Re: [PHP-DB] weird php error
try if (isset($_GET['login']) AND $_GET['login'] == 'forgot') KD On Fri, 29 Aug 2003, Tiberiu Ardeleanu wrote: > Try: > > if ($_GET['login'] == 'forgot') > > > - Original Message - > From: "OpenSource" <[EMAIL PROTECTED]> > To: <[EMAIL PROTECTED]> > Sent: Friday, August 29, 2003 7:38 AM > Subject: [PHP-DB] weird php error > > > > Hi guys, > > > > This is weird to me.. > > I got this script > > --- > > > > > if ($_GET[login] == 'forgot') > > { > > echo "Sorry I forgot my password"; > > } > > else { echo "you are good to go"; } > > > > ?> > > - > > when ran, it gives me this error > > > > > > Notice: Use of undefined constant login - assumed 'login' in > > G:\Inetpub\wwwroot\test\index.php on line 3 > > > > Notice: Undefined index: login in G:\Inetpub\wwwroot\test\index.php on > > line 3 good to go > > > > What is this all about? > > The script look fine to me. > > > > Thanks in advance for your support > > > > > > -- > PHP Database Mailing List (http://www.php.net/) > To unsubscribe, visit: http://www.php.net/unsub.php > -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] weird php error
On 29 August 2003 06:39, OpenSource wrote: > Hi guys, > > This is weird to me.. > I got this script > --- > if ($_GET[login] == 'forgot') > { > echo "Sorry I forgot my password"; > } else { echo "you are good to go"; } > > > > - > when ran, it gives me this error > > > Notice: Use of undefined constant login - assumed 'login' in > G:\Inetpub\wwwroot\test\index.php on line 3 This is because you haven't quoted the array subscript -- PHP thinks you're trying to refer to a constant called login, but on not finding that assumes that you meant the string 'login' instead. To suppress this notice, supply the subscript correctly as a string: if ($_GET['login'] == 'forgot') > > Notice: Undefined index: login in G:\Inetpub\wwwroot\test\index.php > on line 3 This means that there was no login= parameter on the URL that called this script. If this is a permissible condition, you need to allow for it in your code. One way is simply to suppress the error message with the @ operator: if (@$_GET['login'] == 'forgot') Another is to do more explicit checking: if (isset($_GET['login']) && $_GET['login'] == 'forgot') Which you use is really down to personal preference. Cheers! Mike - Mike Ford, Electronic Information Services Adviser, Learning Support Services, Learning & Information Services, JG125, James Graham Building, Leeds Metropolitan University, Beckett Park, LEEDS, LS6 3QS, United Kingdom Email: [EMAIL PROTECTED] Tel: +44 113 283 2600 extn 4730 Fax: +44 113 283 3211 -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] weird php error
Try: if ($_GET['login'] == 'forgot') - Original Message - From: "OpenSource" <[EMAIL PROTECTED]> To: <[EMAIL PROTECTED]> Sent: Friday, August 29, 2003 7:38 AM Subject: [PHP-DB] weird php error > Hi guys, > > This is weird to me.. > I got this script > --- > > if ($_GET[login] == 'forgot') > { > echo "Sorry I forgot my password"; > } > else { echo "you are good to go"; } > > ?> > - > when ran, it gives me this error > > > Notice: Use of undefined constant login - assumed 'login' in > G:\Inetpub\wwwroot\test\index.php on line 3 > > Notice: Undefined index: login in G:\Inetpub\wwwroot\test\index.php on > line 3 good to go > > What is this all about? > The script look fine to me. > > Thanks in advance for your support > > -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php