On Thursday 26 February 2004 01:04, PHELPS, SCOTT wrote:
> The problem is that it only prints one name. Also next() doesn't seem to
> be advancing the table so I am getting duplicates of the one name it does
> print to the table
For starters, you're using next() incorrectly. It returns a value.
Sorry for accidentally posting twice:
I wanted to point out a typo.
At the bottom I meant "advancing the array" not "table" in regards to next()
On Wed, 25 Feb 2004 11:12:10 -0600
"PHELPS, SCOTT" <[EMAIL PROTECTED]> wrote:
> Thanks in advance for reading this:
>
> I am trying to take a query
