>> It does not give me the expected output.
>>
>> Can anybody suggest something ?
>
>Keep your mktime() as it is, that's correct. Then use something like
>this to calculate the age:
>
>$age = date('Y',$now) - date('Y',$dob) -
>((date('z',$now)>=date('z',$dob)) ? 0 : 1);
>
>where $dob and $now are the appropriate unix timestamps that you've
>already got calculated with mktime() and time().
Thanks a lot.
Peace
--
Rajesh
:
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RE: [PHP-DB] difference between two dates
> In my application I am accepting Day, Month and Year from a Select
List.
> What I want to do is calculate the age of the person based on the
above
> selection.
>
> $cboDD is the day variable
> $cboMM is the month variable
> $cboYY is the year variable
>
> I tried this :
>
> $dobtimestamp = mktime(0,0,0,$cboMM,$cboDD,$cboYY);
> $todaytimestamp = time();
> $txtAge = ($todaytimestamp - $dobtimestamp)/86400;
>
> It does not give me the expected output.
>
> Can anybody suggest something ?
Keep your mktime() as it is, that's correct. Then use something like
this to calculate the age:
$age = date('Y',$now) - date('Y',$dob) -
((date('z',$now)>=date('z',$dob)) ? 0 : 1);
where $dob and $now are the appropriate unix timestamps that you've
already got calculated with mktime() and time().
---John W. Holmes...
PHP Architect - A monthly magazine for PHP Professionals. Get your copy
today. http://www.phparch.com/
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