RE: [PHP-DB] mysql_fetch_array() question
Of course, you can avoid that problem if you use a join, I guess it all
comes down to code complexity vs SQL complexity.
-- Josh
-Original Message-
From: Ignatius Reilly [mailto:ignatius.reilly@;free.fr]
Sent: Wednesday, November 06, 2002 1:38 PM
To: Josh Johnson; '1LT John W. Holmes'; 'Graeme McLaren';
[EMAIL PROTECTED]
Subject: Re: [PHP-DB] mysql_fetch_array() question
John is right. In fact one routinely calls two different $result(s) when
coding nested loops:
while( $details = mysql_fetch_array( $result ) ) {
while ( $Email = mysql_fetch_array( $result2 ) )
..
}
}
when executing the next instance of your loop:
while( $details = mysql_fetch_array( $result ) and $Email =
mysql_fetch_array( $result2 ) ),
each mysql_fetch_array will push both pointers (on your two result
resources) by one position.
if your result sets do not have the same number of rows, the shorter one
will choke before the longer one is finished. therefore you will finish
the
loop not having called all results from the "long" resource.
My 0.02 Belgian francs
Ignatius
- Original Message -
From: "Josh Johnson" <[EMAIL PROTECTED]>
To: "'1LT John W. Holmes'" <[EMAIL PROTECTED]>; "'Graeme
McLaren'"
<[EMAIL PROTECTED]>; <[EMAIL PROTECTED]>
Sent: Wednesday, November 06, 2002 7:24 PM
Subject: RE: [PHP-DB] mysql_fetch_array() question
> :) see why I love mailing lists! :)
>
> It must have been their logic then, I respectfully retract everything
I
> said, sorry Graeme! Why do I have to work, I could spend my days
> researching this stuff before I post!
>
> Thanks John!
> -- Josh
>
> -Original Message-
> From: 1LT John W. Holmes [mailto:holmes072000@;charter.net]
> Sent: Wednesday, November 06, 2002 1:21 PM
> To: Josh Johnson; 'Graeme McLaren'; [EMAIL PROTECTED]
> Subject: Re: [PHP-DB] mysql_fetch_array() question
>
> That's not true. You can assign them to different variables and it
works
> fine.
>
> $r1 = mysql_query("select * from main limit 1") or die(mysql_error());
> $r2 = mysql_query("select * from apft limit 1") or die(mysql_error());
>
> $row1 = mysql_fetch_array($r1);
> $row2 = mysql_fetch_array($r2);
>
> print_r($row1);
> echo "";
> print_r($row2);
>
> ---John Holmes...
>
> - Original Message -
> From: "Josh Johnson" <[EMAIL PROTECTED]>
> To: "'Graeme McLaren'" <[EMAIL PROTECTED]>; <[EMAIL PROTECTED]>
> Sent: Wednesday, November 06, 2002 1:02 PM
> Subject: RE: [PHP-DB] mysql_fetch_array() question
>
>
> > In my experience, (I haven't checked the docs just yet to figure out
> > exactly why), you can only work with one result id at a time. Every
> time
> > you call mysql_query, it resets the result id (I think it frees the
> > result id automatically so you can send another query before getting
> the
> > new result id), so even if you store it in two separate variables,
it
> > will only refrence the last id (which sounds just like what happened
> in
> > your initial post). I think this is limited to a given connection,
but
> > I'm not sure.
> >
> > One of the, I guess you could say, "shortcomings" of the mysql
> interface
> > in php is that you can only execute one query at a time, and I think
> > this odd result id overwrighting that happens is due to that fact (I
> > might be wrong, but I think you can execute multiple queries at a
time
> > with perl's DBI module).
> >
> > I hope that makes more sense :)
> >
> > -- Josh
> >
> > -Original Message-
> > From: Graeme McLaren [mailto:mickel@;ntlworld.com]
> > Sent: Wednesday, November 06, 2002 12:17 PM
> > To: [EMAIL PROTECTED]
> > Subject: Re: [PHP-DB] mysql_fetch_array() question
> >
> > Josh, Thank you for reply. Thank you to everyone else who replied
to
> my
> > email also. I solved the problem shortly after posting my question,
> > I've
> > now got a massive SQL query which does the trick.
