On Tue, 28 May 2002, burak delice wrote:
> I want to make a php that include javascript that use a php variable. Code
> is below:
>
> $size = GetImageSize ("images/$resim");
> echo "
> wdth=";$size;echo";";
> echo "";
> ?>
>
> (I am calling that php file as below)
> http://localhost/Aksu/we
>$size = 222;
>echo "";
> echo "width="; echo $size; echo ";";
>echo "";
>?>
>
>Cheers, boyan
>
>--
>Boyan Nedkov
>[EMAIL PROTECTED]
>
>
>
>
>>-Original Message-----
>>From: burak delice [ma
Try something like that:
";
echo "width="; echo $size; echo ";";
echo "";
?>
Cheers, boyan
--
Boyan Nedkov
[EMAIL PROTECTED]
> -Original Message-
> From: burak delice [mailto:[EMAIL PROTECTED]]
> Sent: Monday, May 27, 2002 11:59 PM
On Tuesday 28 May 2002 05:59, burak delice wrote:
> I want to make a php that include javascript that use a php variable. Code
> is below:
No need to post twice.
> $size = GetImageSize ("images/$resim");
> echo "
> wdth=";$size;echo";";
> echo "";
> ?>
That code looks broken to me.
> (I a
burak delice wrote:
>hi everyone,
>
>I want to make a php that include javascript that use a php variable. Code
>is below:
>
>$size = GetImageSize ("images/$resim");
>echo "
> wdth=";$size;echo";";
> echo "";
>?>
>
>
I didn't get the third line.. That's no JavaScript..
Isn't this supposed to
hi everyone,
I want to make a php that include javascript that use a php variable. Code
is below:
wdth=";$size;echo";";
echo "";
?>
(I am calling that php file as below)
http://localhost/Aksu/web/getimage.php?resim=K00.jpg
But explore gives me an javascript error that syntax error. Why? a
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