Even more funny...
I cut and pasted your code and I got;
Wed Dec 12 2001
Sat Mar 1 2003
2001-12-12
2001-03-01
What version of Php and OS are you using??
John
"Niklas lampén" <[EMAIL PROTECTED]> wrote in message
000301c16369$6817a320$ba93c5c3@Niklas">news:000301c16369$6817a320$ba93c5c3@Niklas.
On Thu, 1 Nov 2001, Jason Murray wrote:
> > > You'll also need to compile php as a standalone, and put as
> > > the first line of your php script
> > >
> > > #!/path/to/php -q
> >
> > What if we need both version??
>
> There's nothing stopping you running both.
How do you compile it for both
On Fri, 2 Nov 2001 15:09, Adrian D'Costa wrote:
> On Thu, 1 Nov 2001, Jason Murray wrote:
> > > > You'll also need to compile php as a standalone, and put as
> > > > the first line of your php script
> > > >
> > > > #!/path/to/php -q
> > >
> > > What if we need both version??
> >
> > There's noth
Great. :)
I've got PHP 4.0.6 on linux. You?
I think you should break the dates manually, it would be the most sure
way to do it.
Niklas
-Original Message-
From: John Clarke [mailto:[EMAIL PROTECTED]]
Sent: 2. marraskuuta 2001 9:11
To: [EMAIL PROTECTED]
Subject: Re: [PHP] year 2002 s
Matt,
It sounds like you have a process where the user does this:
page1.php ->
fills out and submits form ->
page2.php which builds a frameset ->
menu.php and editor.php as the frames, you want menu.php to
know what the submitted form values were.
If you've got sessions go
Hi Justin,
That man page is pretty descriptive and contains many examples. It's
sorta like a tutorial :) If there is information you (or anyone) feels is
missing, please say so and it'll be looked into and perhaps added.
Regards,
Philip Olson
On Fri, 2 Nov 2001, Justin French wrote:
> Ummm
I'm still running 4.0.5 because that is what my web host is running.
Methinks there may be a problem here.
In the meantime I've tried storing the dates in the array in the original
format in lieu of the fully converted format.
I then reformat the original from the array as required for each page
I'm having a wierd problem with mySQL query.
$Query = "SELECT UCASE(Company), Icons, ID, LogoD FROM feComps";
returns right amount of rows, but field Company is empty.
$Query = "SELECT Company, Icons, ID, LogoD FROM feComps.";
works fine.
First query works great when I run it
Hi,
Can someone help me on how i could generate or create a pdf file an fill contents
Rgds
Krushna Kumar
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