2007. 03. 21, szerda keltezéssel 00.04-kor Richard Lynch ezt írta:
> On Tue, March 20, 2007 11:08 am, Ford, Mike wrote:
> >> what do you want with that '@' here?
> >> that operator can be used to suppress error messages when calling
> >> functions but not when using a variable
>
> This is most def
On Tue, March 20, 2007 11:08 am, Ford, Mike wrote:
>> what do you want with that '@' here?
>> that operator can be used to suppress error messages when calling
>> functions but not when using a variable
This is most definitely way wrong.
> What complete tosh! @ is a unary operator, so can be app
2007. 03. 20, kedd keltezéssel 16.08-kor Ford, Mike ezt írta:
> On 20 March 2007 13:26, Németh Zoltán wrote:
>
> > 2007. 03. 20, kedd keltezéssel 15.09-kor Pavel Kaznarskiy ezt írta:
> > > Hello !
> > > I have problem with access in mysql
> > >
> > > it is my code:
> > >
> > > SQL Query Sender
>
On 20 March 2007 13:26, Németh Zoltán wrote:
> 2007. 03. 20, kedd keltezéssel 15.09-kor Pavel Kaznarskiy ezt írta:
> > Hello !
> > I have problem with access in mysql
> >
> > it is my code:
> >
> > SQL Query Sender
> >
> > > $host="";
> > $user="";
> > $password="";
> > /* Section that execute
Németh Zoltán wrote:
> 2007. 03. 20, kedd keltezéssel 15.09-kor Pavel Kaznarskiy ezt írta:
>> Hello !
...
>
> what do you want with that '@' here?
> that operator can be used to suppress error messages when calling
> functions but not when using a variable
>
not true - although it's a lazy/bad
> >
> > Warning: mysql_select_db(): Access denied for user
> 'ODBC'@'localhost' (using password: NO) in
> z:\home\localhost\www\2.php on line 12
> >
> > Warning: mysql_select_db(): A link to the server could not
> be established in z:\home\localhost\www\2.php on line 12
> >
> > Warning: mysql_qu
On 3/20/07, Pavel Kaznarskiy <[EMAIL PROTECTED]> wrote:
Hello !
I have problem with access in mysql
it is my code:
SQL Query Sender
{$_POST['database']}
Query: $queryResults";
if($result == 0)
echo "Error ".mysql_errno().": ".mysql_error().
"";
elseif (@mysql_num_rows($result) == 0)
echo("Quer
2007. 03. 20, kedd keltezéssel 15.09-kor Pavel Kaznarskiy ezt írta:
> Hello !
> I have problem with access in mysql
>
> it is my code:
>
> SQL Query Sender
>
> $host="";
> $user="";
> $password="";
> /* Section that executes query */
> if(@$_GET['form'] == "yes")
what do you want with that '@'
Hello !
I have problem with access in mysql
it is my code:
SQL Query Sender
{$_POST['database']}
Query: $queryResults";
if($result == 0)
echo "Error ".mysql_errno().": ".mysql_error().
"";
elseif (@mysql_num_rows($result) == 0)
echo("Query completed. No results returned.
");
else
{
echo "
";
fo
Hello,
Im fairly new to PHP and I am running an Apache web server on my
computer, set up as localhost, and i recently installed MySQL 4.1 . I
am having trouble making a DB and a table in the DB. when i try to
create it from a command prompt it tells me this:
C:\mysql\bin>mysqld-opt
C:\mysql\bin>
IL PROTECTED]
Sent: Thursday, 24 July 2003 8:24 AM
To: David Nicholson
Cc: PHP List
Subject: Re: [PHP] Problem with MySQL Query
Tried NOT LIKE and that didnt exclude it either.
I am trying to exclude only 'Meal Plans'
Phil
- Original Message -
From: "David Nicholson" <
dnesday, July 23, 2003 6:19 PM
Subject: Re: [PHP] Problem with MySQL Query
> Hello,
>
> This is a reply to an e-mail that you wrote on Wed, 23 Jul 2003 at
> 22:54, lines prefixed by '>' were originally written by you.
>
> > > $dbqueryshipping1 = "s
Hello,
This is a reply to an e-mail that you wrote on Wed, 23 Jul 2003 at
22:54, lines prefixed by '>' were originally written by you.
> > $dbqueryshipping1 = "select * from tempuserpurchase
where
> > (usersessionid="$User_Shopping_Id") and day="1" and
> > type<>'Meal Plans'
> Tryed both me
> > $dbqueryshipping1 = "select * from tempuserpurchase where
> > (usersessionid=\"$User_Shopping_Id\") and day=\"1\" and
> > type<>'Meal Plans'
> >
>
> Tryed both methods and it is still not excluding anything matching Meal
> Plans
Been a short while since I used SQL with my PHP, but try pu
>
> $dbqueryshipping1 = "select * from tempuserpurchase where
> (usersessionid=\"$User_Shopping_Id\") and day=\"1\" and
> type<>'Meal Plans'
>
Tryed both methods and it is still not excluding anything matching Meal
Plans
---
Outgoing mail is certified Virus Free.
Checked by AVG anti-virus
Hello,
This is a reply to an e-mail that you wrote on Wed, 23 Jul 2003 at
22:28, lines prefixed by '>' were originally written by you.
> As per your suggestion
> $dbqueryshipping1 = "select * from tempuserpurchase where
> (usersessionid="$User_Shopping_Id") and day="1" and
type!='Meal
> Plan
gt; forgiving.
>
> ---John Holmes...
