On Mon, Dec 19, 2011 at 9:19 AM, Floyd Resler fres...@adex-intl.com wrote:
In the previous version of PHP we were using, I could pass a string to
number_format and it would just change it to a 0 without complaint. With
5.3.6 I get an expects double error. I don't suppose there's a way to
Quoting Floyd Resler fres...@adex-intl.com:
In the previous version of PHP we were using, I could pass a string
to number_format and it would just change it to a 0 without
complaint. With 5.3.6 I get an expects double error. I don't
suppose there's a way to make it work like it used
On 11-12-19 11:08 AM, Bastien Koert wrote:
On Mon, Dec 19, 2011 at 9:19 AM, Floyd Reslerfres...@adex-intl.com wrote:
In the previous version of PHP we were using, I could pass a string to number_format and
it would just change it to a 0 without complaint. With 5.3.6 I get an expects
double
On Dec 19, 2011, at 11:38 AM, Robert Cummings wrote:
On 11-12-19 11:08 AM, Bastien Koert wrote:
On Mon, Dec 19, 2011 at 9:19 AM, Floyd Reslerfres...@adex-intl.com wrote:
In the previous version of PHP we were using, I could pass a string to
number_format and it would just change it to a 0
João Cândido de Souza Neto wrote:
I´m having some troubles with the number_format function.
When i run a number_format(3000,2,,,.) if returns correctly, but when
i try to run number_format(300,2,,,.) it returns the value formatted
but with two spaces before.
Anyone knows how can i avoid
João Cândido de Souza Neto wrote:
If you look at carefuly, you´ll see that i´ve two problems in the same
function.
1 - This function add blank spaces at the beginning of the string.
2 - This function rounds the $var value and it can causes meny troubles.
Ok, I've already checked that
I´m sorry.
My head´s crazy todar.
Thanks a lot.
Stut [EMAIL PROTECTED] escreveu na mensagem
news:[EMAIL PROTECTED]
João Cândido de Souza Neto wrote:
If you look at carefuly, you´ll see that i´ve two problems in the same
function.
1 - This function add blank spaces at the beginning of the
PROTECTED]
To: Jay Blanchard [EMAIL PROTECTED]
Cc: [EMAIL PROTECTED]
Sent: Thursday, October 31, 2002 2:36 PM
Subject: RE: [PHP] number_format question
Tried it. It works but crops everything after the first , in the number
if you enter a number with commas. Works great if you don't enter any
[snip]
I using number_format where I need to turn a number say 123456789 into
123,456,789 and it works just fine. I also need it to strip the decimal
out if someone enters it. I.E 123456.00 would become 123,456
the command I'm using right now is:
number_format($number, ,);
If I enter 123456.00
If I try that I get a wrong parameter count error.
Ed
On Thu, 31 Oct 2002, Jay Blanchard wrote:
[snip]
I using number_format where I need to turn a number say 123456789 into
123,456,789 and it works just fine. I also need it to strip the decimal
out if someone enters it. I.E 123456.00
[snip]
If I try that I get a wrong parameter count error.
[/snip]
number_format ( float number [, int decimals [, string dec_point [, string
thousands_sep]]])
number_format($number, 0, '', ',');
Try that ...
Jay
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Tried it. It works but crops everything after the first , in the number
if you enter a number with commas. Works great if you don't enter any
commas.
What I need to be able to do:
IN OUT
123456789 123,456,789
123456789.00 123,456,789
123,456,789.00 123,456,789
Ed
what about str_replace(,, , $str) before you pass the value to
number_format()?
-Original Message-
From: [EMAIL PROTECTED] [mailto:ed;home.homes2see.com]
Sent: Friday, November 01, 2002 9:37 AM
To: Jay Blanchard
Cc: [EMAIL PROTECTED]
Subject: RE: [PHP] number_format question
Tried
Tried it. It works but crops everything after the first , in the
number
if you enter a number with commas. Works great if you don't enter any
commas.
How many integers can you name that have commas in them??? In other
words, you have a string, so PHP converts it to an integer to pass to
why not multiply the number by 1000 and then use
str_pad($in,6,0,STR_PAD_LEFT)
Alastair Battrick
Senior Developer
Lightwood Consultancy Ltd
http://www.lightwood.net
-Original Message-
From: Scott St. John [mailto:[EMAIL PROTECTED]]
Sent: 08 March 2002 17:02
To: [EMAIL PROTECTED]
Ok, I think I got it using this:
$anum = number_format($fie31,2);
$anum = str_replace($replace_char, $replace_strings, $anum);
On Fri, 8 Mar 2002, Alastair Battrick wrote:
why not multiply the number by 1000 and then use
str_pad($in,6,0,STR_PAD_LEFT)
Alastair Battrick
Senior Developer
Look into printf and sprintf.
--- Scott St. John [EMAIL PROTECTED] wrote:
Hi everyone,
I am trying to format a number for a report, the one
consistant thing is
the three decimal places. But I need to strip them,
then fill in zero's
from the left.
So, if the number coming in is
Jeff Oien [EMAIL PROTECTED] wrote:
I have a number like this 0.51 and I would like it to display without
the leading 0. How can I do this? Thanks.
There are lots of solutions.
$num = 0.51;
$num_parts = explode( '.', $num );
$num_new = '.' . $num_parts[1];
Or if it's always going to be a
I'm finding some problems on using number_format($value, $decimal, ",",
".") when I have a value comming from a resultset (database query
results)...
If I had something like '123.45', using number_format it will return
'123,00'.
I think this happens because my value is a string and PHP
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