> >
> > I was interested when you replied and part of it read: "Just
> > remember that you can only work with one mysql result per connection
> at
> > a time". Can you explain a little more about that please? I don't
> > think I
> > fully understand what you mean.
> >
> > Cheers,
> >
> > Graeme :)
> >
> > - Original Message -
> > From: "Josh Johnson" <[EMAIL PROTECTED]>
> > To: <[EMAIL PROTECTED]>
> > Sent: Wednesday, November 06, 2002 12:
Re: [PHP-DB] mysql_fetch_array() question
John is right. In fact one routinely calls two different $result(s) when
coding nested loops:
while( $details = mysql_fetch_array( $result ) ) {
while ( $Email = mysql_fetch_array( $result2 ) )
..
}
}
when executing the next instance of your loop:
while( $details = mysql_fetch_array( $result ) and $Email =
mysql_fetch_array( $result2 ) ),
each mysql_fetch_array will push both pointers (on your two result
resources) by one position.
if your result sets do not have the same number of rows, the shorter one
will choke before the longer one is finished. therefore you will finish the
loop not having called all results from the "long" resource.
My 0.02 Belgian francs
Ignatius
- Original Message -
From: "Josh Johnson" <[EMAIL PROTECTED]>
To: "'1LT John W. Holmes'" <[EMAIL PROTECTED]>; "'Graeme McLaren'"
<[EMAIL PROTECTED]>; <[EMAIL PROTECTED]>
Sent: Wednesday, November 06, 2002 7:24 PM
Subject: RE: [PHP-DB] mysql_fetch_array() question
> :) see why I love mailing lists! :)
>
> It must have been their logic then, I respectfully retract everything I
> said, sorry Graeme! Why do I have to work, I could spend my days
> researching this stuff before I post!
>
> Thanks John!
> -- Josh
>
> -Original Message-
> From: 1LT John W. Holmes [mailto:holmes072000@;charter.net]
> Sent: Wednesday, November 06, 2002 1:21 PM
> To: Josh Johnson; 'Graeme McLaren'; [EMAIL PROTECTED]
> Subject: Re: [PHP-DB] mysql_fetch_array() question
>
> That's not true. You can assign them to different variables and it works
> fine.
>
> $r1 = mysql_query("select * from main limit 1") or die(mysql_error());
> $r2 = mysql_query("select * from apft limit 1") or die(mysql_error());
>
> $row1 = mysql_fetch_array($r1);
> $row2 = mysql_fetch_array($r2);
>
> print_r($row1);
> echo "";
> print_r($row2);
>
> ---John Holmes...
>
> ----- Original Message -
> From: "Josh Johnson" <[EMAIL PROTECTED]>
> To: "'Graeme McLaren'" <[EMAIL PROTECTED]>; <[EMAIL PROTECTED]>
> Sent: Wednesday, November 06, 2002 1:02 PM
> Subject: RE: [PHP-DB] mysql_fetch_array() question
>
>
> > In my experience, (I haven't checked the docs just yet to figure out
> > exactly why), you can only work with one result id at a time. Every
> time
> > you call mysql_query, it resets the result id (I think it frees the
> > result id automatically so you can send another query before getting
> the
> > new result id), so even if you store it in two separate variables, it
> > will only refrence the last id (which sounds just like what happened
> in
> > your initial post). I think this is limited to a given connection, but
> > I'm not sure.
> >
> > One of the, I guess you could say, "shortcomings" of the mysql
> interface
> > in php is that you can only execute one query at a time, and I think
> > this odd result id overwrighting that happens is due to that fact (I
> > might be wrong, but I think you can execute multiple queries at a time
> > with perl's DBI module).
> >
> > I hope that makes more sense :)
> >
> > -- Josh
> >
> > -Original Message-
> > From: Graeme McLaren [mailto:mickel@;ntlworld.com]
> > Sent: Wednesday, November 06, 2002 12:17 PM
> > To: [EMAIL PROTECTED]
> > Subject: Re: [PHP-DB] mysql_fetch_array() question
> >
> > Josh, Thank you for reply. Thank you to everyone else who replied to
> my
> > email also. I solved the problem shortly after posting my question,
> > I've
> > now got a massive SQL query which does the trick.
> >
> > I was interested when you replied and part of it read: "Just
> > remember that you can only work with one mysql result per connection
> at
> > a time". Can you explain a little more about that please? I don't
> > think I
> > fully understand what you mean.
