Re: [PHP-DB] mysql_pconnect cannot create two permanent connections to the same machine ?
The code worked perfectly when databases 'bebbicell' and 'asterisk' were in the separate machines. It stopped working, when i copied the website to my machine. Aarno On 17 Jan 2006, at 18:48, Micah Stevens wrote: On Tuesday 17 January 2006 7:57 am, Aarno Syvänen wrote: Hi List, I do not claim that this is bug, but it is not a nice feature either. I do have following: Note that databases here are totally unrelated. They are on the same machine only because i am developing. I want later to move 'asterisk' to a separate machine, but when i do this, i want just change $db*s, not any other code. Because on this, i want both $bid and $accid to be valid handles. Currently it is not so. Both $res = mysql_query($sql,$accid); $err = mysql_error($accid); will generate error Warning: mysql_query(): supplied argument is not a valid MySQL-Link resource in /var/www/bebbicell.ch/signup.php And yes, there are no functions in signup.php. Aarno If you remove the $bid connection code, (comment it out) does your test code with $accid work? -Micah -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] mysql_pconnect cannot create two permanent connections to the same machine ?
On Tuesday 17 January 2006 7:57 am, Aarno Syvänen wrote: > Hi List, > > I do not claim that this is bug, but it is not a nice feature either. > > I do have following: > > /* db.php */ > $db_server="127.0.0.1"; > $db_user = ** > $db_pass = ** > $db_db = "bebbicell"; > > $db_account_server="127.0.0.1"; > $db_account_user = > $db_account_pass = > $db_account_db = "asterisk"; > > //$level= error_reporting ( 0); > $bid=mysql_pconnect($db_server,$db_user,$db_pass); > //error_reporting ( $level); > mysql_select_db($db_db,$bid); > > //$level= error_reporting ( 0); > $accid=mysql_pconnect($db_account_server,$db_account_user, > $db_account_pass); > //error_reporting ( $level); > mysql_select_db($db_account_db, $accid); > ?> > > Note that databases here are totally unrelated. They are on the same > machine only > because i am developing. I want later to move 'asterisk' to a > separate machine, but > when i do this, i want just change $db*s, not any other code. Because > on this, i want > both $bid and $accid to be valid handles. > > Currently it is not so. Both > > $res = mysql_query($sql,$accid); > $err = mysql_error($accid); > > will generate error > > Warning: mysql_query(): supplied argument is not a valid MySQL-Link > resource in /var/www/bebbicell.ch/signup.php > > And yes, there are no functions in signup.php. > > Aarno If you remove the $bid connection code, (comment it out) does your test code with $accid work? -Micah -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] mysql_pconnect cannot create two permanent connections to the same machine ?
Hi List, I do not claim that this is bug, but it is not a nice feature either. I do have following: Note that databases here are totally unrelated. They are on the same machine only because i am developing. I want later to move 'asterisk' to a separate machine, but when i do this, i want just change $db*s, not any other code. Because on this, i want both $bid and $accid to be valid handles. Currently it is not so. Both $res = mysql_query($sql,$accid); $err = mysql_error($accid); will generate error Warning: mysql_query(): supplied argument is not a valid MySQL-Link resource in /var/www/bebbicell.ch/signup.php Hmm... from the manual: First, when connecting, the function would first try to find a (persistent) link that's already open with the same host, username and password. If one is found, an identifier for it will be returned instead of opening a new connection. That is, the database is not considered in determining a pre-existing persistent connection. So, if $db_user == $db_account_user and $db_pass == $db_account_pass then $bid == $accid. That said though what you have above should work since multiple calls to mysql_pconnect with the same parameters should just return the original handle. Perhaps (and assuming the connection info is identical) $db_user doesn't have access to $db_account_db to run whatever $sql query you're running? That error doesn't seem right for that, but that's the only thing I can think of. -philip -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
