Hey all,
I'm trying to pick up some basic use of MongoDB using PHP.
I seem to have hit an early obstacle that I'd like your opinion on. I try
to pass an array to the mongo insert function, but for some reason the
function does not recognize the array I'm passing. Even though I can
perform a
Could the comma after the last element in your array be causing the problem?
Date: Sat, 6 Jul 2013 14:42:07 -0400
From: bluethu...@gmail.com
To: php-general@lists.php.net
Subject: [PHP] mongo usage
Hey all,
I'm trying to pick up some basic use of MongoDB using PHP.
I seem to have
You commented out the setting of yhe addresses variable
On Jul 6, 2013 1:42 PM, Tim Dunphy bluethu...@gmail.com wrote:
Hey all,
I'm trying to pick up some basic use of MongoDB using PHP.
I seem to have hit an early obstacle that I'd like your opinion on. I try
to pass an array to the
the
problem?
Date: Sat, 6 Jul 2013 14:42:07 -0400
From: bluethu...@gmail.com
To: php-general@lists.php.net
Subject: [PHP] mongo usage
Hey all,
I'm trying to pick up some basic use of MongoDB using PHP.
I seem to have hit an early obstacle that I'd like your opinion on. I try
| You commented out the setting of yhe addresses variable
Those were both equivalent ways of stating the same thing. I tried
substituting the other statement but there was no change:
$db = $connection-jfdb;
//$collection = $db-addresses;
$adresses = $connection-jfdb-adresses;
On Sat, Jul 6, 2013 at 9:16 PM, Tim Dunphy bluethu...@gmail.com wrote:
| You commented out the setting of yhe addresses variable
Those were both equivalent ways of stating the same thing. I tried
substituting the other statement but there was no change:
$db = $connection-jfdb;
| You seem to spell the variable differently (1 'd' vs. 2 'd's)?
Thanks! Fixed the type-o. Still no change.
$connection = new Mongo();
$db = $connection-jfdb;
//$collection = $db-addresses;
$adresses = $connection-jfdb-addresses;
Any other suggestions? Appreciated.
Tim
On
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