> >
> > Cheers,
> >
> > Graeme :)
> >
> > - Original Message -
> > From: "Josh Johnson" <[EMAIL PROTECTED]>
> > To: <[EMAIL PROTECTED]>
> > Sent: Wednesday, November 06, 2002 12:29 PM
> > Subject: RE: [PHP-DB] mysql_fetch_array() question
> >
> >
> > > I concur with Jason, but if restructuring is out of the question,
> just
> > > rearrange your queries like this:
> > >
> > > $query = "SELECT Name, Address FROM users";
> > > $result = mysql_query($query);
> > > while($details = mysql_fetch_arr
RE: [PHP-DB] mysql_fetch_array() question
:) see why I love mailing lists! :)
It must have been their logic then, I respectfully retract everything I
said, sorry Graeme! Why do I have to work, I could spend my days
researching this stuff before I post!
Thanks John!
-- Josh
-Original Message-
From: 1LT John W. Holmes [mailto:holmes072000@;charter.net]
Sent: Wednesday, November 06, 2002 1:21 PM
To: Josh Johnson; 'Graeme McLaren'; [EMAIL PROTECTED]
Subject: Re: [PHP-DB] mysql_fetch_array() question
That's not true. You can assign them to different variables and it works
fine.
$r1 = mysql_query("select * from main limit 1") or die(mysql_error());
$r2 = mysql_query("select * from apft limit 1") or die(mysql_error());
$row1 = mysql_fetch_array($r1);
$row2 = mysql_fetch_array($r2);
print_r($row1);
echo "";
print_r($row2);
---John Holmes...
- Original Message -
From: "Josh Johnson" <[EMAIL PROTECTED]>
To: "'Graeme McLaren'" <[EMAIL PROTECTED]>; <[EMAIL PROTECTED]>
Sent: Wednesday, November 06, 2002 1:02 PM
Subject: RE: [PHP-DB] mysql_fetch_array() question
> In my experience, (I haven't checked the docs just yet to figure out
> exactly why), you can only work with one result id at a time. Every
time
> you call mysql_query, it resets the result id (I think it frees the
> result id automatically so you can send another query before getting
the
> new result id), so even if you store it in two separate variables, it
> will only refrence the last id (which sounds just like what happened
in
> your initial post). I think this is limited to a given connection, but
> I'm not sure.
>
> One of the, I guess you could say, "shortcomings" of the mysql
interface
> in php is that you can only execute one query at a time, and I think
> this odd result id overwrighting that happens is due to that fact (I
> might be wrong, but I think you can execute multiple queries at a time
> with perl's DBI module).
>
> I hope that makes more sense :)
>
> -- Josh
>
> -Original Message-----
> From: Graeme McLaren [mailto:mickel@;ntlworld.com]
> Sent: Wednesday, November 06, 2002 12:17 PM
> To: [EMAIL PROTECTED]
> Subject: Re: [PHP-DB] mysql_fetch_array() question
>
> Josh, Thank you for reply. Thank you to everyone else who replied to
my
> email also. I solved the problem shortly after posting my question,
> I've
> now got a massive SQL query which does the trick.
>
> I was interested when you replied and part of it read: "Just
> remember that you can only work with one mysql result per connection
at
> a time". Can you explain a little more about that please? I don't
> think I
> fully understand what you mean.
>
> Cheers,
>
> Graeme :)
>
> - Original Message -
> From: "Josh Johnson" <[EMAIL PROTECTED]>
> To: <[EMAIL PROTECTED]>
> Sent: Wednesday, November 06, 2002 12:29 PM
> Subject: RE: [PHP-DB] mysql_fetch_array() question
>
>
> > I concur with Jason, but if restructuring is out of the question,
just
> > rearrange your queries like this:
> >
> > $query = "SELECT Name, Address FROM users";
> > $result = mysql_query($query);
> > while($details = mysql_fetch_array($result)){
> > echo "Name: $details[Name]";
> > echo "Address: $details[Address]";
> > }
> > $query2 = "SELECT EmailAddress From Members";
> > $result2 = mysql_query($query2);
> > while($details = mysql_fetch_array($result2)){
> > echo "Email: $Email[EmailAddress]";
> > }
> >
> > The results won't come out at the same time, but you could use some
> > logic to combine the results into an array by a common factor. Just
> > remember that you can only work with one mysql result per connection
> at
> > a time. You *may* (untested!) be able to accomplish what you want to
> do
> > with two separate connections, but again, this is seriously
overkill.
