why not using php.exe instead of php-cgi.exe as a parser ?
On Wed, Jun 8, 2011 at 7:42 AM, Lists li...@euca.us wrote:
Lists wrote:
Windows Server 2003
PHP fastcgi 5.2
O.K. '-q' is quiet mode (no header info), which works better when not using
the -f flag when calling the script (it
Joe Francis wrote:
why not using php.exe instead of php-cgi.exe as a parser ?
Thanks for pointing that out... didn't have any reasoning, but since
your post, I've learned the difference and have changed the script.
Donovan
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dbrooke
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To
Windows Server 2003
PHP fastcgi 5.2
Hello,
I am needing to call a php script from another language, so I am using cli.
I have it basically working but have a couple questions.
First, what is the (suggested) '-q' flag for in the shebang script?
last, my shell is returning the actual call
Lists wrote:
Windows Server 2003
PHP fastcgi 5.2
O.K. '-q' is quiet mode (no header info), which works better when not
using the -f flag when calling the script (it appears).
anyway, I solved my issues with a work around, so no worries.
Donovan
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dbrooke
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PHP General Mailing List
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