hi,
thanks for your help again.
i've noticed that file function have two different behaviors.
i tested file function with the url and it seems that the file is
interpreted. But i tried the code u give me and without the
http://myurl.com/; at the beginning, a warning is raised :
Warning:
all:
I just noticed that I was not replying to the list, but to the
posting email adresses. I just switched to another email client
and was not aware of this. My apologies :-(
---
You,
could it be that you want to do the following?:
?php
// primary php
$foo = $_REQUEST[foo]
//
nope sorry...
-Message d'origine-
De : Chris Knipe [mailto:[EMAIL PROTECTED]]
Envoyé : samedi 31 août 2002 20:10
À : you; 'Richard Lynch'
Cc : [EMAIL PROTECTED]
Objet : Re: [PHP] RE : include interpreted php file
fopen()
Regards,
Chris Knipe
Cell: (072) 434-7582
MegaLAN Corporate
Hi,
Thanks for u help. But i just wanna include a php file in an other. But
the included file must be interpreted before including it.
Thx
kciop
-Message d'origine-
De : Richard Lynch [mailto:[EMAIL PROTECTED]]
Envoyé : samedi 31 août 2002 02:12
À : you
Cc : [EMAIL PROTECTED]
Objet :
received this email in error,
| please notify us immediately by return email and delete the document.
\---
- Original Message -
From: you [EMAIL PROTECTED]
To: 'Richard Lynch' [EMAIL PROTECTED]
Cc: [EMAIL PROTECTED]
Sent: Saturday, August 31, 2002 7:44 PM
Subject: [PHP] RE : include
pb : include a php file in an other php file
contraints : the php file must be interpreted before being included
solution known : fsock then get the html code from the server and include
it...
Is there an other solution (easier) to include that file?
Not real sure if you *want* the PHP file
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