> :)
> >
> > I'd definitely recommend restructuring your talbes as Jason
suggested.
> > -- Josh
> >
> >
> > -Original Message-
> > From: Jason Wong [mailto:phplist@;gremlins.com.hk]
> > Sent: Wednesday, November 06, 2002 5:24 AM
> > To: [EMAIL PROTECTED]
> > Subject: Re: [PHP-DB] mysql_fetch_array() question
> >
> > On Tuesday 05 November 2002 05:47, Graeme McLaren wrote:
> > > Hi, Anyone know how I can use two mysql_fetch_array() functions
> > similar
> > > to the code below? I've tried a few different ways but I keep
> getting
> > > Resource ID #4. I need to do this to retrieve an email address
from
> > one
> > > t
Re: [PHP-DB] mysql_fetch_array() question
That's not true. You can assign them to different variables and it works
fine.
$r1 = mysql_query("select * from main limit 1") or die(mysql_error());
$r2 = mysql_query("select * from apft limit 1") or die(mysql_error());
$row1 = mysql_fetch_array($r1);
$row2 = mysql_fetch_array($r2);
print_r($row1);
echo "";
print_r($row2);
---John Holmes...
- Original Message -
From: "Josh Johnson" <[EMAIL PROTECTED]>
To: "'Graeme McLaren'" <[EMAIL PROTECTED]>; <[EMAIL PROTECTED]>
Sent: Wednesday, November 06, 2002 1:02 PM
Subject: RE: [PHP-DB] mysql_fetch_array() question
> In my experience, (I haven't checked the docs just yet to figure out
> exactly why), you can only work with one result id at a time. Every time
> you call mysql_query, it resets the result id (I think it frees the
> result id automatically so you can send another query before getting the
> new result id), so even if you store it in two separate variables, it
> will only refrence the last id (which sounds just like what happened in
> your initial post). I think this is limited to a given connection, but
> I'm not sure.
>
> One of the, I guess you could say, "shortcomings" of the mysql interface
> in php is that you can only execute one query at a time, and I think
> this odd result id overwrighting that happens is due to that fact (I
> might be wrong, but I think you can execute multiple queries at a time
> with perl's DBI module).
>
> I hope that makes more sense :)
>
> -- Josh
>
> -----Original Message-----
> From: Graeme McLaren [mailto:mickel@;ntlworld.com]
> Sent: Wednesday, November 06, 2002 12:17 PM
> To: [EMAIL PROTECTED]
> Subject: Re: [PHP-DB] mysql_fetch_array() question
>
> Josh, Thank you for reply. Thank you to everyone else who replied to my
> email also. I solved the problem shortly after posting my question,
> I've
> now got a massive SQL query which does the trick.
>
> I was interested when you replied and part of it read: "Just
> remember that you can only work with one mysql result per connection at
> a time". Can you explain a little more about that please? I don't
> think I
> fully understand what you mean.
>
> Cheers,
>
> Graeme :)
>
> - Original Message -
> From: "Josh Johnson" <[EMAIL PROTECTED]>
> To: <[EMAIL PROTECTED]>
> Sent: Wednesday, November 06, 2002 12:29 PM
> Subject: RE: [PHP-DB] mysql_fetch_array() question
>
>
> > I concur with Jason, but if restructuring is out of the question, just
> > rearrange your queries like this:
> >
> > $query = "SELECT Name, Address FROM users";
> > $result = mysql_query($query);
> > while($details = mysql_fetch_array($result)){
> > echo "Name: $details[Name]";
> > echo "Address: $details[Address]";
> > }
> > $query2 = "SELECT EmailAddress From Members";
> > $result2 = mysql_query($query2);
> > while($details = mysql_fetch_array($result2)){
> > echo "Email: $Email[EmailAddress]";
> > }
> >
> > The results won't come out at the same time, but you could use some
> > logic to combine the results into an array by a common factor. Just
> > remember that you can only work with one mysql result per connection
> at
> > a time. You *may* (untested!) be able to accomplish what you want to
> do
> > with two separate connections, but again, this is seriously overkill.
> :)
> >
> > I'd definitely recommend restructuring your talbes as Jason suggested.