>
> - Original Message -
> From: "Phillip Blancher" <[EMAIL PROTECTED]>
> To: "PHP List" <[EMAIL PROTECTED]>
> Sent: Wednesday, July 23, 2003 5:08 PM
> Subject: [PHP] Problem with MySQL Query
>
>
27;";
You don't need quotes around '1' since it's an integer, but MySQL is
forgiving.
---John Holmes...
- Original Message -
From: "Phillip Blancher" <[EMAIL PROTECTED]>
To: "PHP List" <[EMAIL PROTECTED]>
Sent: Wednesday, July 2
Problem with mySQL Query
This is the query I have:
$dbqueryshipping1 = "select * from tempuserpurchase where
(usersessionid=\"$User_Shopping_Id\") and day=\"1\" and type!=\"Meal+Plans\" ";
What I want to do is to select everything from tempuserpurchase that matchs the user
session and the da
Hello, I wrote the code for deleting the oldest string in the mysql if
it reaches over 15 strings, but it works only under 4.x.x series of MySQL and i have
3.x.x. What should I change in the code that it would work under 3.x.x
version of MySQL? Here`s the code:
$quer = "SELECT COUNT(id) FROM loga
source versions of MySQL, in that
case, use
--with-mysql=/usr/local
- Original Message -
From: "Jon Haworth" <[EMAIL PROTECTED]>
Newsgroups: php.general
To: "Ryan Vennell" <[EMAIL PROTECTED]>; <[EMAIL PROTECTED]>
Sent: Monday, March 31, 2003 5:0
;
Sent: Monday, March 31, 2003 5:00 PM
Subject: RE: [PHP] problem with mysql.
> Hi Ryan,
>
> > when configuring php i use --with-mysql and it configures just
> > fine. i've even added an =/path/to/php after it to no avail.
>
> Try --with-mysql=/path/to/mysql inste
Sorry about that. i did use /path/to/mysql. i wasnt paying attention when writing my
pervious post.
-Ryan
>>> Jon Haworth<[EMAIL PROTECTED]> 03/31/03 04:00PM >>>
Hi Ryan,
> when configuring php i use --with-mysql and it configures just
> fine. i've even added an =/path/to/php after it to no
Hi Ryan,
> when configuring php i use --with-mysql and it configures just
> fine. i've even added an =/path/to/php after it to no avail.
Try --with-mysql=/path/to/mysql instead of --with-mysql=/path/to/php.
Cheers
Jon
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit:
ok i've reinstalled phpseveral times now, reinstalled mysql, and even reinstalled
apache once but i am still getting this same problem.
when configuring php i use --with-mysql and it configures just fine. i've even added
an =/path/to/php after it to no avail.
i keep getting this on pages t
this value will always be unique. period.
>
> -Chris
>
> -Original Message-
> From: Chad Day [mailto:[EMAIL PROTECTED]]
> Sent: Wed 2/19/2003 1:16 PM
> To: php general
> Cc:
> Subject: [PHP] problem with mysql / auto increment fields.. ?
>
>
>
>
To: php general
Cc:
Subject: [PHP] problem with mysql / auto increment fields.. ?
On my website there are a couple places where people can sign up ..
The querys after the sign up process look like
$blahblah
On my website there are a couple places where people can sign up ..
The querys after the sign up process look like
$blahblah = query(insert firstname lastname) values (blah blah blah)
$userid = mysql_insert_id($blahblah);
$insertintoothertable = query(userid, blah blah blah) etc.
it then uses t
myrow[title];
> $videoid = $myrow[videoid];
> $catergory = $myrow[catergory];
> $appraisal = $myrow[appraisal];
>
> // blah blah blah everything else
> }
>
> Tyler Longren
> Captain Jack Communications
> www.captainjack.com
> [EMAIL PROTECTED]
>
> - Origi
www.captainjack.com
[EMAIL PROTECTED]
- Original Message -
From: "Chuck Payne" <[EMAIL PROTECTED]>
To: "PHP General" <[EMAIL PROTECTED]>
Sent: Friday, June 14, 2002 11:03 PM
Subject: [PHP] Problem with MySQL
Hi,
I am working on a movie database I have two databas
Hi,
I am working on a movie database I have two database that I am calling from
but the problem I am having when I ask it to go and fetch all the movies
with the same title, it stops and only shows one.
Here is a basic layout...
if($videoid) {
$result = mysql_query("SELECT * FROM library WHER
On Thursday 11 April 2002 20:40, Roman Duriancik wrote:
> Please send me info : how to set path for *.pid file and ho to set path
> where will be mysql.sock in mysql database on linux ?
> i want : mysql.sock and localhost.pid in directory /var/lib/mysql
>
> i install mysql with this command...
>
Please send me info : how to set path for *.pid file and ho to set path
where will be mysql.sock in mysql database on linux ?
i want : mysql.sock and localhost.pid in directory /var/lib/mysql
i install mysql with this command...
./configure --localstatedir=/var/lib/mysql --bindir=/usr/bin --lib
We are running Apache 1.3.20 with PHP 4.0.6/rfc1876-patch built as a
module. We are using PHP on a load-sharing cluster with n web servers.
Our cluster supports an application that makes extensive use of mysql
connections via the PHP mysql_* functions.
The application was tested on a single web s
On Fri, 22 Jun 2001 19:52, Null wrote:
> In a script I have an update query adding on to a LONGTEXT field in my
> database. Strangely it will no longer work after seemingly random
> string lengths. So far, one row stopped adding at 440 bytes and another
> at 1049 bytes.
>
> mysql_query("UPDATE dod
In a script I have an update query adding on to a
LONGTEXT field in my database. Strangely it will no longer work after seemingly
random string lengths. So far, one row stopped adding at 440 bytes and another
at 1049 bytes.
mysql_query("UPDATE dod_news SET
Comments='$comments', NumComments
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