start here: http://www.php.net/readdir
check out as well: 'string functions' for finding 'amrs'
and loops to make recursive search...
t.
Nicholas Couloute wrote:
I want a script where it will count all the amrs in a folder and it's
sub folders like this setup:
amrs
50 cent amrs
You can start with looking at some code examples that do similar things :
Directory browser
http://www.weberdev.com/get_example-1539.html
How to get a dir listing of the current dir of php script in an array
http://www.weberdev.com/get_example-1855.html
filesystem Show Files Script
I have used these functions but how would I count them! here is my
attempt that doesn't work!:
$count = 0;
$dir = /amrs;
$files1 = scandir($dir);
if ($files1 !== '.' $files1 !== '..') {
foreach ($files1 as $files2){
$dir2 = /amrs/$files2;
$files3 = scandir($dir2);
if ($files3 !== '.' $files3
here is what I tried but it doesn't work! any advice suggestions or
something?
$count = 0;
$dir = /amrs;
$files1 = scandir($dir);
if ($files1 !== '.' $files1 !== '..') {
foreach ($files1 as $files2){
$dir2 = /amrs/$files2;
$files3 = scandir($dir2);
if ($files3 !== '.' $files3 !== '..') {
That is some nasty code...
Anything that has repitition like that needs a substantial rewrite, but
I'm guessing that you know that, hence the e-mail.
I just knocked up the following function, powered by the magic of
recursion. It should be close to what you were trying to do.
function
David Otton wrote:
On Wed, 13 Aug 2003 10:54:58 +0200, you wrote:
I want to choose a file at random from a
directory which adheres to certain naming scheme.
I can't get it to work. It's probably something
simple...Here is a relevant snippet:
img src=/szukaj/images/i
?
On Wed, 13 Aug 2003 10:54:58 +0200, you wrote:
I want to choose a file at random from a
directory which adheres to certain naming scheme.
I can't get it to work. It's probably something
simple...Here is a relevant snippet:
img src=/szukaj/images/i
?
chdir('./szukaj/images/');
echo
Try this bit of code and see if it works. (I don't know if there's a less
taxing (on the server) way to get a count of files in a directory or not.)
$myDirectory = dir("yourdirectory");
while($entry=$myDirectory-read())
{
$filecount++;
}
$myDirectory-close();
$number = rand(1,
On Friday, February 16, 2001, at 10:31 AM, Hoover, Josh wrote:
Try this bit of code and see if it works. (I don't know if there's a less
taxing (on the server) way to get a count of files in a directory or not.)
this code snippet won't work as a standalone. you are referencing an object
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