> > -- Josh
> >
> >
> > -Original Message-
> > From: Jason Wong [mailto:phplist@;gremlins.com.hk]
> > Sent: Wednesday, November 06, 2002 5:24 AM
> > To: [EMAIL PROTECTED]
> > Subject: Re: [PHP-DB] mysql_fetch_array() question
> >
> > On Tuesday 05 November 2002 05:47, Graeme McLaren wrote:
> > > Hi, Anyone know how I can use two mysql_fetch_array() functions
> > similar
> > > to the code below? I've tried a few different ways but I keep
> getting
> > > Resource ID #4. I need to do this to retrieve an email address from
> > one
> > > table and retrieve details from another.
> > >
> > > Cheers for any tips - I'm stumped with this one,
> > >
> > > Graeme :)
> > >
> > > $query = "SELECT Name, Address FROM users";
> > > $query2 = "SELECT EmailAddress From Members";
> > >
> > > $result = mysql_query($query);
> > > $result2 = mysql_query($query2);
> > >
> > > while($details = my
RE: [PHP-DB] mysql_fetch_array() question
In my experience, (I haven't checked the docs just yet to figure out
exactly why), you can only work with one result id at a time. Every time
you call mysql_query, it resets the result id (I think it frees the
result id automatically so you can send another query before getting the
new result id), so even if you store it in two separate variables, it
will only refrence the last id (which sounds just like what happened in
your initial post). I think this is limited to a given connection, but
I'm not sure.
One of the, I guess you could say, "shortcomings" of the mysql interface
in php is that you can only execute one query at a time, and I think
this odd result id overwrighting that happens is due to that fact (I
might be wrong, but I think you can execute multiple queries at a time
with perl's DBI module).
I hope that makes more sense :)
-- Josh
-Original Message-
From: Graeme McLaren [mailto:mickel@;ntlworld.com]
Sent: Wednesday, November 06, 2002 12:17 PM
To: [EMAIL PROTECTED]
Subject: Re: [PHP-DB] mysql_fetch_array() question
Josh, Thank you for reply. Thank you to everyone else who replied to my
email also. I solved the problem shortly after posting my question,
I've
now got a massive SQL query which does the trick.
I was interested when you replied and part of it read: "Just
remember that you can only work with one mysql result per connection at
a time". Can you explain a little more about that please? I don't
think I
fully understand what you mean.
Cheers,
Graeme :)
- Original Message -
From: "Josh Johnson" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Wednesday, November 06, 2002 12:29 PM
Subject: RE: [PHP-DB] mysql_fetch_array() question
> I concur with Jason, but if restructuring is out of the question, just
> rearrange your queries like this:
>
> $query = "SELECT Name, Address FROM users";
> $result = mysql_query($query);
> while($details = mysql_fetch_array($result)){
> echo "Name: $details[Name]";
> echo "Address: $details[Address]";
> }
> $query2 = "SELECT EmailAddress From Members";
> $result2 = mysql_query($query2);
> while($details = mysql_fetch_array($result2)){
> echo "Email: $Email[EmailAddress]";
> }
>
> The results won't come out at the same time, but you could use some
> logic to combine the results into an array by a common factor. Just
> remember that you can only work with one mysql result per connection
at
> a time. You *may* (untested!) be able to accomplish what you want to
do
> with two separate connections, but again, this is seriously overkill.
:)
>
> I'd definitely recommend restructuring your talbes as Jason suggested.
> -- Josh
>
>
> -Original Message-
> From: Jason Wong [mailto:phplist@;gremlins.com.hk]
> Sent: Wednesday, November 06, 2002 5:24 AM
> To: [EMAIL PROTECTED]
> Subject: Re: [PHP-DB] mysql_fetch_array() question
>
> On Tuesday 05 November 2002 05:47, Graeme McLaren wrote:
> > Hi, Anyone know how I can use two mysql_fetch_array() functions
> similar
> > to the code below? I've tried a few different ways but I keep
getting
> > Resource ID #4. I need to do this to retrieve an email address from
> one
> > table and retrieve details from another.
> >
> > Cheers for any tips - I'm stumped with this one,
> >
> > Graeme :)
> >
> > $query = "SELECT Name, Address FROM users";
> > $query2 = "SELECT EmailAddress From Members";
> >
> > $result = mysql_query($query);
> > $result2 = mysql_query($query2);
> >
> > while($details = mysql_fetch_array($result) and $Email =
> > mysql_fetch_array($result2))
> > {
> > echo "Name: $details[Name]";
> > echo "Address: $details[Address]";
> > echo "Email: $Email[EmailAddress]";
> > }
>
> Unless I've missed something you're going about this the wrong way.
For
> what
> you want to do, you should (in general) be able to accomplish it using
> just a
> single query.
>
> What fields do the tables 'users' and 'Members' contain? There should
be
> a
> field there (like eg. userid) which links the two together. If there
> isn't
> one then you should seriously restructure your tables so that there is
> one.
>
> --
> Jason Wong -> Gremlins Associates -> www.gremlins.com.hk
> Open Source Software Systems Integrators
> * Web Design & Hosting * Internet & Intranet Applications Development
*
>
>
> /*
> Cats are smarter than dogs. You can't make eight cats pull a sled
> through
> the snow.
> */
>
>
> --
> PHP Database Mailing List (http://www.php.net/)
> To unsubscribe, visit: http://www.php.net/unsub.php
>
>
>
> --
> PHP Database Mailing List (http://www.php.net/)
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>
--
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Re: [PHP-DB] mysql_fetch_array() question
Josh, Thank you for reply. Thank you to everyone else who replied to my
email also. I solved the problem shortly after posting my question, I've
now got a massive SQL query which does the trick.
I was interested when you replied and part of it read: "Just
remember that you can only work with one mysql result per connection at
a time". Can you explain a little more about that please? I don't think I
fully understand what you mean.
Cheers,
Graeme :)
- Original Message -
From: "Josh Johnson" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Wednesday, November 06, 2002 12:29 PM
Subject: RE: [PHP-DB] mysql_fetch_array() question
> I concur with Jason, but if restructuring is out of the question, just
> rearrange your queries like this:
>
> $query = "SELECT Name, Address FROM users";
> $result = mysql_query($query);
> while($details = mysql_fetch_array($result)){
> echo "Name: $details[Name]";
> echo "Address: $details[Address]";
> }
> $query2 = "SELECT EmailAddress From Members";
> $result2 = mysql_query($query2);
> while($details = mysql_fetch_array($result2)){
> echo "Email: $Email[EmailAddress]";
> }
>
> The results won't come out at the same time, but you could use some
> logic to combine the results into an array by a common factor. Just
> remember that you can only work with one mysql result per connection at
> a time. You *may* (untested!) be able to accomplish what you want to do
> with two separate connections, but again, this is seriously overkill. :)
>
> I'd definitely recommend restructuring your talbes as Jason suggested.
> -- Josh
>
>
> -Original Message-
> From: Jason Wong [mailto:phplist@;gremlins.com.hk]
> Sent: Wednesday, November 06, 2002 5:24 AM
> To: [EMAIL PROTECTED]
> Subject: Re: [PHP-DB] mysql_fetch_array() question
>
> On Tuesday 05 November 2002 05:47, Graeme McLaren wrote:
> > Hi, Anyone know how I can use two mysql_fetch_array() functions
> similar
> > to the code below? I've tried a few different ways but I keep getting
> > Resource ID #4. I need to do this to retrieve an email address from
> one
> > table and retrieve details from another.
> >
> > Cheers for any tips - I'm stumped with this one,
> >
> > Graeme :)
> >
> > $query = "SELECT Name, Address FROM users";
> > $query2 = "SELECT EmailAddress From Members";
> >
> > $result = mysql_query($query);
> > $result2 = mysql_query($query2);
> >
> > while($details = mysql_fetch_array($result) and $Email =
> > mysql_fetch_array($result2))
> > {
> > echo "Name: $details[Name]";
> > echo "Address: $details[Address]";
> > echo "Email: $Email[EmailAddress]";
> > }
>
> Unless I've missed something you're going about this the wrong way. For
> what
> you want to do, you should (in general) be able to accomplish it using
> just a
> single query.
>
> What fields do the tables 'users' and 'Members' contain? There should be
> a
> field there (like eg. userid) which links the two together. If there
> isn't
> one then you should seriously restructure your tables so that there is
> one.
>
> --
> Jason Wong -> Gremlins Associates -> www.gremlins.com.hk
> Open Source Software Systems Integrators
> * Web Design & Hosting * Internet & Intranet Applications Development *
>
>
> /*
> Cats are smarter than dogs. You can't make eight cats pull a sled
> through
> the snow.
> */
>
>
> --
> PHP Database Mailing List (http://www.php.net/)
> To unsubscribe, visit: http://www.php.net/unsub.php
>
>
>
> --
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>
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RE: [PHP-DB] mysql_fetch_array() question
I concur with Jason, but if restructuring is out of the question, just
rearrange your queries like this:
$query = "SELECT Name, Address FROM users";
$result = mysql_query($query);
while($details = mysql_fetch_array($result)){
echo "Name: $details[Name]";
echo "Address: $details[Address]";
}
$query2 = "SELECT EmailAddress From Members";
$result2 = mysql_query($query2);
while($details = mysql_fetch_array($result2)){
echo "Email: $Email[EmailAddress]";
}
The results won't come out at the same time, but you could use some
logic to combine the results into an array by a common factor. Just
remember that you can only work with one mysql result per connection at
a time. You *may* (untested!) be able to accomplish what you want to do
with two separate connections, but again, this is seriously overkill. :)
I'd definitely recommend restructuring your talbes as Jason suggested.
-- Josh
-Original Message-
From: Jason Wong [mailto:phplist@;gremlins.com.hk]
Sent: Wednesday, November 06, 2002 5:24 AM
To: [EMAIL PROTECTED]
Subject: Re: [PHP-DB] mysql_fetch_array() question
On Tuesday 05 November 2002 05:47, Graeme McLaren wrote:
> Hi, Anyone know how I can use two mysql_fetch_array() functions
similar
> to the code below? I've tried a few different ways but I keep getting
> Resource ID #4. I need to do this to retrieve an email address from
one
> table and retrieve details from another.
>
> Cheers for any tips - I'm stumped with this one,
>
> Graeme :)
>
> $query = "SELECT Name, Address FROM users";
> $query2 = "SELECT EmailAddress From Members";
>
> $result = mysql_query($query);
> $result2 = mysql_query($query2);
>
> while($details = mysql_fetch_array($result) and $Email =
> mysql_fetch_array($result2))
> {
> echo "Name: $details[Name]";
> echo "Address: $details[Address]";
> echo "Email: $Email[EmailAddress]";
> }
Unless I've missed something you're going about this the wrong way. For
what
you want to do, you should (in general) be able to accomplish it using
just a
single query.
What fields do the tables 'users' and 'Members' contain? There should be
a
field there (like eg. userid) which links the two together. If there
isn't
one then you should seriously restructure your tables so that there is
one.
--
Jason Wong -> Gremlins Associates -> www.gremlins.com.hk
Open Source Software Systems Integrators
* Web Design & Hosting * Internet & Intranet Applications Development *
/*
Cats are smarter than dogs. You can't make eight cats pull a sled
through
the snow.
*/
--
PHP Database Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
--
PHP Database Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] mysql_fetch_array() question
On Tuesday 05 November 2002 05:47, Graeme McLaren wrote:
> Hi, Anyone know how I can use two mysql_fetch_array() functions similar
> to the code below? I've tried a few different ways but I keep getting
> Resource ID #4. I need to do this to retrieve an email address from one
> table and retrieve details from another.
>
> Cheers for any tips - I'm stumped with this one,
>
> Graeme :)
>
> $query = "SELECT Name, Address FROM users";
> $query2 = "SELECT EmailAddress From Members";
>
> $result = mysql_query($query);
> $result2 = mysql_query($query2);
>
> while($details = mysql_fetch_array($result) and $Email =
> mysql_fetch_array($result2))
> {
> echo "Name: $details[Name]";
> echo "Address: $details[Address]";
> echo "Email: $Email[EmailAddress]";
> }
Unless I've missed something you're going about this the wrong way. For what
you want to do, you should (in general) be able to accomplish it using just a
single query.
What fields do the tables 'users' and 'Members' contain? There should be a
field there (like eg. userid) which links the two together. If there isn't
one then you should seriously restructure your tables so that there is one.
--
Jason Wong -> Gremlins Associates -> www.gremlins.com.hk
Open Source Software Systems Integrators
* Web Design & Hosting * Internet & Intranet Applications Development *
/*
Cats are smarter than dogs. You can't make eight cats pull a sled through
the snow.
*/
--
PHP Database Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
